The arithmetic mean of 100 observations was 50. Later on, it was found that two observations were misread as 82 and 6 instead of 182 and 56. What is the value of the corrected mean?

Question

Accepted Answer

51·5. Original sum = 100 × 50 = 5000. Misread observations sum = 82 + 6 = 88. Correct observations sum = 182 + 56 = 238. Correction = 238 − 88 = 150. Corrected total = 5000 + 150 = 5150. Corrected mean = 5150/100 = 51.5.

The arithmetic mean of 100 observations was 50. Later on, it was found that two observations were misread as 82 and 6 instead of 182 and 56. What is the value of the corrected mean?

Explanation

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