CDS 2025 · PYQ · Physics / Work, Power and Energy · easy
The minimum power required to lift a mass of 50 kg to a vertical height of 8 m in 10 s is : (Assume g = 10 m/s²)
- A.400 W✓ Correct
- B.40 W
- C.50 W
- D.500 W
Work done in lifting the mass = mgh = 50 × 10 × 8 = 4000 J. Power = Work/Time = 4000/10 = 400 W. Hence the minimum power required is 400 W.
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