Percentage for UP Police Constable — Complete Concept, Tricks & PYQs

beginner 18 min read

Concept

Percentage is one of the most frequently tested topics in UP Police Constable quant — and it shows up disguised in profit-loss, interest, and data interpretation too. So getting this right is not optional.

Here is the core idea: "percent" means "per hundred" (Latin: per centum). When you say 40%, you mean 40 out of every 100 parts. That is it. Everything else — percentage change, reverse percentage, comparing two quantities — is just this one idea applied in different directions.

Think of it this way: imagine you have a chapati divided into 100 equal pieces. If someone takes 40 pieces, they took 40% of the chapati. If they took 32 pieces, that is 32%. The total (100 pieces) is your base — always called the denominator in the formula.

The general formula:

Percentage=PartWhole×100\text{Percentage} = \frac{\text{Part}}{\text{Whole}} \times 100

Now, where students go wrong — they mix up which quantity is the "whole." In the question "what percentage of V is H?", H is the part and V is the whole. In "what percentage of H is V?", V is the part and H is the whole. These give different answers. Identifying the base correctly is 80% of the battle in percentage problems.

The three types of questions UP Police Constable papers repeat:

  1. Find the percentage — given the part and whole, calculate the %.
  2. Find the value — given the % and the whole (or the %), calculate the missing number.
  3. Percentage change — how much did something increase or decrease relative to the original?

Everything in the PYQs you will see below falls into one of these three buckets.


Deep Dive

The Core Formula — Three Versions

From Percentage = (Part / Whole) × 100, you can derive:

Part=Percentage×Whole100\text{Part} = \frac{\text{Percentage} \times \text{Whole}}{100}

Whole=Part×100Percentage\text{Whole} = \frac{\text{Part} \times 100}{\text{Percentage}}

Commit these three rearrangements to memory — not by rote, but by understanding that you are always solving for the missing variable in a three-variable relationship.

Reverse Percentage

Look — this is where most candidates drop marks. If 70% of a number is 56, what is the number?

Using the formula: Whole = (Part × 100) / Percentage = (56 × 100) / 70 = 80.

The shortcut: divide by the percentage and multiply by 100. Or better — use the fraction form: 70% = 7/10, so (7/10) × number = 56 → number = 56 × (10/7) = 80. Fraction form is faster than decimal division for clean percentages.

Percentage Increase and Decrease

Percentage Increase=New ValueOld ValueOld Value×100\text{Percentage Increase} = \frac{\text{New Value} - \text{Old Value}}{\text{Old Value}} \times 100

Percentage Decrease=Old ValueNew ValueOld Value×100\text{Percentage Decrease} = \frac{\text{Old Value} - \text{New Value}}{\text{Old Value}} \times 100

The key rule: the denominator is always the original (old) value, never the new one. This is the single most common error in percentage change problems.

Example: Revenue goes from 35 to 80. Increase = 45. Percentage increase = (45/35) × 100 = 128.57%. Note — the base is 35, not 80.

Multiplier Method for Percentage Change

Instead of calculating increase/decrease separately, use multipliers:

This is faster than writing out the fraction and especially useful when changes are applied successively.

Example: A number is increased by 25%. New value = Original × 1.25. If original = 80, new = 80 × 1.25 = 100.

Successive Percentage Changes

When a number is first increased by a% and then decreased by b%, the net change is NOT simply (a - b)%. The formula for net change is:

Net % change=abab100\text{Net \% change} = a - b - \frac{ab}{100}

When a = b (same percentage up then down):

Net change=a2100%\text{Net change} = -\frac{a^2}{100}\%

The negative sign means it is always a decrease. A 20% increase followed by 20% decrease = -(20²/100) = -4%. This is a direct PYQ pattern.

"X% of Y = Y% of X" Property

This is a useful symmetry property: 8% of 25 = 25% of 8 = 2. This matters when one calculation is easier than the other. 25% is just dividing by 4 — that is much faster than calculating 8% of 25 the long way.

Converting Common Percentages to Fractions

Memorise these — they save 20-30 seconds per question:

| Percentage | Fraction | |-----------|---------| | 10% | 1/10 | | 12.5% | 1/8 | | 16.67% | 1/6 | | 20% | 1/5 | | 25% | 1/4 | | 33.33% | 1/3 | | 37.5% | 3/8 | | 50% | 1/2 | | 62.5% | 5/8 | | 75% | 3/4 |

When you see 16.67% in a question, immediately think 1/6. When you see 312.5%, think 25/8.


