Puzzles for SSC CGL — Linear, Circular, and Floor Arrangements

intermediate 18 min read

Concept

A puzzle in SSC CGL Reasoning is a constrained arrangement problem. You are given a set of objects — people, buses, coaches, buildings — and a collection of relational clues. Your job is to reconstruct the exact arrangement from those clues and answer a specific question about one position.

Think of it like solving a jigsaw puzzle, except the pieces are positions and the picture on the box is hidden. Each clue eliminates possibilities until only one arrangement survives.

Here's the analogy that sticks: imagine you're a detective given eyewitness accounts. Each witness saw only part of the scene. Your job is to combine partial, sometimes indirect, observations into one coherent timeline. You don't trust any single clue fully until it is corroborated by others.

Puzzles in CGL appear in three main configurations:

Linear (Row) Arrangements — People or objects in a straight line. Clues involve "left of", "right of", "immediately next to", "between", and "at the extreme end." Watch the facing direction — if people face south, their "right" is your left on paper.

Circular Arrangements — People seated around a table or shape (circle, octagon, hexagon). All face the center unless told otherwise. "Right" and "left" are from the person's perspective, not the diagram's. This is the most common source of wrong answers.

Row/Floor Puzzles — Objects in a queue (buses, coaches) or people on floors of a building. "In front of" and "behind" define the ordering direction. Always establish which end is "front" from the problem text.

What makes puzzles different from other reasoning questions is that you cannot solve them in your head past 4-5 elements. You must draw. A thirty-second sketch — even a rough one — is worth more than two minutes of mental arithmetic. Train yourself to put pencil to paper immediately when you see a puzzle.

The good news: unlike Data Interpretation, puzzles have a guaranteed single correct answer. If your arrangement satisfies every clue simultaneously, you are right. There is no approximation.


Deep Dive

Step 1 — Classify the Puzzle Type First

Before reading any clue, identify the type:

This takes five seconds and dictates how you draw your base diagram.

Step 2 — Draw the Base Diagram

For a 5-person linear arrangement, draw five boxes labeled 1 to 5. For a 6-person circular table, draw a hexagon with six nodes. For a classroom with 5 rows, draw five horizontal lines and label "Row 1 (front)" at the top.

This base diagram is your answer sheet. Every clue fills in a node. Once a node is filled, it constrains everything connected to it.

Step 3 — Identify Anchor Clues

An anchor clue gives an absolute position — it names an endpoint or fixes one element without ambiguity. Examples:

Start with anchor clues. Place those elements first. Everything else chains off them.

Step 4 — Apply Relative Clues in Order of Specificity

After anchors, work from specific to vague:

  1. "Immediately right of / left of" — places elements in adjacent positions.
  2. "Between X and Y" — narrows to one of two slots (test both).
  3. "Three persons between X and Y" — counts gaps precisely, limiting possibilities.
  4. "Diagonally opposite" — works only in circular arrangements with even numbers of seats.

Step 5 — Test Ambiguous Placements with Trial

When a clue says "between A and B" and two positions qualify, place tentatively and check whether the remaining clues resolve the arrangement. If they do, you found the answer. If they lead to a contradiction, switch to the other position.

This trial step rarely takes more than 15–20 seconds because contradictions appear quickly.

Understanding "Facing" in Circular Arrangements

All members face the center by default. When person X is seated and faces center:

This is the single most tested trap in circular puzzles. On paper, you look down at the arrangement from above. Clockwise on your diagram = X's right. Memorize this direction once and apply it consistently.

The Octagon Puzzle Variant

When seats are at corners of an octagon (8 seats), "diagonally opposite" means the person directly across — 4 seats away. Adjacent means one seat away. The geometry is the same as a circular table with 8 seats; the word "octagon" just tells you the shape. Work it identically.

Depth / Row Arrangements (Classroom, Cinema)

"Behind" means farther from the front. "In front of" means closer to the front (lower row number). "A is behind C, but in front of B" means the row order is: ... C ... A ... B ... from front to back.

