Depreciation and Valuation of Inventories for SSC CGL Finance and Accounts

intermediate 18 min read

Concept

Every physical asset wears out over time. A machine bought today will not function — or sell — for the same price ten years later. Depreciation is the systematic process of allocating the cost of a tangible fixed asset over its useful life. It is not a cash payment; it is an accounting entry that matches the expense of using an asset to the revenue it helps generate. This is the matching principle in action.

Think of it like a mobile phone. You buy it for ₹30,000. By year three, it is worth maybe ₹10,000. That ₹20,000 reduction in value happened gradually — depreciation is how accountants capture that reduction year by year in the books.

Inventory valuation is a separate but equally important topic. A business buys raw materials or goods at different prices over time. When it sells goods, which cost do you charge to the Profit & Loss account — the oldest purchase price, the newest, or some average? The method you choose directly affects your reported profit and the value of closing stock on the Balance Sheet.

Look — in SSC CGL Finance and Accounts, these two topics almost always appear together because both deal with asset measurement and both directly affect the financial statements. The examiner tests whether you can distinguish methods, apply formulas quickly, and identify the impact each method has on profit.

Here is a grounding analogy: depreciation is like eating a loaf of bread slice by slice (the cost of the whole loaf is consumed over time), while inventory valuation is deciding which slice you eat first — the one you bought yesterday or the one from last week.


Deep Dive

Depreciation: Core Methods

1. Straight Line Method (SLM)

Also called the Fixed Instalment Method (समान किश्त विधि in Indian classrooms).

Formula:

Annual Depreciation = (Cost of Asset − Scrap Value) / Useful Life

Depreciation Rate % = (Annual Depreciation / Cost) × 100

The key feature: the same rupee amount is charged every year. The book value decreases in a straight line from cost to scrap value.

When the examiner gives you: Cost, Scrap Value (or Residual/Salvage Value), and Useful Life — use SLM.

Example: Machine cost ₹1,20,000, scrap ₹20,000, life 10 years. Depreciation = (1,20,000 − 20,000) / 10 = ₹10,000 per year.

Characteristics of SLM:

2. Written Down Value Method (WDV)

Also called Diminishing Balance Method or Reducing Balance Method (ह्रासमान शेष विधि).

Formula:

Depreciation for Year = Book Value at Start of Year × Rate %

Book Value at End of Year n = Cost × (1 − r)^n

where r is the depreciation rate as a decimal.

The key feature: depreciation is higher in early years and reduces progressively. The asset never fully reaches zero book value mathematically (it asymptotically approaches zero).

When the examiner gives you: Cost, Rate %, and asks for book value after n years — use the formula Cost × (1 − r)^n.

Example: Machine cost ₹80,000, rate 25%, after 2 years:

Or directly: 80,000 × (0.75)² = 80,000 × 0.5625 = ₹45,000.

Characteristics of WDV:

3. Sum of Years' Digits Method (SYD)

An accelerated depreciation method (like WDV) but calculated differently.

Formula:

Sum of Years' Digits (SYD) = n(n+1)/2 where n = useful life

Depreciation for Year t = (Remaining Useful Life at Start of Year t / SYD) × Depreciable Amount

Depreciable Amount = Cost − Scrap Value

Example: Machine cost ₹1,20,000, scrap ₹20,000, life 5 years.

Inventory Valuation: Core Methods

Inventory valuation determines what goes into Cost of Goods Sold (COGS) and what remains as Closing Stock.

FIFO — First In, First Out

The oldest stock is assumed to be sold first. Closing stock is valued at the most recent purchase prices.

In a rising price environment:

LIFO — Last In, First Out

The newest stock is assumed to be sold first. Closing stock is valued at the oldest purchase prices.

In a rising price environment:

Weighted Average Method

A single average cost per unit is calculated and applied to both goods sold and closing stock.

Weighted Average Cost = Total Cost of Goods Available / Total Units Available

This method smooths out price fluctuations. It is the most commonly used method in India under AS-2.

