Profit and Loss for UP Police Constable — Complete Guide with PYQs

beginner 18 min read

Concept

Profit and Loss is one of those topics where the concept is completely intuitive — you've lived it every time you've bought or sold anything. The challenge in the exam hall is not understanding, it is executing the right formula fast under pressure.

Here's the core idea. Every transaction has two prices: what you paid (Cost Price, CP or लागत मूल्य) and what you received (Selling Price, SP or विक्रय मूल्य). If SP > CP, you made a profit (लाभ). If SP < CP, you took a loss (हानि).

Think of it like this: you buy mangoes at ₹10 per dozen from the wholesale market and sell them at ₹15 per dozen in your shop. The ₹5 difference is your profit. Now if a customer haggles you down to ₹8 per dozen, you're selling at a loss of ₹2. Simple as that.

Where it gets exam-worthy is when the question introduces a third price — the Marked Price (MP or अंकित मूल्य), also called the listed price or printed price. This is the price written on the tag before any discount. The shopkeeper marks goods above CP to create room for a discount while still making a profit.

The chain looks like this: CP → (add markup) → MP → (subtract discount) → SP.

A question on UP Police Constable may ask you to find any one of these four quantities (CP, SP, MP, Profit/Loss%) given the others. Sometimes it throws in a false-weight twist, which is essentially a hidden extra profit the shopkeeper earns by cheating on the weighing scale.

The good news: every Profit and Loss question on this exam reduces to one of five standard types. Learn the formula for each type, practice two questions per type, and you're done. No special talent required — just clean arithmetic and the right formula.


Deep Dive

The Core Formulas

Profit and Loss (absolute values):

Profit=SPCP(when SP>CP)\text{Profit} = SP - CP \quad (\text{when } SP > CP)

Loss=CPSP(when CP>SP)\text{Loss} = CP - SP \quad (\text{when } CP > SP)

Percentage form — always on CP:

Profit%=SPCPCP×100\text{Profit\%} = \frac{SP - CP}{CP} \times 100

Loss%=CPSPCP×100\text{Loss\%} = \frac{CP - SP}{CP} \times 100

This "always on CP" rule is the single most important thing to burn into memory. Profit% and Loss% are calculated as a fraction of CP, not SP. Most wrong answers in exams come from dividing by SP instead of CP.

Finding SP when CP and percentage are given:

SP=CP×100+Profit%100(profit case)SP = CP \times \frac{100 + \text{Profit\%}}{100} \quad \text{(profit case)}

SP=CP×100Loss%100(loss case)SP = CP \times \frac{100 - \text{Loss\%}}{100} \quad \text{(loss case)}

Finding CP when SP and percentage are given:

CP=SP×100100+Profit%(profit case)CP = \frac{SP \times 100}{100 + \text{Profit\%}} \quad \text{(profit case)}

CP=SP×100100Loss%(loss case)CP = \frac{SP \times 100}{100 - \text{Loss\%}} \quad \text{(loss case)}

The Marked Price — Discount Chain

The discount is always calculated on MP, not on CP. This is another common trap.

Discount=MPSP\text{Discount} = MP - SP

Discount%=MPSPMP×100\text{Discount\%} = \frac{MP - SP}{MP} \times 100

SP=MP×100Discount%100SP = MP \times \frac{100 - \text{Discount\%}}{100}

The combined formula (when you know both markup above CP and discount on MP):

Let CP = 100. Then:

MP=CP×100+Markup%100MP = CP \times \frac{100 + \text{Markup\%}}{100}

SP=MP×100Discount%100SP = MP \times \frac{100 - \text{Discount\%}}{100}

Profit%=SPCPCP×100\text{Profit\%} = \frac{SP - CP}{CP} \times 100

Always take CP = 100 as your base. This single assumption eliminates half the algebra in marked-price questions.

False Weight Problems

When a dishonest seller claims to sell at CP but uses a short weight, the gain comes purely from the shortfall in weight.

Gain%=True weightFalse weightFalse weight×100\text{Gain\%} = \frac{\text{True weight} - \text{False weight}}{\text{False weight}} \times 100

Look at the denominator — it is the false weight (what the seller actually gives), not the true weight. This trips up many students who put 1000 in the denominator instead of 960.

Finding the New SP to Hit a Target Profit

This is a two-step process that appears frequently:

Step 1: Find CP from the given SP and current profit/loss%.

