Data Interpretation — Tables, Bar Charts and Pie Charts for UPSC CSAT

intermediate 22 min read

Concept

Data Interpretation (DI) is the backbone of UPSC CSAT Paper II. The format is consistent: a set of raw data presented in one or more formats — a table, a bar chart, a pie chart, or combinations — followed by 4–5 questions that require you to extract, compare, calculate, and conclude.

Think of DI as a treasurer presenting quarterly accounts to a committee. The treasurer (the question setter) has already done the hard work of organising numbers. Your job as the committee member (the exam-taker) is not to create new numbers but to read what is already there — and sometimes combine two pieces of information to derive a third.

Here is the key analogy that separates average from high scorers: DI is a reading comprehension test, not a computation test. Most candidates waste 60–70% of their time computing when the answer is already visible via ratios, estimation, or elimination. The numbers are usually chosen so that one or two options are obviously wrong — use that.

The three formats tested in UPSC CSAT:

One conceptual thread runs through all three formats: relative change matters more than absolute value. A department growing from 35 to 42 (absolute: +7) may outperform one growing from 120 to 145 (absolute: +25) when you look at the rate of growth. UPSC questions are specifically designed to trap candidates who anchor on absolute numbers.


Deep Dive

Reading Tables Without Getting Lost

A table presents data in rows and columns. Before touching any calculation, spend 20–25 seconds doing this:

  1. Read the title and units (hundreds, lakhs, percentages — mix-ups here cost marks).
  2. Identify whether numbers are absolute or relative (percentage, ratio, index).
  3. Note the time axis (years, quarters, months) — this tells you what "growth" means.
  4. Skim for the largest and smallest values in each row and column — this primes your mental model.

Questions on tables typically ask for: total across a row or column, ratio between two cells, percentage change over time, or average annual growth rate (AAGR).

AAGR — the one formula you cannot approximate away:

AAGR=[(Final ValueInitial Value)1/n1]×100\text{AAGR} = \left[\left(\frac{\text{Final Value}}{\text{Initial Value}}\right)^{1/n} - 1\right] \times 100

where n is the number of years of growth (not the number of data points). If you have data for 2022 and 2024, that is n = 2. The trap: many candidates set n = 3 (counting 2022, 2023, 2024 as three years). Count the gaps, not the years.

You do not need to compute the exact square root in the exam. The relative ranking of AAGR values across options is enough. For two departments, the one with the higher ratio (Final/Initial) will have the higher AAGR when n is the same. Compute precisely only when two departments are close.

Bar Charts — Absolute and Stacked

A simple bar chart lets you read magnitudes directly off the y-axis. Common questions: which month had the highest value, what is the percentage change from period A to period B, what is the average over n periods.

Percentage change formula — say it once, use it always:

% change=NewOldOld×100\% \text{ change} = \frac{\text{New} - \text{Old}}{\text{Old}} \times 100

"New minus Old over Old." Not over New. This is the single most common arithmetic error in DI.

Stacked bar charts add complexity: each bar is divided into segments representing sub-categories. Read these carefully:

When a question gives you a stacked percentage composition and a total, convert: Actual value = Total × (Segment %) / 100. In June with a total of 150 lakh and Education at 27%, Education = 150 × 0.27 = 40.5 lakh. Direct multiplication — no multi-step detour needed.

Pie Charts — Angles are Everything

The relationship is linear: (Angle / 360°) = (Value / Total). From this single equation, you derive everything:

Here is the fastest path when a pie chart question gives you one segment's actual count and asks for another:

Target Value=Known Value×Target AngleKnown Angle\text{Target Value} = \text{Known Value} \times \frac{\text{Target Angle}}{\text{Known Angle}}

No need to find the total at all. If Production (72°) = 2400, then Quality (54°) = 2400 × (54/72) = 2400 × 0.75 = 1800. This skips one multiplication and one division compared to the long route.

Combining Data Across Formats

Some UPSC sets give you a table alongside a pie chart, or a bar chart alongside a paragraph of text. The question requires combining both sources. The discipline here is: extract one number from source 1, extract one number from source 2, then perform one operation. Do not try to hold both datasets in working memory simultaneously. Write down the intermediate value before proceeding.

