Why this topic matters · 8 min read
Time and Work is a consistent scorer in AFCAT Numerical Ability. Expect 2-3 questions per paper. Questions test your ability to find combined work rates, calculate days when workers join or leave midway, and handle pipe and cistern variants. Difficulty is moderate — mostly formula-based with one tricky twist. Mastering the unitary method and LCM approach will let you solve most questions in under 90 seconds.
Core Concept: Work as a Rate
Think of work as filling a bucket. If A fills it in 10 days, then in 1 day A fills 1/10th of the bucket. This fraction is called the work rate or efficiency. The golden rule is: Work Done = Rate x Time. All Time and Work problems reduce to combining or comparing these rates.
- If a person completes a job in N days, their 1-day work = 1/N
- Total work is always assumed = 1 (the whole job)
- Combined rate of A and B together = 1/A + 1/B
- Time taken together = 1 divided by combined rate
- If work is given in units (not fraction), scale proportionally
Key formulas
Time Together
T = (A x B) / (A + B)
When: Use when exactly two people work together throughout
Combined Rate
Combined Rate = 1/A + 1/B + 1/C + ...
When: Use when 3 or more people work together
Work Done Formula
Work Done = Rate x Days Worked
When: Use when a person works for only part of the total duration
Worked examples
A can do a job in 12 days, B in 18 days. Together: T = (12x18)/(12+18) = 216/30 = 7.2 days. Answer = 7 days 4 hours or simply 7.2 days.
A and B together finish in 6 days. A alone takes 10 days. B alone: 1/B = 1/6 - 1/10 = (5-3)/30 = 2/30 = 1/15. So B takes 15 days.
LCM Method (Faster for AFCAT)
Instead of working with fractions, assume total work = LCM of all given days. Then each person's efficiency becomes a whole number. This method is faster and less error-prone in exam conditions. Think of it as counting bricks instead of fractions of a wall.
- Step 1: Find LCM of all days given in the problem
- Step 2: Efficiency of each person = LCM divided by their individual days
- Step 3: Combined efficiency = sum of individual efficiencies
- Step 4: Days to complete = Total Work (LCM) divided by combined efficiency
- This method avoids messy fractions completely
Key formulas
LCM Method
Days Together = LCM(A, B, ...) / (LCM/A + LCM/B + ...)
When: Best approach when 2 or more workers are involved — always faster
Worked examples
A finishes in 12 days, B in 18 days. LCM = 36. Efficiency: A = 36/12 = 3 units/day, B = 36/18 = 2 units/day. Combined = 5 units/day. Days = 36/5 = 7.2 days. Same answer, no fractions needed.
A does a job in 10 days, B in 15 days, C in 30 days. LCM = 30. A = 3, B = 2, C = 1 units/day. Together = 6 units/day. Days = 30/6 = 5 days.
Midway / Alternate Work Problems
AFCAT frequently asks: A works for some days, then B joins (or A leaves). You need to find total time. Strategy: Calculate work done in the first phase, find remaining work, then apply the new rate for the second phase. For alternate day problems, calculate work done in a 2-day cycle and multiply.
- Midway join: Work done before joining + Work done together = 1
- For alternate days: Find work in 1 cycle (e.g., 2 days), then multiply cycles
- Always check if remaining work finishes in full days or partial days
- If A leaves early, remaining work is done by B alone — set up equation clearly
- LCM method makes midway problems much cleaner
Key formulas
Remaining Work
Remaining Work = 1 - (Rate x Days Already Worked)
When: Use when one person starts alone and another joins or leaves midway
Worked example
A and B can finish a job in 12 and 18 days. A works alone for 4 days, then B joins. Using LCM=36: A=3, B=2. Work done in 4 days by A = 4x3=12 units. Remaining = 36-12=24 units. Together rate=5. Days = 24/5 = 4.8 days. Total = 4 + 4.8 = 8.8 days.
Pipes and Cisterns
This is just Time and Work in disguise. Inlet pipes fill the tank (positive rate), outlet pipes or leaks drain it (negative rate). Treat filling as positive efficiency and draining as negative. Everything else is identical to standard work problems.