CP=Given SP×100100±Given %CP = \frac{\text{Given SP} \times 100}{100 \pm \text{Given \%}}

(use + for profit, − for loss in denominator)

Step 2: Find new SP using the target profit%:

New SP=CP×100+Target Profit%100\text{New SP} = CP \times \frac{100 + \text{Target Profit\%}}{100}

Finding Discount% When Target Profit is Given (MP-CP type)

Given: markup% above CP and a target profit%, find the discount%.

Take CP = 100. Calculate MP. Calculate required SP for the target profit. Then:

Discount%=MPSPMP×100\text{Discount\%} = \frac{MP - SP}{MP} \times 100

This is cleaner than any algebraic approach and takes about 20 seconds.


Memory Tricks & Shortcuts

patternThe Multiplier Method

Instead of computing profit/loss separately and then dividing, collapse it into one multiplication.

SP = CP × multiplier, where multiplier = (100 ± %)/100.

Example: CP = ₹40,000, profit = 15%. Standard method: find 15% of 40,000 = 6,000, add to get 46,000. Two steps, 30 seconds.

Shortcut: 40,000 × 1.15 = 46,000. One step, 8 seconds. Similarly, 2.5% loss on ₹18,560 → 18,560 × 0.975 = 18,096. Direct.

For finding CP from SP: flip the multiplier. SP at 15% loss = 1900, so CP = 1900 / 0.95 = 2000. No formula memorization needed beyond "multiply or divide by the decimal."

substitutionCP = 100 Base Assumption for Markup-Discount Questions

Any question involving markup% and discount% together — immediately set CP = 100. Don't use variables.

Example: marked 160% above CP, 25% discount. CP = 100, MP = 260, SP = 260 × 0.75 = 195. Profit% = 95%. Total time: 15 seconds.

Standard algebraic method (using CP = x, forming equations): 45-60 seconds, with risk of sign errors.

This substitution works because profit% is scale-independent — it doesn't matter whether CP is ₹100 or ₹10,000, the percentage comes out the same.

patternFalse Weight Formula — Denominator is the False Weight

False weight gain% = [(True − False) / False] × 100.

Micro-example: 960 gm sold as 1 kg. Gain% = (40/960) × 100 = 25/6 = 4¹⁄₆%.

The trap: students put 1000 in the denominator, getting 4%, which is a wrong answer that actually appears as a distractor in the options. The denominator is what the seller gives (960), because that's the seller's actual cost. Standard approach with full ratio setup: 40 seconds. Pattern-recall with this rule: 10 seconds.

eliminationTwo-Step CP Recovery for 'New SP' Questions

When told "sold at X% loss for ₹P, at what price to gain Y%?" — recover CP first, then find new SP.

CP = (P × 100) / (100 − loss%). New SP = CP × (100 + gain%) / 100.

Example: sold for ₹1,700 at 15% loss. CP = 1700 × 100 / 85 = 2,000. New SP for 20% gain = 2,000 × 1.20 = ₹2,400.

Students who skip the CP-recovery step try to directly ratio 1,700 to find the new price — that gives the wrong answer every time. Always recover CP first. This two-step structure reduces errors to near zero: 4 multiplications, no algebra.

substitutionDiscount% from MP-CP Problem (Target Profit Given)

Given: MP is X% above CP, required profit is Y%. Find discount%.

Set CP = 100. MP = (100 + X). Required SP = (100 + Y). Discount% = [(MP − SP) / MP] × 100.

Example: MP is 40% above CP, required profit = 12%. CP = 100, MP = 140, SP = 112. Discount% = 28/140 × 100 = 20%.

Standard method using simultaneous equations: 60+ seconds. This substitution method: under 20 seconds, zero equation setup required.


Fast-Solving Framework

Read the question and identify which of the five types it is:

Type 1 — Direct profit/loss (absolute): CP and SP both given. Subtract. Done in 5 seconds.

Type 2 — Find SP from CP and %: Use SP = CP × multiplier. One multiplication.

Type 3 — Find CP from SP and %: Use CP = SP / multiplier. One division.

Type 4 — Markup + Discount → Profit%: Set CP = 100 immediately. Three multiplications.

Type 5 — False weight: Gain% = (shortfall / false weight) × 100. Identify false weight as the denominator — not 1000.

Type 6 — New SP for target profit: Step 1: recover CP. Step 2: apply new%. Two multiplications.

Decision rule for discount questions: Is the discount given on MP or on CP? It is always on MP. Is profit/loss% always on CP? Yes, always. If you're unsure which price to divide by, ask yourself "whose money are we measuring gain on?" — the buyer's cost is CP, so divide by CP.