Percentile and Distribution Questions

Occasionally, DI questions embed a statistical concept like the 75th percentile. Above the 75th percentile means the top 25% — this is definitional. In a uniform distribution, 25% of the population = 1/4. The trap in these questions is to conflate the actual success rate from the table (e.g., 15%) with the percentile-based cutoff (25%). They are independent pieces of information.


Memory Tricks & Shortcuts

patternAngle Ratio Shortcut for Pie Charts

When one segment's value is given, find any other segment's value by multiplying by the ratio of their angles. Skip the step of computing the total. Example: Production (72°) = 2400 workers; Quality (54°) = ? Calculation: 2400 × 54/72 = 2400 × 3/4 = 1800. Standard method requires finding Total first (= 2400 × 360/72 = 12,000), then multiplying by 54/360 — that is 4 arithmetic operations. Direct ratio method: 2 operations. Time saved: roughly 20–25 seconds per pie-chart question.

estimationAAGR Ranking Without Full Computation

To rank departments by AAGR without computing every square root, compare (Final/Initial) ratios directly — higher ratio means higher AAGR when n is identical for all. Compute the exact root only for the top 2 candidates to confirm. In the 5-department table example: Sales ratio = 110/80 = 1.375, IT ratio = 145/120 = 1.208, Finance ratio = 42/35 = 1.2, Ops ratio = 71/60 = 1.183, HR ratio = 52/45 = 1.156. Sales is the clear winner without touching a single square root. Standard method (computing all 5 square roots): ~90 seconds. Ratio-ranking method: ~20 seconds.

patternPercentage Increase — Anchor on the Denominator

The most common error is dividing by the new value instead of the old (base) value. Lock this in: % change = (Difference / Base) × 100. "Base" = earlier period, original value, or whatever came first. For Jan-to-June traffic: difference = 420 − 250 = 170; base = 250 (January). Result = 170/250 × 100 = 68%. If you accidentally used 420 as base: 170/420 × 100 ≈ 40.5% — none of the given options. Wrong base = instant wrong answer. This single anchor removes one option from your error set entirely.

substitutionStacked Bar — Non-Admin Pool Shortcut

When a stacked bar has one growing segment (e.g., Admin increasing linearly) and asks about another segment's actual value, find the non-Admin pool percentage first, then apply the sub-segment's share. Education in June: Admin = 10%, so non-Admin = 90%. Education = 30% of 90% = 27% of total. Actual = 150 × 0.27 = 40.5 lakh. This collapses a 4-step chain (find Admin, subtract, find Education share, multiply) into 2 mental steps: "90% pool, 30% of that = 27%, times total." Saves 2 arithmetic steps per question of this type.

patternAverage Monthly Growth — Total Change Divided by Intervals

Average monthly growth = (Final value − Initial value) / (number of intervals). For North district: Jan = 210, Jun = 360. Change = 150 over 5 intervals (Jan→Feb, Feb→Mar, Mar→Apr, Apr→May, May→Jun). Average = 150/5 = 30. The trap: dividing by 6 (number of months listed). Count intervals, not data points — same logic as the AAGR trap. Standard fumble (dividing by 6): gives 25, which is option D — a planted distractor. Correct method (dividing by 5): gives 30.


Fast-Solving Framework

When you hit a DI set in the exam hall, follow this sequence without deviation:

Step 1 — Format scan (15 seconds). Is it a table, bar, pie, or combination? Note the units. Note whether values are absolute or percentage.

Step 2 — Question triage (30 seconds). Read all questions in the set before solving any. Flag the ones that need only reading (direct lookup), flagging those that need computation. Solve reading questions first.

Step 3 — For percentage change questions: always write down (New − Old) and Old before dividing. Never compute in your head for both.

Step 4 — For AAGR questions: compute (Final/Initial) ratios for all candidates, rank them, compute the square root only for the top 1–2.

Step 5 — For pie chart questions: use the angle-ratio shortcut. Only compute the total if more than two questions in the set require it.

Step 6 — Eliminate first. Before computing, ask: "Is any option obviously too high or too low?" DI setters place deliberate distractors at ±1 step-error distances from the correct answer. If your rough estimate points to a range, eliminate outside it and confirm within.