Memory Tricks & Shortcuts

patternFraction Flip for Reverse Percentage

When the question asks "V is 32% of H, so H is what % of V?", you are being asked to flip the relationship.

If V = (32/100) × H, then H = (100/32) × V = (25/8) × V = 312.5% of V.

The rule: if A is P% of B, then B is (100/P) × 100 % of A, which simplifies to (10000/P)%.

So for 32%: 10000/32 = 312.5%. One division step.

Standard method: set up equation, solve for H, divide — 4 steps, ~40 seconds. This shortcut: one division, ~10 seconds.

patternNet Change Formula for Successive Percentages

When a value goes up by r% then down by r% (or any two successive changes), skip the two-step calculation entirely.

Formula: Net % = a - b - (ab/100) where increase is positive, decrease is negative.

For "20% increase then 20% decrease": 20 - 20 - (20×20)/100 = 0 - 4 = -4%.

Standard method: take 100, increase to 120, decrease 20% of 120 = 24, so 120 - 24 = 96. Change = -4%. That is 3 steps, ~35 seconds. Formula: 1 step, ~8 seconds. Use whenever both percentage values are given together.

patternX% of Y = Y% of X Swap

When asked for 16% of 25 or 32% of 25, swap the percentages.

16% of 25 = 25% of 16 = 16/4 = 4. Done. 32% of 25 = 25% of 32 = 32/4 = 8. Done.

25% of anything is just dividing by 4 — you can do that instantly. This works whenever one side of the swap gives you a "clean" percentage (25%, 50%, 20%, 10%, etc.).

Standard method: 16 × 25 / 100 = 400/100 = 4 (~20 seconds). Swap method: 25/4 = 4 (~5 seconds). Saves one multiplication step.

eliminationDifference Shortcut for Vote/Election Problems

When two candidates get a% and b% of total votes, the extra votes for the winner = (b - a)% of total.

You do not need to calculate each candidate's votes separately and subtract.

Example: P gets 42%, Q gets 58%, total = 4500. Difference = 16% of 4500 = 720. That is one multiplication instead of two multiplications and a subtraction.

Standard method: Q's votes = 58% of 4500 = 2610; P's votes = 42% of 4500 = 1890; difference = 720. Three steps, ~40 seconds. Shortcut: one step, ~12 seconds.

estimationTable/DI Percentage — Anchor on the Base

In table-based questions with a given total income or total marks, calculate only the specific percentage asked — do not calculate all rows unless asked.

Example: Total income = 57,000. House rent = 20%. Remaining = 80% of 57,000 = 45,600.

Instead of: computing 20% of 57,000 = 11,400 and subtracting from 57,000. Directly compute 80% = 0.8 × 57,000. One step vs two steps. When the table has 5-6 rows, this focus saves you from reading and computing unnecessary data — saves 30-45 seconds per DI set.


Fast-Solving Framework

Read the question and classify it in the first 5 seconds:

Type 1 — Find the number (reverse percentage): "X% of a number is Y, find the number." Formula: Number = Y × 100 / X. Or use fraction: if X% = m/n, then number = Y × (n/m).

Type 2 — Find the percentage: "What % of A is B?" Formula: (B/A) × 100. Identify A as the base — A is the "of" quantity.

Type 3 — Percentage change: "Change from old to new." Formula: (New - Old) / Old × 100. Base is always OLD value.

Type 4 — Successive changes: Two percentage changes one after another. Use net change formula: a - b - ab/100. Saves you from two-step calculation.

Type 5 — Table/DI percentage: Only compute the row or column asked. Use multiplier directly on total.

Decision rule: if the question has two successive percentage changes, always reach for the formula. If it has a table, ignore rows not asked. If it says "what % of X is Y", the base is X, not Y.


Solved PYQs

Why this question: Tests the two-step chain — first find the original number using reverse percentage, then apply a new percentage change using the multiplier method.

Previous Year Questionपिछले वर्ष का प्रश्न2026
यदि किसी संख्या का 70%, 56 है, तो उस संख्या को 25% बढ़ाने के बाद उसका मान क्या होगा?
यदि किसी संख्या का 70%, 56 है, तो उस संख्या को 25% बढ़ाने के बाद उसका मान क्या होगा?
  1. 70
  2. 50
  3. 100
  4. 60
  1. 70
  2. 50
  3. 60
  4. 100
Solutionसमाधान
70% of number = 56 → number = 56×100/70 = 80. After 25% increase: 80 × 1.25 = 100.