If the arithmetic looks messy (e.g., 18,560 × 0.975), break it: 18,560 × 1 = 18,560, minus 18,560 × 0.025. 18,560 × 0.025 = 464. 18,560 − 464 = 18,096. Clean.


Solved PYQs

Why this question: Tests the absolute basics — total CP vs total SP across multiple units. If you can't do this in under 10 seconds, fix your foundation first.

Previous Year Questionपिछले वर्ष का प्रश्न2026
A shopkeeper bought 150 pencils at ₹10 each and sold them at ₹5 each. Calculate the total profit or loss.
एक दुकानदार ने ₹10 प्रति पेंसिल की दर से 150 पेंसिल खरीदीं और उन्हें ₹5 प्रति पेंसिल की दर से बेच दिया। कुल लाभ या हानि की गणना कीजिए।
  1. ₹670 loss
  2. ₹750 loss
  3. ₹450 profit
  4. ₹560 profit
  1. ₹670 हानि
  2. ₹560 लाभ
  3. ₹450 लाभ
  4. ₹750 हानि
Solutionसमाधान
Cost price = 150 × 10 = ₹1,500. Selling price = 150 × 5 = ₹750. Loss = 1500 − 750 = ₹750 loss.

Solving path: Total CP = 150 × 10 = ₹1,500. Total SP = 150 × 5 = ₹750. Since SP < CP, it's a loss. Loss = 1,500 − 750 = ₹750. No formula needed — pure arithmetic.


Why this question: Tests the multiplier method for loss%. The number 18,560 is deliberately uncomfortable — the question is checking whether you use the clean multiplier or get stuck in long division.

Previous Year Questionपिछले वर्ष का प्रश्न2026
एक वस्तु को ₹ 18,560 में खरीदा जाता है और 2.5% की हानि पर बेचा जाता है। विक्रय मूल्य क्या है?
एक वस्तु को ₹ 18,560 में खरीदा जाता है और 2.5% की हानि पर बेचा जाता है। विक्रय मूल्य क्या है?
  1. ₹ 18,650
  2. ₹ 15,900
  3. ₹ 18,096
  4. ₹ 15,675
  1. ₹ 18,096
  2. ₹ 18,650
  3. ₹ 15,900
  4. ₹ 15,675
Solutionसमाधान
SP = CP × (1 - loss%) = 18560 × 0.975 = 18096.

Solving path: SP = CP × (1 − 0.025) = 18,560 × 0.975. Break it: 18,560 − (18,560 × 0.025) = 18,560 − 464 = ₹18,096. Match to option C.


Why this question: Classic markup-discount-profit% chain. The most common three-variable question type on this exam. Tests whether you know to set CP = 100.

Previous Year Questionपिछले वर्ष का प्रश्न2026
A shopkeeper marks his goods at 160% above the cost price and offers a discount of 25% on the marked price. What is his profit percentage?
एक दुकानदार अपनी वस्तुओं पर क्रय मूल्य से 160% अधिक मूल्य अंकित करता है और अंकित मूल्य पर 25% की छूट प्रदान करता है। उसका लाभ प्रतिशत क्या है?
  1. 77%
  2. 88%
  3. 95%
  4. 80%
  1. 88%
  2. 80%
  3. 77%
  4. 95%
Solutionसमाधान
Let CP = 100. MP = 260. SP = 260 × 0.75 = 195. Profit% = (195-100)/100 × 100 = 95%.

Solving path: CP = 100. MP = 100 + 160 = 260. Discount = 25%, so SP = 260 × 0.75 = 195. Profit% = (195 − 100)/100 × 100 = 95%. Answer: option C.


Why this question: Straightforward profit% to SP. Tests the multiplier formula. Should take under 10 seconds if the method is internalized.

Previous Year Questionपिछले वर्ष का प्रश्न2026
A person bought a laptop for Rs. 40,000 and sold it at a profit of 15%. What is the selling price of the laptop?
एक व्यक्ति ने 40,000 रुपये में एक लैपटॉप खरीदा और इसे 15% के लाभ पर बेच दिया। लैपटॉप का विक्रय मूल्य क्या है?
  1. Rs. 45,000
  2. Rs. 47,000
  3. Rs. 48,000
  4. Rs. 46,000
  1. 46,000 रुपये
  2. 47,000 रुपये
  3. 48,000 रुपये
  4. 45,000 रुपये
Solutionसमाधान
SP = CP × (1 + profit%) = 40000 × 1.15 = 46,000.

Solving path: SP = 40,000 × 1.15 = 46,000. That's 40,000 + 6,000 = ₹46,000. Answer: option D.


