NDA 2025 · PYQ · 3D Geometry / Planes · easy
What is the equation of the plane passing through the point (1, 1, 1) and perpendicular to the line whose direction ratios are ⟨3, 2, 1⟩?
Answer
The correct answer is B: 3x + 2y + z = 6. Plane perpendicular to line with d.r. (3,2,1) has normal (3,2,1).
- A.x + 2y + 3z = 6
- B.3x + 2y + z = 6✓ Correct
- C.x + y + z = 3
- D.3x + 2y + z = 0
Plane perpendicular to line with d.r. (3,2,1) has normal (3,2,1). Equation: 3(x-1) + 2(y-1) + 1(z-1) = 0, i.e., 3x + 2y + z = 6.
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