Suppose p(x) = x⁴ + a₃x³ + a₂x² + a₁x + a₀ and q(x) = x⁴ + b₃x³ + b₂x² + b₁x + b₀ are the polynomials. If α, β, γ, δ are zeros of p(x) and α, β, γ, λ are zeros of q(x), then what is (p(x) − q(x))/((x − α)(x − β)(x − γ)) equal to ?

p(x) = (x − α)(x − β)(x − γ)(x − δ) and q(x) = (x − α)(x − β)(x − γ)(x − λ). So p(x) − q(x) = (x − α)(x − β)(x − γ)[(x − δ) − (x − λ)] = (x − α)(x − β)(x − γ)(λ − δ). Dividing by (x − α)(x − β)(x − γ) gives λ − δ. Wait, that's option (b). Re-checking: (x − δ) − (x − λ) = −δ + λ = λ − δ. So the answer is λ − δ, which is option (b).