CTET PAPER II 2019 · PYQ · Fractions / BODMAS · hard
The value of 6²/₃ ÷ 2¹/₂ × 3³/₄ – 5¹/₂ × 4¹/₄ + 1²/₃(⁷/₈ + ³/₄ × ²/₃) is
- A.–11 1/12✓ Correct
- B.11 1/12
- C.6 1/2
- D.–6 1/2
Converting: 6²/₃ = 20/3, 2¹/₂ = 5/2, 3³/₄ = 15/4, 5¹/₂ = 11/2, 4¹/₄ = 17/4, 1²/₃ = 5/3. First term: (20/3) ÷ (5/2) × (15/4) = (20/3)(2/5)(15/4) = (20×2×15)/(3×5×4) = 600/60 = 10. Second term: (11/2)(17/4) = 187/8. Third bracket: 7/8 + (3/4)(2/3) = 7/8 + 1/2 = 7/8 + 4/8 = 11/8. Third term: (5/3)(11/8) = 55/24. Total: 10 - 187/8 + 55/24 = 240/24 - 561/24 + 55/24 = (240 - 561 + 55)/24 = -266/24 = -133/12 = -11 1/12.
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