The marks obtained by 10 students in a Statistics test are 24, 47, 18, 32, 19, 15, 21, 35, 50 and 41. What is the mean deviation of the largest five observations?

Largest five observations are: 50, 47, 41, 35, 32. Mean = (50+47+41+35+32)/5 = 205/5 = 41. Deviations from mean: |50-41|=9, |47-41|=6, |41-41|=0, |35-41|=6, |32-41|=9. Sum = 30. Mean deviation = 30/5 = 6. Hmm answer would be 6 = option (c). However given options and computation showing 6, the answer is (c).