Step 7 — Cross-check units. If your answer is in crores but the options are in lakhs, you will lose a mark you deserved. Unit check takes 5 seconds and is non-negotiable.


Solved PYQs

Why this question: This tests AAGR ranking across multiple departments — the most common table-based question type in UPSC CSAT. The trap is computing all five square roots.

Previous Year Questionपिछले वर्ष का प्रश्न
A table shows the number of employees (in hundreds) across five departments and three years: 2022 2023 2024 IT: 120 132 145 HR: 45 48 52 Sales: 80 92 110 Ops: 60 66 71 Finance: 35 38 42 Which department had the highest average annual growth rate (AAGR) from 2022 to 2024?
एक तालिका पाँच विभागों और तीन वर्षों में कर्मचारियों की संख्या (सैकड़ों में) दिखाती है: 2022 2023 2024 IT: 120 132 145 HR: 45 48 52 बिक्रय: 80 92 110 Ops: 60 66 71 Finance: 35 38 42 2022 से 2024 तक किस विभाग की वार्षिक औसत वृद्धि दर (AAGR) सबसे अधिक थी?
  1. Finance
  2. Ops
  3. IT
  4. Sales
  1. Finance
  2. Ops
  3. IT
  4. बिक्रय
Solutionसमाधान
AAGR formula: [(Ending Value / Beginning Value) ^ (1/n) − 1] × 100, where n = number of years = 2. IT: [(145/120)^0.5 − 1] × 100 = [(1.2083)^0.5 − 1] × 100 = (1.0990 − 1) × 100 = 9.90%. HR: [(52/45)^0.5 − 1] × 100 = [(1.1556)^0.5 − 1] × 100 = (1.0751 − 1) × 100 = 7.51%. Sales: [(110/80)^0.5 − 1] × 100 = [(1.375)^0.5 − 1] × 100 = (1.1726 − 1) × 100 = 17.26%. Ops: [(71/60)^0.5 − 1] × 100 = [(1.1833)^0.5 − 1] × 100 = (1.0879 − 1) × 100 = 8.79%. Finance: [(42/35)^0.5 − 1] × 100 = [(1.2)^0.5 − 1] × 100 = (1.0954 − 1) × 100 = 9.54%. Sales has the highest AAGR of 17.26%.
AAGR सूत्र: [(अंतिम मान / शुरुआती मान) ^ (1/n) − 1] × 100, जहाँ n = 2 वर्ष। IT: [(145/120)^0.5 − 1] × 100 = 9.90%। HR: [(52/45)^0.5 − 1] × 100 = 7.51%। बिक्रय: [(110/80)^0.5 − 1] × 100 = 17.26%। Ops: [(71/60)^0.5 − 1] × 100 = 8.79%। Finance: [(42/35)^0.5 − 1] × 100 = 9.54%। बिक्रय विभाग की AAGR 17.26% सबसे अधिक है।

Solving path: Compute (Final/Initial) for each department: Sales = 110/80 = 1.375, IT = 145/120 = 1.208, Finance = 42/35 = 1.2, Ops = 71/60 = 1.183, HR = 52/45 = 1.156. Sales has the highest ratio by a wide margin — no square root needed to confirm the winner. If pressed, √1.375 ≈ 1.173, giving AAGR ≈ 17.26%, which matches the explanation.


Why this question: Classic pie chart value-from-angle problem. Tests whether you use the shortcut or the long route.

Previous Year Questionपिछले वर्ष का प्रश्न
A pie chart shows the distribution of workforce (in thousands) across five departments of a factory: Engineering: 36°, Production: 72°, Quality: 54°, HR: 45°, Admin: 153° If the Production department has 2400 workers, how many workers are in the Quality department?
एक पाई चार्ट एक कारखाने के पाँच विभागों में कार्यबल (हज़ारों में) का वितरण दिखाता है: इंजीनियरिंग: 36°, उत्पादन: 72°, गुणवत्ता: 54°, HR: 45°, प्रशासन: 153° यदि उत्पादन विभाग में 2400 कर्मचारी हैं, तो गुणवत्ता विभाग में कितने कर्मचारी हैं?
  1. 2000
  2. 1800
  3. 2200
  4. 1600
  1. 2000
  2. 1800
  3. 2200
  4. 1600
Solutionसमाधान
In a pie chart, 360° represents the total. Production angle is 72° with 2400 workers. So, 72° = 2400 workers, which means 1° = 2400/72 = 33.33 workers. Quality angle is 54°, so Quality workers = 54 × 33.33 = 1800 workers.
पाई चार्ट में, 360° कुल का प्रतिनिधित्व करता है। उत्पादन कोण 72° है जिसमें 2400 कर्मचारी हैं। तो, 72° = 2400 कर्मचारी, जिसका मतलब है 1° = 2400/72 = 33.33 कर्मचारी। गुणवत्ता कोण 54° है, तो गुणवत्ता कर्मचारी = 54 × 33.33 = 1800 कर्मचारी।

