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CDS 2025 · PYQ · Physics / Work, Energy and Power · easy

The minimum power required to lift a mass of 50 kg up to a vertical distance of 8 m in 10 s is : (Take g = 10 m/s²)

  1. A.400 W✓ Correct
  2. B.40 W
  3. C.50 W
  4. D.500 W

Explanation

Power = Work done / Time. Work done in lifting the mass = mgh = 50 × 10 × 8 = 4000 J. Therefore, Power = 4000 J / 10 s = 400 W. This is the minimum power required because we are considering only the work done against gravity, ignoring losses due to friction or other factors.
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