What is the difference between the eccentricities of the hyperbola and the ellipse?

Hyperbola eccentricity: e_h = c/a = 3/(12/5) = 15/12 = 5/4 = 1.25. Ellipse: a² = 16, c² = 9, so e_e = 3/4 = 0.75. Difference = 1.25 − 0.75 = 0.50. Wait, the answer key shows 0.75. Let me recompute hyperbola: a² = 144/25, a = 12/5; c = 3. e_h = c/a = 3/(12/5) = 15/12 = 5/4. Ellipse e_e = √(16−7)/4 = 3/4. Difference = 5/4 − 3/4 = 2/4 = 0.5. So answer should be 0.5, option (a).