CTET PAPER II 2019 · PYQ · Algebraic Expressions · medium
What is the value of a(a + b² + c) + b²(a² + b² + c²) – c(a + b²), when a = 1, b = –3 and c = –2?
- A.138
- B.154✓ Correct
- C.162
- D.176
With a=1, b=-3, c=-2: b²=9, a²=1, c²=4. First term: a(a + b² + c) = 1(1 + 9 - 2) = 1(8) = 8. Second term: b²(a² + b² + c²) = 9(1 + 9 + 4) = 9(14) = 126. Third term: c(a + b²) = -2(1 + 9) = -2(10) = -20. Total: 8 + 126 - (-20) = 8 + 126 + 20 = 154.
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