Profit and Loss for Agniveer Vayu — Complete Concept to PYQ Guide

beginner 18 min read

Concept

Every commercial transaction boils down to two numbers: what you paid and what you received. The difference — and the direction of that difference — determines whether you made a profit or took a loss.

Cost Price (CP): The price at which you buy the article. This is your investment.

Selling Price (SP): The price at which you sell the article. This is your return.

If SP > CP, the surplus is profit. If CP > SP, the deficit is loss. When SP = CP, you break even.

Here is the analogy that keeps it concrete: think of a shopkeeper in a Delhi market. He buys a cricket bat at ₹400 (CP), slaps a tag of ₹600 on it (Marked Price or MP), then offers a 10% discount during a sale. The price after discount becomes his actual SP. His profit is SP minus his CP. The percentage version of that profit, relative to CP, is what every exam question is really asking.

Two additional terms you will encounter:

The entire chapter lives on two foundational relationships:

Profit %=SPCPCP×100\text{Profit \%} = \frac{\text{SP} - \text{CP}}{\text{CP}} \times 100

Loss %=CPSPCP×100\text{Loss \%} = \frac{\text{CP} - \text{SP}}{\text{CP}} \times 100

Notice: percentage profit and percentage loss are always computed on CP, not SP. This single fact causes more wrong answers than any formula confusion.


Deep Dive

Core Formulas and Their Reverse Forms

You need both the forward and backward forms of every relationship. Exam questions almost always give you SP and ask for CP, or give you a loss% and ask for the new SP at profit%.

Forward (given CP, find SP): SP=CP×(1+P%100)for profitSP = CP \times \left(1 + \frac{P\%}{100}\right) \quad \text{for profit} SP=CP×(1L%100)for lossSP = CP \times \left(1 - \frac{L\%}{100}\right) \quad \text{for loss}

Backward (given SP, find CP): CP=SP1+P%100for profitCP = \frac{SP}{1 + \frac{P\%}{100}} \quad \text{for profit} CP=SP1L%100for lossCP = \frac{SP}{1 - \frac{L\%}{100}} \quad \text{for loss}

Look — the multiplier form is the fastest path. When you see "sold at 20% loss for ₹480", immediately write:

480=CP×0.8    CP=4800.8=600480 = CP \times 0.8 \implies CP = \frac{480}{0.8} = 600

No intermediate steps. This is what separates 30-second solvers from 2-minute solvers.

Marked Price and Discount

SP=MP×(1D%100)SP = MP \times \left(1 - \frac{D\%}{100}\right)

Where D% is the discount percentage on the marked price.

If a question involves both a markup (profit on CP to get MP) and a discount (reduction from MP to get SP), you chain the multipliers:

SP=CP×(1+markup%100)×(1D%100)SP = CP \times \left(1 + \frac{\text{markup}\%}{100}\right) \times \left(1 - \frac{D\%}{100}\right)

Example: An article is marked 25% above CP and sold at 20% discount. Net profit/loss?

SP=CP×1.25×0.80=CP×1.00SP = CP \times 1.25 \times 0.80 = CP \times 1.00

Net effect: no profit, no loss. Elegant — and a question type that appears regularly.

Selling Multiple Items at "Same SP" Trap

Here is a classic trap: a person sells two articles each at ₹X, one at 20% profit and one at 20% loss. Students assume they break even. They don't.

CP1=X1.2,CP2=X0.8CP_1 = \frac{X}{1.2}, \quad CP_2 = \frac{X}{0.8}

Total CP = X(11.2+10.8)=X(56+54)=X2512X\left(\frac{1}{1.2} + \frac{1}{0.8}\right) = X\left(\frac{5}{6} + \frac{5}{4}\right) = X \cdot \frac{25}{12}

Total SP = 2X2X

Since 2512>2\frac{25}{12} > 2 (i.e., 25122.08\frac{25}{12} \approx 2.08), there is always a net loss when same SP is used with equal profit% and loss%. The loss% formula:

Loss %=(Common %10)2\text{Loss \%} = \left(\frac{\text{Common \%}}{10}\right)^2

At 20% each: loss = (20/10)2=4%(20/10)^2 = 4\%. Memorise this result — it appears as a direct question.

When Items Are Bought/Sold in Groups

When the question says "9 books purchased at ₹18" — the CP is for the whole batch, and the SP per book or vice versa. Find CP per unit and SP per unit, then apply the standard formula. Don't try to work with the whole-batch numbers and partial-batch numbers simultaneously.

Successive Discounts

Two discounts of a% and b% are NOT equivalent to (a+b)%. The equivalent single discount is:

Single equivalent discount=(a+bab100)%\text{Single equivalent discount} = \left(a + b - \frac{ab}{100}\right)\%

Example: 20% and 10% successive discounts = 20+10200100=28%20 + 10 - \frac{200}{100} = 28\% single discount.


Memory Tricks & Shortcuts

patternMultiplier Method for Reverse Problems

When SP and profit/loss% are given, find CP in one step using the multiplier.

Rule: CP = SP ÷ multiplier, where multiplier = (100 ± p%) / 100.

Sold at 20% loss for ₹480 → CP = 480 ÷ 0.8 = 600. Done. Sold at 25% profit for ₹750 → CP = 750 ÷ 1.25 = 600. Done.

Standard method (setting up the ratio equation): ~40 seconds. Multiplier method: ~10 seconds. You save 30 seconds per question — that is significant when you have many questions.

patternSame SP Equal % Loss Formula

When two items are sold at the SAME selling price — one at x% profit, one at x% loss — there is ALWAYS a net loss.

