The minute hand of a clock is 15 cm long and sweeps an area of 15π cm² on the dial of the clock. How much angle does it describe during this period?

The area swept by the minute hand is the area of a sector with radius r = 15 cm. Area of sector = (θ/360°) × πr². So 15π = (θ/360°) × π × 225. This gives θ/360° = 15/225 = 1/15. Therefore θ = 360°/15 = 24°.