Solving path: 70% of number = 56. So number = 56 × 100/70 = 80. Now increase by 25%: 80 × 1.25 = 100. Both steps use the core formulas — this is a Type 1 + multiplier chain.


Why this question: Classic reverse percentage with relationship flip. The most common trap: candidates calculate V% of H instead of H% of V.

Previous Year Questionपिछले वर्ष का प्रश्न2026
If V is 32% of H, then what percent of V is H?
यदि V, H का 32% है, तो H, V का कितना प्रतिशत है?
  1. 198.5%
  2. 312.5%
  3. 264.5%
  4. 426.5%
  1. 312.5%
  2. 264.5%
  3. 198.5%
  4. 426.5%
Solutionसमाधान
V = 32% of H → H = (100/32) × V = 3.125 × V = 312.5% of V.

Solving path: V = 32% of H means H = (100/32) × V = 3.125V. So H is 312.5% of V. Use the shortcut: 10000/32 = 312.5. The base in the final answer is V, not H.


Why this question: Standard table/DI application. Tests whether you can extract a single percentage from a multi-row table without getting distracted by other rows.

Previous Year Questionपिछले वर्ष का प्रश्न2026
The table given represents the domestic expenditure of a family in percentage. Study the table and answer the question. (Note: The total monthly income of the family is Rs. 57,000) Expenditure: Provident Fund 10%, Food 28%, Medical 12%, Child Education 22%, House Rent 20%, Entertainment 8%. What is the remaining monthly income after deducting house rent expense from the total income?
दी गई तालिका में एक परिवार के घरेलू व्यय को प्रतिशत में दर्शाया गया है। (नोट: परिवार की कुल मासिक आय 57,000 रुपये है) व्यय: भविष्य निधि 10%, भोजन 28%, चिकित्सा 12%, बच्चों की शिक्षा 22%, मकान का किराया 20%, मनोरंजन 8%। कुल आय में से घर के किराए का खर्च घटाने के बाद शेष मासिक आय कितनी है?
  1. Rs. 48,440
  2. Rs. 45,600
  3. Rs. 40,450
  4. Rs. 47,300
  1. 40,450 रुपये
  2. 47,300 रुपये
  3. 48,440 रुपये
  4. 45,600 रुपये
Solutionसमाधान
House rent = 20% of 57,000 = 11,400. Remaining = 57,000 − 11,400 = 45,600.

Solving path: House rent = 20% of 57,000 = 11,400. Remaining = 57,000 - 11,400 = 45,600. Or directly: (100 - 20)% = 80% of 57,000 = 45,600. Two-second identification of the relevant row, one multiplication.


Why this question: Percentage change from a data table — tests whether you correctly identify the old value (2020 = 35) as the base, not the new value (2022 = 80).

Previous Year Questionपिछले वर्ष का प्रश्न2026
A company's revenue (in Rs. lakhs) for five years is listed as: 2018: 40, 2019: 55, 2020: 35, 2021: 65, 2022: 80. What is the percentage increase in revenue from 2020 to 2022?
एक कंपनी का पाँच वर्षों का राजस्व (लाख रुपये में) इस प्रकार दिया गया है: 2018: 40, 2019: 55, 2020: 35, 2021: 65, 2022: 80. 2020 से 2022 तक राजस्व में कितने प्रतिशत की वृद्धि हुई है?
  1. 120%
  2. 128.57%
  3. 100%
  4. 114.33%
  1. 100%
  2. 114.33%
  3. 120%
  4. 128.57%
Solutionसमाधान
Increase = 80−35 = 45. Percentage increase = (45/35)×100 = 128.57%.

Solving path: Increase = 80 - 35 = 45. Percentage increase = (45/35) × 100. Now 45/35 = 9/7. 9/7 × 100 = 900/7 = 128.57%. Key: base is 35 (the older year), not 80.


Why this question: Tests basic percentage calculation with addition — a high-frequency format in school-mark-based questions.