Net Loss %=(x10)2\text{Net Loss \%} = \left(\frac{x}{10}\right)^2

At x = 20%: loss = 4%. At x = 10%: loss = 1%. At x = 30%: loss = 9%.

Standard method (finding both CPs, summing, comparing): 6 steps, ~90 seconds. This formula: 1 step, ~8 seconds.

patternMarkup + Discount Net Effect via Multiplier Chain

Chain the two multipliers and compare to 1.

Markup 25%, Discount 20%: 1.25 × 0.80 = 1.00 → break even. Markup 30%, Discount 25%: 1.30 × 0.75 = 0.975 → 2.5% loss. Markup 20%, Discount 10%: 1.20 × 0.90 = 1.08 → 8% profit.

Standard method: convert each to fraction, find SP in terms of CP, then compare: ~70 seconds. Multiplier chain: multiply two decimals mentally: ~15 seconds.

patternSuccessive Discount Single Equivalent

For two discounts a% and b%, the single equivalent discount is:

(a+bab100)%\left(a + b - \frac{ab}{100}\right)\%

Example: 30% and 20% → 30+20600100=44%30 + 20 - \frac{600}{100} = 44\%.

Standard method: apply first discount to MP, then second discount to new price, calculate overall reduction in 4 steps. This formula: 1 calculation, ~12 seconds vs ~50 seconds.

patternFraction Shortcut for Common Profit/Loss Percentages

Standard profit/loss percentages map to clean fractions of CP:

| % | Fraction | Use | |---|----------|-----| | 25% profit | SP = 5/4 of CP | | | 20% profit | SP = 6/5 of CP | | | 33.33% profit | SP = 4/3 of CP | | | 20% loss | SP = 4/5 of CP | | | 25% loss | SP = 3/4 of CP | |

Recognising these fractions lets you skip decimal arithmetic entirely. For "sold at 25% profit for ₹750", write SP = 5/4 × CP → CP = 750 × 4/5 = 600. Three steps, no decimals, ~10 seconds vs standard ~35 seconds.


Fast-Solving Framework

When you see a profit and loss question in the exam hall, run this decision tree:

Step 1 — Identify what's given and what's asked.

Step 2 — Check for special structures.

Step 3 — Work with multipliers, not raw differences. Avoid writing "profit = SP − CP" as your first line unless the question literally hands you both in rupees. Multipliers are faster and less error-prone.

Step 4 — Sanity check the answer. If SP > CP, your profit% must be positive. If CP was ₹600 and you're getting profit% as negative, you flipped something.

For Agniveer Vayu, these questions tend to be one-step or two-step. If your working exceeds three lines, you have probably missed a shortcut.


Solved PYQs

Why this question (PYQ 1): This tests your ability to handle batch-to-unit conversion before applying the profit% formula. A common trap is using 18 and 20 directly as if they are per-book prices.

Previous Year Questionपिछले वर्ष का प्रश्न2023
If 9 books are purchased at Rs. 18 and sold at Rs 20, then the profit % is
  1. 12
  2. 11 1/9
  3. 12 1/9
  4. 11
Solutionसमाधान
CP per book = 18/9 = 2, SP per book = 20/9. Profit% = ((20/9 - 2)/2) × 100 = (2/9)/2 × 100 = 100/9 = 11 1/9%.

Solving path: First, find CP per book: ₹18 for 9 books → CP = 18/9 = ₹2 per book. SP per book: ₹20 for 9 books → SP = 20/9 per book.

Profit%=SPCPCP×100=20922×100=201892×100=29×2×100=1009=1119%\text{Profit\%} = \frac{SP - CP}{CP} \times 100 = \frac{\frac{20}{9} - 2}{2} \times 100 = \frac{\frac{20 - 18}{9}}{2} \times 100 = \frac{2}{9 \times 2} \times 100 = \frac{100}{9} = 11\frac{1}{9}\%

The answer is option (B): 1119%11\frac{1}{9}\%.


Why this question (PYQ 2): This is a two-stage problem — recover CP from a loss scenario, then apply a profit% to the same CP. The multiplier method makes it two lines.

Previous Year Questionपिछले वर्ष का प्रश्न2023
By selling an article for Rs. 480 a person lost 20%. For what should he sell it to make a profit of 20%?
  1. Rs. 750
  2. Rs. 700
  3. Rs. 720
  4. Rs. 675
Solutionसमाधान
SP = 480 at 20% loss means CP = 480/0.8 = 600. For 20% profit, new SP = 600 × 1.2 = Rs. 720.

Solving path: SP at 20% loss = ₹480. Using the multiplier:

CP=4800.8=600CP = \frac{480}{0.8} = 600

For 20% profit on the same CP:

New SP=600×1.2=Rs. 720\text{New SP} = 600 \times 1.2 = \text{Rs. } 720

The answer is option (C): Rs. 720.


Why this question (PYQ 3): This is the most direct form — given both CP and SP in rupees, find profit%. Good for calibrating your baseline speed.

Previous Year Questionपिछले वर्ष का प्रश्न2022
Kapil purchase the cycle for 2000 Rs and sold it for 2100 Rs. then profit % is:
  1. 2 %
  2. 5 %
  3. 3 %
  4. 4 %
Solutionसमाधान
Profit = 2100 − 2000 = 100. Profit % = (100/2000) × 100 = 5%.

Solving path: Profit = 2100 − 2000 = ₹100.

Profit%=1002000×100=5%\text{Profit\%} = \frac{100}{2000} \times 100 = 5\%

The answer is option (B): 5%.

Observation: recognise that 100/2000 = 1/20 = 5% without any multiplication. If you see CP ending in round hundreds and profit is a small number, convert to fraction first.


Common Mistakes


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