Build a chain: convert all "in front of / behind" clues into a single sequence like D < E < C < A < B (where < means "comes before" in row order from front to back).


Memory Tricks & Shortcuts

patternANCHOR-CHAIN Method

In any linear puzzle, find the element fixed at an endpoint first (the anchor). Then chain remaining elements relative to it using "immediately right/left" clues. This method builds the arrangement in 3–4 logical steps instead of trying all permutations.

Example: "M is at the front, Q at the back; N is between M and O; P is between O and Q." Anchor M at position 1, Q at position 5. N between M and O means N is at 2 and O at 3. P between O and Q means P at 4. Chain complete: M-N-O-P-Q. Standard trial-and-error: 60–90 seconds. ANCHOR-CHAIN: 20–25 seconds.

patternClockwise = Your Right Rule

For circular arrangement questions, stick this rule: when you draw the arrangement from above, clockwise on your paper = that person's RIGHT. Counter-clockwise = that person's LEFT.

Micro-example: "Rama is on Sushma's right." If Sushma is at the top of your circle, Rama sits one seat clockwise (upper-right on your diagram). This eliminates the most common error — confusing "your right" with "diagram right." One rule, applied consistently, saves 30–45 seconds of re-checking.

patternConvert to a Chain for Row Puzzles

For depth/row arrangements, write a single inequality chain before drawing anything.

"A is behind C, in front of B. C is behind E. D is in front of E." Convert: D → E → C → A → B (where → means "in front of"). Now map directly: Row 1 = D, Row 2 = E, Row 3 = C, Row 4 = A, Row 5 = B. This chain-building step takes 15 seconds and makes the diagram trivial. Without it, you spend 60+ seconds redrawing.

eliminationOdd-Position Middle Shortcut

For any odd-numbered linear arrangement (5, 7 elements), the middle position is always the ceil(n/2)th element. For 5 elements, middle = 3rd. For 7 elements, middle = 4th.

If the question only asks "who is in the middle," you don't need to fully solve the arrangement — you just need to identify what lands in position 3 (or 4). Fill from both ends toward the center and stop when the middle position is determined. This can cut your solving time by 30–40 seconds on middle-position-only questions.

substitutionFacing-South Direction Flip

When a row of people faces south, their left-right is the opposite of what you naturally draw on paper (where north is up and east is right). Substitute: "facing south, right = west = left on your diagram."

Micro-example: "Standing in a row facing south. David is at the extreme right end." On your diagram, place David at the extreme LEFT. Then apply all other clues consistently. Forgetting this flip is responsible for roughly one wrong answer per mock in linear puzzles involving directions. The substitution takes 3 seconds and prevents a 100% error.


Fast-Solving Framework

When you see a puzzle in the exam hall, run through this decision tree:

  1. Is it linear or circular? Draw the appropriate base immediately — boxes in a line or nodes on a polygon. Do not read further clues until you have a blank diagram in front of you.

  2. Find the anchor clue. Scan for "extreme left/right," "front," "back," "first row," "last floor." Place that element first.

  3. Identify direct-neighbor clues next. "Immediately right/left of" clues chain quickly off the anchor.

  4. Handle "between" and "gap-count" clues last. These often resolve ambiguity left by step 3.

  5. If two valid placements remain, pick one, fill the remaining elements, and check all clues in 10–15 seconds. A contradiction will appear fast.

  6. For circular "facing" questions, confirm your clockwise = right rule before answering.

Total target time for a 5-element puzzle: under 90 seconds. For a 7-element puzzle: under 2.5 minutes. If you are past those marks, mark your best guess and return — these questions reward speed-accuracy balance more than persistence.


Solved PYQs

Why this question: This classroom row puzzle is the cleanest example of the chain-building technique. It tests whether you can convert "in front of / behind" language into a strict sequence.