Previous Year Questionपिछले वर्ष का प्रश्न2026
एक छात्र ने पाँच विषयों में निम्न अंक प्राप्त किए: अंग्रेजी: 72, गणित: 88, विज्ञान: 65, सामाजिक अध्ययन: 79, हिंदी: 81। कुल 500 अंकों में से छात्र ने कितने प्रतिशत अंक प्राप्त किए?
एक छात्र ने पाँच विषयों में निम्न अंक प्राप्त किए: अंग्रेजी: 72, गणित: 88, विज्ञान: 65, सामाजिक अध्ययन: 79, हिंदी: 81। कुल 500 अंकों में से छात्र ने कितने प्रतिशत अंक प्राप्त किए?
  1. 77%
  2. 78%
  3. 79%
  4. 76%
  1. 79%
  2. 78%
  3. 76%
  4. 77%
Solutionसमाधान
Total marks = 72+88+65+79+81 = 385. Percentage = (385/500)×100 = 77%.

Solving path: Add all marks: 72 + 88 + 65 + 79 + 81 = 385. Percentage = (385/500) × 100 = 77%. The addition step is where errors happen — add carefully, left to right: 72+88=160, 160+65=225, 225+79=304, 304+81=385.


Why this question: Election-vote type — tests the difference shortcut. Many candidates compute both candidates' votes separately and subtract. There is a faster path.

Previous Year Questionपिछले वर्ष का प्रश्न2026
दो उम्मीदवार P और Q एक चुनाव में क्रमशः 42% और 58% वोट प्राप्त करते हैं। यदि वोटों की कुल संख्या 4500 थी, तो Q को P से कितने अधिक वोट मिले?
दो उम्मीदवार P और Q एक चुनाव में क्रमशः 42% और 58% वोट प्राप्त करते हैं। यदि वोटों की कुल संख्या 4500 थी, तो Q को P से कितने अधिक वोट मिले?
  1. 880
  2. 540
  3. 460
  4. 720
  1. 540
  2. 720
  3. 460
  4. 880
Solutionसमाधान
Difference in percentage = 58% - 42% = 16%. Extra votes for Q = 16% of 4500 = 720.

Solving path: Difference in % = 58 - 42 = 16%. Extra votes = 16% of 4500 = 720. One multiplication, not three operations.


Why this question: Successive percentage change — the trap is thinking that +20% then -20% cancels out to 0. It does not, and this is a direct formula application question.

Previous Year Questionपिछले वर्ष का प्रश्न2026
A number is first increased by 20% and then decreased by 20%. What is the net percentage change?
एक संख्या पहले 20% बढ़ाई जाती है और फिर 20% घटाई जाती है। शुद्ध प्रतिशत परिवर्तन क्या है?
  1. 4% decrease
  2. 0% (no change)
  3. 6% decrease
  4. 8% increase
  1. 6% कमी
  2. 4% कमी
  3. 8% वृद्धि
  4. 0% (कोई परिवर्तन नहीं)
Solutionसमाधान
Net change = -( r²/100)% = -(400/100)% = -4%, i.e., a 4% decrease.

Solving path: Net change = -(r²/100) = -(400/100) = -4%. It is a 4% decrease. Using numbers to verify: start with 100, increase by 20% → 120, decrease 20% of 120 = 24 → 96. Change = -4%. The formula gives the answer in one step.


Why this question: Percentage of a subset — here you count how many items fail a condition and express that count as a percentage of the total count.

Previous Year Questionपिछले वर्ष का प्रश्न2026
A student's marks in six subjects are shown as: Physics: 78, Chemistry: 82, Mathematics: 90, Biology: 74, English: 68, Computer: 86. If the passing mark is 70 in each subject, what percentage of subjects did the student fail in?
एक छात्र के छह विषयों के अंक इस प्रकार हैं: भौतिकी: 78, रसायन विज्ञान: 82, गणित: 90, जीव विज्ञान: 74, अंग्रेज़ी: 68, कंप्यूटर: 86। यदि प्रत्येक विषय में उत्तीर्ण होने के लिए 70 अंक आवश्यक हैं, तो छात्र कितने प्रतिशत विषयों में अनुत्तीर्ण हुआ?
  1. 12.14%
  2. 13.21%
  3. 16.67%
  4. 15%
  1. 16.67%
  2. 13.21%
  3. 15%
  4. 12.14%
Solutionसमाधान
Only English (68) is below 70. Failed in 1 out of 6 subjects = (1/6)×100 = 16.67%.

Solving path: Check each subject against 70: Physics 78 ✓, Chemistry 82 ✓, Mathematics 90 ✓, Biology 74 ✓, English 68 ✗, Computer 86 ✓. Failed = 1. Percentage = (1/6) × 100 = 16.67%. Use the fraction-to-percentage table: 1/6 = 16.67%.


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