What is the number of factors of 24³ - 16³ - 8³?

If a + b + c = 0 then a³ + b³ + c³ = 3abc. Here let a = -24, b = 16, c = 8: a+b+c = 0. So (-24)³ + 16³ + 8³ = 3(-24)(16)(8) = -9216, meaning 24³ - 16³ - 8³ = 9216. Wait: -24³ + 16³ + 8³ = 3(-24)(16)(8) = -9216. So 24³ - 16³ - 8³ = 9216. Factorize 9216 = 2^10 × 3² = 1024 × 9. Number of factors = 11 × 3 = 33. Hmm, that gives (a) 33. But official may be (b) 30. Let me recompute: 24³ = 13824, 16³ = 4096, 8³ = 512. 13824 - 4096 - 512 = 9216. 9216 = 2^10 × 3². Factors: (10+1)(2+1) = 33. Answer (a) 33.