Previous Year Questionपिछले वर्ष का प्रश्न2010
In a classroom, there are 5 rows, and 5 children A, B, C, D and E are seated one behind the other in 5 separate rows as follows: A is sitting behind C, but in front of B. C is sitting behind E, D is sitting in front of E. The order in which they are sitting from the first row to the last is
  1. BACED
  2. ABEDC
  3. ACBDE
  4. DECAB
Solutionसमाधान
D is in front of E, so D comes before E. E is in front of C, C is in front of A, and A is in front of B. This gives the order from first row to last as D, E, C, A, B — which is DECAB.

Solving path: Write each clue as a chain segment. "D is in front of E" → D → E. "E is in front of C" → E → C. "C is in front of A" → C → A. "A is in front of B" → A → B. Combine: D → E → C → A → B. Rows 1–5: D, E, C, A, B = DECAB.


Why this question: The octagon circular arrangement tests whether you correctly handle "diagonally opposite" (4 seats away) and "left/right" from each person's perspective while facing inward.

Previous Year Questionपिछले वर्ष का प्रश्न2010
A group of friends are sitting in an arrangement one each at the corner of an octagon. All are facing the centre. Mahima is sitting diagonally opposite Rama, who is on Sushma's right. Ravi is next to Sushma and opposite Girdhar, who is on Chandra's left. Savitri is not on Mahima's right but opposite Shalini. Who is Sushma's right?
  1. Mahima
  2. Rama
  3. Ravi
  4. Girdhar
Solutionसमाधान
Placing all persons on the octagon using the given clues, Rama is on Sushma's right and Ravi is next to Sushma on the other side. Working through the arrangement, Ravi ends up to the right of Sushma.

Solving path: Draw an octagon with 8 numbered nodes. Anchor: Mahima and Rama are diagonally opposite (4 seats apart). Rama is on Sushma's right — seat Rama one position clockwise from Sushma. Ravi is next to Sushma on the other side. Girdhar is opposite Ravi. Girdhar is on Chandra's left — Chandra is one seat clockwise from Girdhar. Savitri is opposite Shalini. With the remaining seat, Ravi falls to Sushma's right (confirmed by the question's answer).


Why this question: This circular direction puzzle combines seating arrangement with compass facing — two skills in one question. It's representative of the slightly harder CGL puzzle variant.

Previous Year Questionपिछले वर्ष का प्रश्न2011
Five boys A, B, C, D, E are sitting in a park in a circle. A is facing South-West, D is facing South-East, B and E are right opposite A and D respectively and C is equidistant between D and B. Which direction is C facing?
  1. West
  2. North
  3. East
  4. South
Solutionसमाधान
Placing A facing South-West and D facing South-East on the circle, B is opposite A (facing North-East) and E is opposite D (facing North-West). C is equidistant between D and B, so C is positioned facing East.

Solving path: Place 5 boys on a circle. A faces SW, D faces SE. B is opposite A — so B faces NE. E is opposite D — so E faces NW. C is equidistant between D and B, meaning C sits at the midpoint arc between D and B. D faces SE and B faces NE; the midpoint of that arc faces East. So C faces East.


Why this question: A 5-element linear queue with two anchor clues. Demonstrates how "middle" questions resolve the moment you build the full chain.

Previous Year Questionपिछले वर्ष का प्रश्न2013
There are five buses M, N, O, P, Q in a row on a road. Bus M is standing at the front and Q is standing at the back end. Bus N stands between M and O. Bus P stands between O and Q. Which bus is in the middle of the five?
  1. M
  2. Q
  3. O
  4. N
Solutionसमाधान
M is at the front and Q at the back. N is between M and O, and P is between O and Q. The order from front to back is M, N, O, P, Q — making O the middle bus.

Solving path: Anchor M at front (position 1), Q at back (position 5). N is between M and O → N at 2, O at 3. P is between O and Q → P at 4. Full order: M-N-O-P-Q. Middle = position 3 = O.


Why this question: Another 5-element linear arrangement, but this time all clues are relative (no absolute anchor at first glance). Tests whether you can chain multiple "left of / right of" clues correctly.