Solving path: Use angle ratio directly: Quality/Production = 54°/72° = 3/4. Quality workers = 2400 × (3/4) = 1800. No need to find the total workforce. Verify: total = 2400 × (360/72) = 12,000; Quality = 12,000 × (54/360) = 1800. Same answer, more steps.


Why this question: Tests whether you can isolate the relevant row and column from a 2-company table and apply profit margin correctly. The combined revenue figure is a deliberate distractor.

Previous Year Questionपिछले वर्ष का प्रश्न
The table below shows quarterly profit margins (%) for Company X and Company Y: | Quarter | Company X | Company Y | |---------|-----------|----------| | Q1 | 12 | 15 | | Q2 | 14 | 13 | | Q3 | 16 | 14 | | Q4 | 18 | 17 | If both companies had a combined revenue of ₹500 crores in Q3, and Company X's revenue was ₹200 crores, what was Company X's profit in Q3?
नीचे दी गई तालिका कंपनी X और कंपनी Y के लिए त्रैमासिक लाभ मार्जिन (%) दर्शाती है: | त्रैमासिक | कंपनी X | कंपनी Y | |---------|---------|----------| | Q1 | 12 | 15 | | Q2 | 14 | 13 | | Q3 | 16 | 14 | | Q4 | 18 | 17 | यदि दोनों कंपनियों का Q3 में संयुक्त राजस्व ₹500 करोड़ था, और कंपनी X का राजस्व ₹200 करोड़ था, तो Q3 में कंपनी X का लाभ क्या था?
  1. ₹30 crores
  2. ₹36 crores
  3. ₹28 crores
  4. ₹32 crores
  1. ₹30 करोड़
  2. ₹36 करोड़
  3. ₹28 करोड़
  4. ₹32 करोड़
Solutionसमाधान
Company X's revenue in Q3 was ₹200 crores. From the table, Company X's profit margin in Q3 is 16%. Profit = Revenue × Profit Margin = 200 × 0.16 = ₹32 crores.
Q3 में कंपनी X का राजस्व ₹200 करोड़ था। तालिका से, Q3 में कंपनी X का लाभ मार्जिन 16% है। लाभ = राजस्व × लाभ मार्जिन = 200 × 0.16 = ₹32 करोड़।

Solving path: Company X's Q3 revenue = ₹200 crores (given in question text, not derived from combined). Q3 margin for X = 16% (from table, Q3 row, Company X column). Profit = 200 × 0.16 = ₹32 crores. The combined revenue of ₹500 crores and Company Y's data are irrelevant — planted to slow you down.


Why this question: Embeds a statistical concept (percentile) inside a DI table. Tests conceptual clarity, not computation.