Key Comparison: Impact on Profit (Rising Prices)

| Method | COGS | Closing Stock | Profit | |--------|------|---------------|--------| | FIFO | Lowest | Highest | Highest | | LIFO | Highest | Lowest | Lowest | | Weighted Avg | Middle | Middle | Middle |


Memory Tricks & Shortcuts

patternWDV Power Formula — Skip the Year-by-Year Grind

When the question asks for book value after n years under WDV, never calculate year by year. Use directly: Book Value = Cost × (1 − r)^n. For rate 20%, (1−0.20) = 0.80. For 3 years: multiply by 0.80 three times mentally — 0.80 × 0.80 = 0.64, × 0.80 = 0.512. So ₹1,00,000 at 20% WDV for 3 years = ₹51,200. Year-by-year method: 6 multiplication steps. Direct formula: 2 steps. Time saved: approximately 30 seconds per question.

patternSLM Answer in One Line — No Formula Memorisation Needed

For SLM questions, the examiner always gives you Cost, Scrap Value, and Life. The answer is always: (Cost − Scrap) ÷ Life. Train your eye to spot these three numbers and divide immediately. For ₹1,20,000 cost, ₹20,000 scrap, 10 years life: (1,20,000 − 20,000) = 1,00,000 ÷ 10 = ₹10,000. One subtraction, one division. Standard reading-plus-formula approach takes 45 seconds; this pattern recognition takes under 10 seconds.

patternSYD Fraction — Count Down from n

For SYD, the fraction for any year t is: (n − t + 1) / SYD. You do not need to build the full table. For a 5-year asset, Year 3 fraction = (5 − 3 + 1) / 15 = 3/15. The numerator is simply the remaining life at the start of that year. Memorise: "Remaining Life over SYD." This eliminates the need to write out all fractions — saves 4 steps compared to building the full depreciation schedule.

eliminationFIFO vs LIFO Profit Direction — Rising Prices Trigger

When the question asks which method gives higher profit in a period of rising prices, eliminate LIFO immediately — it charges recent higher costs first, suppressing profit. FIFO charges old lower costs, inflating profit. The trigger phrase is "rising prices" → FIFO = higher profit. If the question says "falling prices," reverse the logic. This binary elimination works on every FIFO/LIFO comparison question — standard approach of tracing through numbers takes 60 seconds; trigger-word recognition takes 5 seconds.

patternWDV Successive Multiplication — The 0.75 Trick for 25% Rate

For the very common 25% WDV rate questions: (1 − 0.25) = 0.75. Memorise 0.75^2 = 0.5625 and 0.75^3 = 0.421875. For a ₹80,000 machine at 25% after 2 years: 80,000 × 0.5625 = ₹45,000 (directly). For the 20% rate: 0.80^2 = 0.64, 0.80^3 = 0.512. Keeping these squares and cubes memorised converts a 3-step iterative calculation into a single multiplication.


Fast-Solving Framework

Read the question and identify the method being tested before touching numbers.

Step 1 — Identify the method:

Step 2 — Apply the direct formula:

Step 3 — Sanity check:

Watch out for: questions that give you Rate% under SLM — that means (Annual Depreciation / Cost) × 100, not on depreciable amount. Re-read whether rate is "on cost" or "on WDV."


Solved PYQs

Why this question: The SLM formula is the single most-tested depreciation concept in SSC CGL Finance papers. This is a direct one-formula question — if you fumble here, it costs you an easy mark.

Previous Year Questionपिछले वर्ष का प्रश्न
A machine is purchased for ₹1,20,000. Its scrap value at the end of its useful life of 10 years is ₹20,000. What is the annual depreciation under the Straight Line Method (SLM)?
एक मशीन ₹1,20,000 में खरीदी जाती है। 10 साल की उपयोगी आयु के अंत में उसका रद्दी मूल्य ₹20,000 है। स्ट्रेट लाइन मेथड (SLM) के तहत वार्षिक मूल्यह्रास क्या होगा?
  1. ₹14,000
  2. ₹8,000
  3. ₹12,000
  4. ₹10,000
  1. ₹14,000
  2. ₹8,000
  3. ₹12,000
  4. ₹10,000
Solutionसमाधान
Under SLM, Annual Depreciation = (Cost – Scrap Value) / Useful Life = (1,20,000 – 20,000) / 10 = 1,00,000 / 10 = ₹10,000. This fixed amount is charged every year over the asset's useful life.
SLM में वार्षिक मूल्यह्रास = (लागत – रद्दी मूल्य) / उपयोगी आयु = (1,20,000 – 20,000) / 10 = 1,00,000 / 10 = ₹10,000। यह निश्चित राशि हर साल आस्ति की उपयोगी आयु में चार्ज की जाती है।

Solving path: Identify: Cost = ₹1,20,000, Scrap = ₹20,000, Life = 10 years. Apply SLM formula: (1,20,000 − 20,000) / 10 = 1,00,000 / 10 = ₹10,000. Option D. Time: under 15 seconds.