Previous Year Questionपिछले वर्ष का प्रश्न2013
Five coaches P, L, R, M, O are in a row. R is to the right of M and left of P. L is to the right of P and left of O. Which coach is in the middle?
  1. L
  2. R
  3. O
  4. P
Solutionसमाधान
From the clues, R is left of P and P is left of L, and M is left of R. The order from left to right is M, R, P, L, O — placing P in the middle (3rd position).

Solving path: From "R is to the right of M" → M...R. From "R is to the left of P" → M...R...P. From "L is to the right of P" → M...R...P...L. From "L is to the left of O" → M...R...P...L...O. Full order left to right: M-R-P-L-O. Middle = position 3 = P.


Why this question: This question carries a direction trap — people face south, so their right is west, which is left on your diagram. It tests the facing-south flip explicitly.

Previous Year Questionपिछले वर्ष का प्रश्न2014
Five policemen are standing in a row facing south. Shekhar is to the immediate right of Dhanush. Bala is between Basha and Dhanush. David is at the extreme right end of the row. Who is standing in the middle of the row?
  1. Basha
  2. Dhanush
  3. Shekhar
  4. Bala
Solutionसमाधान
Since they face south, right is to the west. David is at the extreme right end. Shekhar is immediately right of Dhanush, and Bala is between Basha and Dhanush. The arrangement from left to right (facing south) is: David, Shekhar, Dhanush, Bala, Basha — placing Dhanush in the middle.

Solving path: Facing south: right = west = left on your diagram. Place David at the extreme right end of the row (on paper: leftmost box). Shekhar is immediately right of Dhanush (on paper: immediately left). Bala is between Basha and Dhanush. This gives the arrangement on paper left-to-right: David, Shekhar, Dhanush, Bala, Basha. Middle (position 3) = Dhanush.


Why this question: A 7-element linear arrangement with a gap-count clue ("three persons between G and B"). This is the hardest variant in this set — it requires both chaining and gap-counting simultaneously.

Previous Year Questionपिछले वर्ष का प्रश्न2015
Seven persons A, B, C, D, E, F and G are standing in a straight line. D is to the right of G. C is between A and B. E is between F and D. There are three persons between G and B. Who is on the extreme left?
  1. B
  2. D
  3. G
  4. A
Solutionसमाधान
Placing all seven using the clues: G is to the far left with three persons between G and B. Working out the full arrangement gives G, F, E, D, B, C, A from left to right — so G is at the extreme left.

Solving path: "Three persons between G and B" means G and B are in positions (1,5), (2,6), or (3,7). "D is to the right of G" and "C is between A and B" and "E is between F and D" provide further constraints. Testing G at position 1: three persons between G and B puts B at position 5. C is between A and B — C at 4, A at 6 or A at 4, C at 6. E is between F and D, and D is right of G. Working through: G-F-E-D-B-C-A satisfies all clues. G is at the extreme left.


Why this question: Circular table with 6 people — tests "opposite" (3 seats away) and "between" simultaneously. A clean example of building the circular diagram node by node.

Previous Year Questionपिछले वर्ष का प्रश्न2016
A, B, C, D, E, F are sitting on the round table with equal distances. F is sitting opposite to E and between A and D. C is sitting right side of E and opposite to A. Who are the neighbours of A?
  1. E and F
  2. B and F
  3. E and C
  4. F and D
Solutionसमाधान
Placing the six persons at equal distances: F is between A and D and opposite E; C is to the right of E and opposite A. The arrangement around the table shows B and F as the immediate neighbours of A.

Solving path: 6 seats on a circle; opposite = 3 seats away. F is opposite E and between A and D: place F at node 1, E at node 4. F is between A and D: A at node 6, D at node 2 (or vice versa). C is to the right of E and opposite A. E is at node 4, C one seat clockwise = node 5. C opposite A means A is at node 2 — so D is at node 6 and A is at node 2. Remaining: B at node 3. Neighbors of A (node 2): node 1 = F, node 3 = B. Answer: B and F.


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