The arch of a bridge is in the form of an arc of a circle. If the span of the bridge is 40 m and height in the middle is 8 m, then what is the radius of curvature of the bridge?
A.29 m✓ Correct
B.27 m
C.31 m
D.25 m
Explanation
Half-chord = 20, sagitta = 8. R = (c² + 4h²)/(8h) = (1600+256)/64 = 1856/64 = 29 m.
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