- Inlet pipe fills in A hours — rate = +1/A
- Outlet pipe empties in B hours — rate = -1/B
- Net rate = sum of all positive rates minus all negative rates
- Time to fill = 1 divided by net rate
- If net rate is negative, tank will never fill — it empties instead
Key formulas
Net Fill Rate
Net Rate = (1/Inlet) - (1/Outlet)
When: When both inlet and outlet are open simultaneously
Time to Fill with Leak
Time = 1 / [(1/Fill Time) - (1/Leak Time)]
When: When a leak or outlet reduces filling efficiency
Worked examples
Pipe A fills in 6 hours, Pipe B empties in 12 hours. Both open: Net = 1/6 - 1/12 = 2/12 - 1/12 = 1/12. Tank fills in 12 hours.
A tap fills a tank in 8 hours. A leak empties it in 24 hours. Net = 1/8 - 1/24 = 3/24 - 1/24 = 2/24 = 1/12. Tank fills in 12 hours.
⚠ Common mistakes to avoid
- Adding days directly instead of adding rates: A takes 10 days + B takes 20 days does NOT mean together they take 30 days. Always add 1/10 + 1/20, never 10 + 20.
- Forgetting to check if the answer is a fraction of a day: AFCAT options sometimes give hours or mixed numbers — convert 0.5 days to 12 hours if needed.
- In pipes and cisterns, treating outlet as positive rate: Always subtract outlet/leak rate from inlet rate or you get a wrong sign and wrong answer.
- Using the two-person formula T = AB/(A+B) for three or more people: This formula works only for exactly two workers. For three, use the LCM method.
- In alternate-day problems, assuming both work every day: If A works on odd days and B on even days, calculate a 2-day cycle first, do not just add their rates directly.
🧠 Memory aids
- RATE FIRST, DAYS LAST: Always convert days to rates (1/N) before doing any math. Never touch days directly in addition or subtraction.
- LCM = Your Best Friend: Whenever you see multiple workers, immediately find LCM and convert to efficiency units. It turns fractions into whole numbers instantly.
- FILL PLUS, DRAIN MINUS: For pipes, write all inlets as positive (+) and all outlets as negative (-). Add them up. Done.
- The Bucket Analogy: Each worker fills a fraction of the bucket per day. Adding workers = adding bucket-fill speeds. If one pokes a hole (leak), subtract that speed.
🎯 AFCAT exam tips
- AFCAT typically has 2-3 Time and Work questions per paper. At least one will be a straightforward two-person combined work problem — free marks if you know the formula.
- One question is usually a midway variation — A works alone for X days then B joins. Use LCM method here to avoid fraction errors under time pressure.
- Pipes and Cisterns appears in roughly 40-50 percent of papers as a substitute question in place of a standard work problem. Treat it identically — same method.
- Answer options in AFCAT are usually clean numbers or simple fractions. If your calculation gives a messy decimal, you have likely made a sign error or added days instead of rates.
- Target under 75 seconds per question. If it crosses 90 seconds, mark and move on. The LCM method should keep you well within time on standard questions.
Q1 · medium · AI-verified
A and B together can complete a task in 12 days. B and C together can complete the same task in 15 days. A and C together can complete it in 20 days. How many days will A alone take to complete the task?
- 30 days
- 40 days
- 24 days
- 36 days
Q2 · medium · AI-verified
A pipe can fill a tank in 8 hours and another pipe can empty it in 12 hours. If both pipes are opened simultaneously, in how many hours will the tank be filled?
- 16 hours
- 24 hours
- 28 hours
- 20 hours
Q3 · medium · AI-verified
A tap can fill a cistern in 4 hours. Due to a leak at the bottom, it takes 6 hours to fill the cistern. In how much time can the leak empty the full cistern?
- 12 hours
- 10 hours
- 8 hours
- 15 hours
Q4 · medium · AI-verified
A squadron can complete a training mission in 12 days. Another squadron can complete the same mission in 18 days. If both squadrons work together, in how many days can they complete the mission?
- 9 days
- 8 days
- 6.5 days
- 7.2 days
Q5 · medium · AI-verified
A and B together can complete a work in 12 days. A alone can complete the same work in 20 days. In how many days can B alone complete the work?
- 30 days
- 25 days
- 28 days
- 24 days