Why this question: The false-weight trap question. Four wrong-looking answer choices, and the specific distractor of 4% (using 1000 as denominator) is very likely to catch you if you haven't practiced this type.

Previous Year Questionपिछले वर्ष का प्रश्न2024
A dishonest shopkeeper professes to sell goods at his cost price but uses a false weight of 960 gm for each kilogram. What is his gain percent?
एक बेईमान दुकानदार अपने मूल्य पर सामान बेचने का दावा करता है लेकिन प्रत्येक किलोग्राम के लिए 960 ग्राम (गलत) उपाय) उपयोग करता है। तो उसका लाभ प्रतिशत कितना है?
  1. 5³⁄₁₇%
  2. 4¹⁄₆%
  3. 6²⁄₃%
  4. 9¹⁄₄%
  1. 6²⁄₃%
  2. 4¹⁄₆%
  3. 5³⁄₁₇%
  4. 9¹⁄₄%
Solutionसमाधान
Gain% = [(1000-960)/960] × 100 = [40/960] × 100 = 4000/960 = 25/6 = 4¹/₆%. The gain percent is 4¹/₆% (option B, index 1).

Solving path: True weight = 1000 gm, false weight = 960 gm. Shortfall = 40 gm. Gain% = (40/960) × 100 = 4000/960 = 25/6 = 4¹⁄₆%. Key: denominator is 960 (false weight), not 1000. Answer: option B (4¹⁄₆%).


Why this question: Two-step CP recovery question. Tests whether you can work backwards from SP to CP and then forward to a new SP.

Previous Year Questionपिछले वर्ष का प्रश्न2024
By selling a tape-recorder for Rs. 1900, I lost 5%. What percent shall I gain by selling it for Rs. 2080?
एक टेप-रिकॉर्डर को 1900 रुपये में बेचने से मुझे 5% की हानि हुई। इसे 2080 रुपये में बेचने पर मुझे कितने प्रतिशत का लाभ होगा?
  1. 19%
  2. 4.5%
  3. 8.5%
  4. 4%
  1. 19%
  2. 8.5%
  3. 4%
  4. 4.5%
Solutionसमाधान
CP = 1900×100/95 = 2000. Profit on selling at 2080 = 80. Profit% = 80/2000×100 = 4%.

Solving path: Sold at ₹1,900 with 5% loss. CP = 1900 × 100/95 = ₹2,000. New SP = ₹2,080. Profit = 2,080 − 2,000 = ₹80. Profit% = (80/2,000) × 100 = 4%. Answer: option D.


Why this question: Tests finding discount% when both markup and target profit are given. The CP = 100 substitution makes this trivial.

Previous Year Questionपिछले वर्ष का प्रश्न2024
The printed price of an article is 40% higher than its cost price. Then, what is the rate of discount so that the gain is 12% profit?
एक वस्तु का मुद्रित मूल्य उसके क्रय मूल्य से 40% अधिक है। तो छूट की दर कितनी होनी चाहिए ताकि 12% लाभ प्राप्त हो सके?
  1. 15%
  2. 18%
  3. 21%
  4. 20%
  1. 15%
  2. 18%
  3. 20%
  4. 21%
Solutionसमाधान
Let CP=100, MP=140. For 12% profit, SP=112. Discount = (140-112)/140 × 100 = 28/140 × 100 = 20%.

Solving path: CP = 100, MP = 140 (40% above CP). For 12% profit, SP = 112. Discount = 140 − 112 = 28. Discount% = 28/140 × 100 = 20%. Answer: option D.


Why this question: Two-step question with 15% loss going to 20% profit. Tests clean CP recovery and forward calculation.

Previous Year Questionपिछले वर्ष का प्रश्न2024
On selling an article for ₹1,700, a shopkeeper loses 15%. To gain 20%, at what price must he sell that article?
एक वस्तु को ₹1,700 में बेचने पर, एक दुकानदार को 15% की हानि होती है। 20% लाभ प्राप्त करने के लिए, उसे उस वस्तु को कितने रुपये में बेचना होगा?
  1. ₹2,100
  2. ₹2,120
  3. ₹2,400
  4. ₹2,155
  1. ₹2,120
  2. ₹2,100
  3. ₹2,155
  4. ₹2,400
Solutionसमाधान
SP=1700 at 15% loss → CP = 1700/0.85 = 2000. For 20% gain, SP = 2000×1.20 = ₹2,400.

Solving path: SP = ₹1,700 at 15% loss. CP = 1700/0.85 = 1700 × 100/85 = ₹2,000. For 20% gain, new SP = 2,000 × 1.20 = ₹2,400. Answer: option C.


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