Previous Year Questionपिछले वर्ष का प्रश्न
A table shows the number of candidates who appeared and qualified in 5 competitive exams: Exam | Appeared | Qualified X | 8000 | 1200 Y | 12000 | 2400 Z | 10000 | 1500 W | 15000 | 3000 V | 5000 | 750 If the success rate (qualified/appeared) of exam Y is 20%, and a candidate needs to score above the 75th percentile of exam V to qualify for a merit list, what fraction of exam V candidates will likely be on the merit list, assuming uniform distribution?
एक तालिका 5 प्रतिस्पर्धी परीक्षाओं में उपस्थित और उत्तीर्ण उम्मीदवारों की संख्या दिखाती है: परीक्षा | उपस्थित | उत्तीर्ण X | 8000 | 1200 Y | 12000 | 2400 Z | 10000 | 1500 W | 15000 | 3000 V | 5000 | 750 अगर परीक्षा Y की सफलता दर (उत्तीर्ण/उपस्थित) 20% है, और एक उम्मीदवार को योग्यता सूची के लिए परीक्षा V के 75वें प्रतिशत से ऊपर अंक प्राप्त करने की आवश्यकता है, तो परीक्षा V के कितने हिस्से के उम्मीदवार योग्यता सूची में होंगे, यदि समान वितरण मानें?
  1. 1/4
  2. 1/5
  3. 3/10
  4. 1/3
  1. 1/4
  2. 1/5
  3. 3/10
  4. 1/3
Solutionसमाधान
The 75th percentile means the top 25% of candidates. In a uniform distribution, those scoring above the 75th percentile = 100% − 75% = 25% = 1/4 of the distribution. Exam V success rate is 750/5000 = 15%, but the percentile-based merit list selection is independent and uses the 75th percentile cutoff. Thus, 1/4 of V's candidates will be above the 75th percentile.
75वें प्रतिशत का अर्थ है शीर्ष 25% उम्मीदवार। एक समान वितरण में, 75वें प्रतिशत से ऊपर अंक प्राप्त करने वाले = 100% − 75% = 25% = 1/4 वितरण। परीक्षा V की सफलता दर 750/5000 = 15% है, लेकिन प्रतिशत-आधारित योग्यता सूची चयन स्वतंत्र है और 75वें प्रतिशत कटऑफ का उपयोग करता है। इस प्रकार, V के 1/4 उम्मीदवार 75वें प्रतिशत से ऊपर होंगे।

Solving path: "Above the 75th percentile" = top 25% = 1/4 of the distribution. The actual success rate of Exam V (750/5000 = 15%) is irrelevant to this question — it is there to distract. Uniform distribution assumption makes this straightforward: 100% − 75% = 25% = 1/4.


Why this question: Tests a derived index (Educated Population Index) and asks for the difference between two cities. Common in UPSC sets that combine census-style data.

Previous Year Questionपिछले वर्ष का प्रश्न
Two cities' population data (in lakhs) and literacy rates (%) are given for 2020 and 2024: City A: 2020 (Pop = 80, Literacy = 65%), 2024 (Pop = 96, Literacy = 72%) City B: 2020 (Pop = 60, Literacy = 55%), 2024 (Pop = 75, Literacy = 68%) If we define 'Educated Population Index' as (Total Literate Population) / (Total Population) × 100, what is the difference in this index between City A and City B in 2024?
दो शहरों के जनसंख्या डेटा (लाख में) और साक्षरता दरें (%) 2020 और 2024 के लिए दी गई हैं: शहर A: 2020 (जन = 80, साक्षरता = 65%), 2024 (जन = 96, साक्षरता = 72%) शहर B: 2020 (जन = 60, साक्षरता = 55%), 2024 (जन = 75, साक्षरता = 68%) यदि हम 'शिक्षित जनसंख्या सूचकांक' को (कुल साक्षर जनसंख्या) / (कुल जनसंख्या) × 100 के रूप में परिभाषित करते हैं, तो 2024 में शहर A और शहर B के बीच इस सूचकांक में अंतर क्या है?
  1. 2.8 percentage points
  2. 3.2 percentage points
  3. 4 percentage points
  4. 5.6 percentage points
  1. 2.8 प्रतिशत बिंदु
  2. 3.2 प्रतिशत बिंदु
  3. 4 प्रतिशत बिंदु
  4. 5.6 प्रतिशत बिंदु
Solutionसमाधान
City A 2024: Literate population = 96 × 0.72 = 69.12 lakhs. Index for A = (69.12 / 96) × 100 = 72%. City B 2024: Literate population = 75 × 0.68 = 51 lakhs. Index for B = (51 / 75) × 100 = 68%. Difference = 72% − 68% = 4 percentage points.
शहर A 2024: साक्षर जनसंख्या = 96 × 0.72 = 69.12 लाख। A का सूचकांक = (69.12 / 96) × 100 = 72%। शहर B 2024: साक्षर जनसंख्या = 75 × 0.68 = 51 लाख। B का सूचकांक = (51 / 75) × 100 = 68%। अंतर = 72% − 68% = 4 प्रतिशत बिंदु।

Solving path: The Educated Population Index = (Literate/Total) × 100 = literacy rate. City A 2024 literacy = 72%. City B 2024 literacy = 68%. Difference = 4 percentage points. Look — the index simplifies to the literacy rate itself because literate population = total × literacy rate, and dividing back by total cancels out. Many candidates compute 69.12 and 51 unnecessarily. Recognise the identity and save 45 seconds.


