The area of a trapezium is 105 cm² and its height is 7 cm. If one of the parallel sides is longer than the other by 6 cm, then the length of the longer side, in cm, is
A.18✓ Correct
B.16
C.15
D.12
Explanation
Area of trapezium = (1/2)(sum of parallel sides)(height). Let shorter side = a, longer = a+6. So 105 = (1/2)(a + a+6)(7) → 105 = (7/2)(2a+6) → 30 = 2a+6 → 2a = 24 → a = 12. Longer side = 12+6 = 18 cm.
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