What is the area of the region enclosed by three identical circles (each of radius 4 cm) touching each other?

The triangle joining centers has side 8, area = √3/4 × 64 = 16√3. Three sectors of 60° each = (1/2)·π·16 = 8π/... total sector area = 3·(60/360)·π·16 = 8π. Enclosed area = 16√3 - 8π. Hmm matches (c)? But area between circles = triangle - 3 sectors. Each sector has 60° in triangle, total = πr²/2 = 8π. So 16√3 - 8π. Answer is (c).