Why this question: WDV after two years tests whether you can apply the reducing balance correctly. The trap is applying 25% on the original cost in Year 2 instead of the Year 1 closing balance.

Previous Year Questionपिछले वर्ष का प्रश्न
Under the Written Down Value (WDV) method, a machine costing ₹80,000 is depreciated at 25% per annum. What is the book value of the machine at the end of the second year?
अवक्षयित मूल्य (WDV) विधि के अंतर्गत, ₹80,000 की एक मशीन पर प्रतिवर्ष 25% की दर से मूल्यह्रास लगाया जाता है। दूसरे वर्ष के अंत में मशीन का बुक मूल्य क्या होगा?
  1. ₹50,000
  2. ₹45,000
  3. ₹48,000
  4. ₹40,000
  1. ₹50,000
  2. ₹45,000
  3. ₹48,000
  4. ₹40,000
Solutionसमाधान
End of Year 1: WDV = 80,000 × (1 − 0.25) = 80,000 × 0.75 = ₹60,000. End of Year 2: WDV = 60,000 × 0.75 = ₹45,000. In WDV method, depreciation is applied on the reducing balance each year.
पहले वर्ष के अंत में: WDV = 80,000 × 0.75 = ₹60,000। दूसरे वर्ष के अंत में: WDV = 60,000 × 0.75 = ₹45,000। WDV विधि में प्रत्येक वर्ष घटते हुए बैलेंस पर मूल्यह्रास लगाया जाता है।

Solving path: Use direct formula: 80,000 × (0.75)^2 = 80,000 × 0.5625 = ₹45,000. Option B. Alternatively: Year 1 WDV = 80,000 − 20,000 = 60,000; Year 2 depreciation = 60,000 × 25% = 15,000; Year 2 WDV = 60,000 − 15,000 = ₹45,000. Time: 20 seconds using direct formula.


Why this question: SYD is less frequently tested but is a favourite for "surprise" questions. The key is computing the correct fraction for the specific year asked.

Previous Year Questionपिछले वर्ष का प्रश्न
A machine costing ₹1,20,000 has a useful life of 5 years and a residual value of ₹20,000. Using the Sum of Years' Digits (SYD) method, what is the depreciation charge for the 3rd year?
₹1,20,000 की लागत वाली एक मशीन की उपयोगी आयु 5 वर्ष है और अवशिष्ट मूल्य ₹20,000 है। वर्षों के अंकों के योग (SYD) विधि का उपयोग करते हुए, तीसरे वर्ष का मूल्यह्रास शुल्क क्या होगा?
  1. ₹20,000
  2. ₹33,333
  3. ₹26,667
  4. ₹13,333
  1. ₹20,000
  2. ₹33,333
  3. ₹26,667
  4. ₹13,333
Solutionसमाधान
Depreciable amount = ₹1,20,000 − ₹20,000 = ₹1,00,000. Sum of years' digits = 1+2+3+4+5 = 15. For the 3rd year, the remaining life at the start of year 3 is 3 years, so the fraction = 3/15 = 1/5. Depreciation = 1/5 × ₹1,00,000 = ₹20,000.
मूल्यह्रास योग्य राशि = ₹1,20,000 − ₹20,000 = ₹1,00,000। वर्षों के अंकों का योग = 1+2+3+4+5 = 15। तीसरे वर्ष के लिए, शुरुआत में शेष आयु 3 वर्ष है, अतः भिन्न = 3/15 = 1/5। मूल्यह्रास = 1/5 × ₹1,00,000 = ₹20,000।

Solving path: Depreciable amount = 1,20,000 − 20,000 = ₹1,00,000. SYD = 5×6/2 = 15. Year 3 remaining life = 3, so fraction = 3/15 = 1/5. Depreciation = (1/5) × 1,00,000 = ₹20,000. Option A. Time: 30 seconds.