Why this question: Direct percentage change on bar chart data. Tests anchor discipline (dividing by base, not new value).

Previous Year Questionपिछले वर्ष का प्रश्न
A bar chart displays monthly website traffic (in thousands of visitors) for an e-commerce platform: Jan: 250, Feb: 275, Mar: 320, Apr: 300, May: 380, Jun: 420 What is the percentage increase in traffic from January to June?
एक बार चार्ट एक ई-कॉमर्स प्लेटफॉर्म के लिए मासिक वेबसाइट ट्रैफिक (हज़ारों आगंतुकों में) प्रदर्शित करता है: जनवरी: 250, फरवरी: 275, मार्च: 320, अप्रैल: 300, मई: 380, जून: 420 जनवरी से जून तक ट्रैफिक में कितने प्रतिशत की वृद्धि हुई है?
  1. 72%
  2. 68%
  3. 70%
  4. 65%
  1. 72%
  2. 68%
  3. 70%
  4. 65%
Solutionसमाधान
January traffic: 250 thousand. June traffic: 420 thousand. Increase = 420 − 250 = 170 thousand. Percentage increase = (170/250) × 100 = 68%.
जनवरी का ट्रैफिक: 250 हज़ार। जून का ट्रैफिक: 420 हज़ार। वृद्धि = 420 − 250 = 170 हज़ार। प्रतिशत वृद्धि = (170/250) × 100 = 68%।

Solving path: Increase = 420 − 250 = 170. Base = 250 (January, the earlier value). % increase = (170/250) × 100 = 68%. Option A (72%) corresponds to using 236 as the base — a number close enough to trap hasty computation. Option C (70%) corresponds to rounding 170/250 imprecisely.


Why this question: Stacked bar with a linearly changing Admin proportion — tests the non-Admin pool shortcut.

Previous Year Questionपिछले वर्ष का प्रश्न
A stacked bar chart shows monthly expenses (in ₹ lakh) for an NGO across four categories (Food, Medical, Education, Admin) for 6 months. The totals are: Jan = 120, Feb = 135, Mar = 128, Apr = 142, May = 138, Jun = 150. The proportion breakdown (stacked percentages) remains constant except for Admin, which increases linearly: Jan = 5%, Feb = 6%, Mar = 7%, Apr = 8%, May = 9%, Jun = 10%. If Food, Medical, and Education together made up 95% in January, what was the actual expense on Education in June (in ₹ lakh) if Education's share of the non-Admin pool remained constant at 30%?
एक स्टैक्ड बार चार्ट 6 महीनों के लिए एक एनजीओ के मासिक खर्च (₹ लाख में) चार श्रेणियों (खाद्य, चिकित्सा, शिक्षा, प्रशासन) में दिखाता है। कुल हैं: जन = 120, फरवरी = 135, मार्च = 128, अप्रैल = 142, मई = 138, जून = 150। अनुपात विभाजन (स्टैक्ड प्रतिशत) प्रशासन को छोड़कर स्थिर रहता है, जो रैखिक रूप से बढ़ता है: जन = 5%, फरवरी = 6%, मार्च = 7%, अप्रैल = 8%, मई = 9%, जून = 10%। यदि जनवरी में खाद्य, चिकित्सा और शिक्षा एक साथ 95% थे, तो जून में शिक्षा पर वास्तविक खर्च क्या था (₹ लाख में) यदि गैर-प्रशासन पूल में शिक्षा की हिस्सेदारी 30% स्थिर रही?
  1. 40.5 lakh
  2. 38.7 lakh
  3. 44.1 lakh
  4. 42.3 lakh
  1. 40.5 लाख
  2. 38.7 लाख
  3. 44.1 लाख
  4. 42.3 लाख
Solutionसमाधान
In January, Admin = 5%, so Food + Medical + Education = 95%. Education's share of the non-Admin pool = 30%, meaning Education = 30% of 95% = 28.5% of total. In June, Admin = 10%, so non-Admin = 90%. Education = 30% of 90% = 27% of total. June total = 150 lakh. Education in June = 150 × 0.27 = 40.5 lakh.
जनवरी में, प्रशासन = 5%, इसलिए खाद्य + चिकित्सा + शिक्षा = 95%। गैर-प्रशासन पूल में शिक्षा की हिस्सेदारी = 30%, मतलब शिक्षा = 95% का 30% = कुल का 28.5%। जून में, प्रशासन = 10%, इसलिए गैर-प्रशासन = 90%। शिक्षा = 90% का 30% = कुल का 27%। जून का कुल = 150 लाख। जून में शिक्षा = 150 × 0.27 = 40.5 लाख।

Solving path: June Admin = 10%, so non-Admin pool = 90%. Education = 30% of non-Admin pool = 30% of 90% = 27% of total June expenses. Actual Education = 150 × 0.27 = 40.5 lakh. The distractor at 44.1 (option C) comes from incorrectly using 30% of the total instead of 30% of the non-Admin pool.


Why this question: Tests average monthly growth with the "intervals vs. data points" trap embedded.

Previous Year Questionपिछले वर्ष का प्रश्न
A stacked bar chart shows monthly water consumption (in million litres) across three districts (North, Central, South) for 6 months. The totals and composition are: Month | Total | North% | Central% | South% January | 600 | 35 | 40 | 25 February| 660 | 36 | 38 | 26 March | 720 | 37 | 36 | 27 April | 780 | 38 | 34 | 28 May | 840 | 39 | 32 | 29 June | 900 | 40 | 30 | 30 Based on the pattern, what is the average monthly growth in the North district's consumption from January to June?
एक स्टैक्ड बार चार्ट 6 महीनों में तीन जिलों (उत्तर, केंद्रीय, दक्षिण) में मासिक जल खपत (मिलियन लीटर में) दर्शाता है। कुल और संरचना हैं: माह | कुल | उत्तर% | केंद्रीय% | दक्षिण% जनवरी | 600 | 35 | 40 | 25 फरवरी | 660 | 36 | 38 | 26 मार्च | 720 | 37 | 36 | 27 अप्रैल | 780 | 38 | 34 | 28 मई | 840 | 39 | 32 | 29 जून | 900 | 40 | 30 | 30 पैटर्न के आधार पर, जनवरी से जून तक उत्तर जिले की खपत में औसत मासिक वृद्धि क्या है?
  1. 35 million litres per month
  2. 30 million litres per month
  3. 28 million litres per month
  4. 25 million litres per month
  1. 35 मिलियन लीटर प्रति माह
  2. 30 मिलियन लीटर प्रति माह
  3. 28 मिलियन लीटर प्रति माह
  4. 25 मिलियन लीटर प्रति माह
Solutionसमाधान
North district consumption: Jan = 35% of 600 = 210, Feb = 36% of 660 = 237.6, Mar = 37% of 720 = 266.4, Apr = 38% of 780 = 296.4, May = 39% of 840 = 327.6, Jun = 40% of 900 = 360. Total increase = 360 − 210 = 150 million litres over 5 months (Jan to Jun). Average monthly growth = 150 / 5 = 30 million litres per month.
उत्तर जिले की खपत: जनवरी = 600 का 35% = 210, फरवरी = 660 का 36% = 237.6, मार्च = 720 का 37% = 266.4, अप्रैल = 780 का 38% = 296.4, मई = 840 का 39% = 327.6, जून = 900 का 40% = 360। कुल वृद्धि = 360 − 210 = 150 मिलियन लीटर 5 महीने में (जनवरी से जून)। औसत मासिक वृद्धि = 150 / 5 = 30 मिलियन लीटर प्रति माह।

Solving path: Compute North values: Jan = 35% × 600 = 210, Jun = 40% × 900 = 360. Change = 150 over 5 intervals. Average = 150/5 = 30 million litres/month. Option D (25) is exactly what you get by dividing by 6 (months listed) rather than 5 (intervals between months) — the most predictable trap in growth-rate questions.


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