Why this question: This question requires WDV over 3 years with a realistic asset cost. It tests whether you can chain the multiplication cleanly or use the direct formula. Note the date context — April 2020 to March 2023 is exactly 3 financial years, no partial-year trap here.

Previous Year Questionपिछले वर्ष का प्रश्न
A machine was purchased on 1st April 2020 for ₹5,00,000. The company uses the Written Down Value (WDV) method of depreciation at 20% per annum. After 3 years, the machine's book value on 31st March 2023 would be:
एक मशीन 1 अप्रैल 2020 को ₹5,00,000 में खरीदी गई। कंपनी 20% प्रति वर्ष की दर से WDV (Written Down Value) पद्धति से मूल्यह्रास लगाती है। 3 वर्षों के बाद, 31 मार्च 2023 को मशीन का बही मूल्य क्या होगा?
  1. ₹2,56,000
  2. ₹3,00,000
  3. ₹2,40,000
  4. ₹2,00,000
  1. ₹2,56,000
  2. ₹3,00,000
  3. ₹2,40,000
  4. ₹2,00,000
Solutionसमाधान
Under WDV method, depreciation is charged on the reducing balance. Year 1: ₹5,00,000 × 20% = ₹1,00,000; WDV = ₹4,00,000. Year 2: ₹4,00,000 × 20% = ₹80,000; WDV = ₹3,20,000. Year 3: ₹3,20,000 × 20% = ₹64,000; WDV = ₹2,56,000. Hence the book value after 3 years is ₹2,56,000.
WDV पद्धति में मूल्यह्रास घटते हुए बही मूल्य पर लगाया जाता है। वर्ष 1: ₹5,00,000 × 20% = ₹1,00,000; WDV = ₹4,00,000। वर्ष 2: ₹4,00,000 × 20% = ₹80,000; WDV = ₹3,20,000। वर्ष 3: ₹3,20,000 × 20% = ₹64,000; WDV = ₹2,56,000। इसलिए 3 वर्षों के बाद बही मूल्य ₹2,56,000 है।

Solving path: Rate = 20%, so multiplier = 0.80. After 3 years: 5,00,000 × (0.80)^3 = 5,00,000 × 0.512 = ₹2,56,000. Option A. If you don't remember 0.80^3 = 0.512: Year 1 = 5,00,000 × 0.8 = 4,00,000; Year 2 = 4,00,000 × 0.8 = 3,20,000; Year 3 = 3,20,000 × 0.8 = 2,56,000. Time: 25 seconds using direct formula.


Why this question: Another WDV three-year question but with a different starting cost. Tests pattern recognition — if you noticed the 20% WDV pattern from the previous question, this should take under 20 seconds.

Previous Year Questionपिछले वर्ष का प्रश्न
Under the Written Down Value (WDV) method, an asset worth ₹1,00,000 is depreciated at 20% per annum. What is the book value at the end of 3 years?
लिखित मूल्य (WDV) विधि के अंतर्गत, ₹1,00,000 मूल्य की एक परिसंपत्ति पर 20% प्रति वर्ष की दर से मूल्यह्रास लगाया जाता है। 3 वर्षों के अंत में पुस्तक मूल्य क्या होगा?
  1. ₹48,000
  2. ₹64,000
  3. ₹51,200
  4. ₹40,000
  1. ₹48,000
  2. ₹64,000
  3. ₹51,200
  4. ₹40,000
Solutionसमाधान
Year 1: 1,00,000 × 0.80 = ₹80,000. Year 2: 80,000 × 0.80 = ₹64,000. Year 3: 64,000 × 0.80 = ₹51,200. The book value at end of 3 years is ₹51,200.
वर्ष 1: 1,00,000 × 0.80 = ₹80,000. वर्ष 2: 80,000 × 0.80 = ₹64,000. वर्ष 3: 64,000 × 0.80 = ₹51,200. 3 वर्षों के अंत में पुस्तक मूल्य ₹51,200 है।

Solving path: 1,00,000 × (0.80)^3 = 1,00,000 × 0.512 = ₹51,200. Option C. Do not be distracted by ₹64,000 (which is the Year 2 book value — a classic decoy). Time: 10 seconds if you have memorised 0.80^3 = 0.512.


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