Sarkari RiseLogin

Gravitation and Satellites Questions for AGNIVEER VAYU

Free, AI-curated practice for the Gravitation and Satellites section of AGNIVEER VAYU. We have 20+ verified questions in this bank. Below: 5 sample questions. Sign up free to unlock unlimited practice + AI explanations + per-topic analytics.

▶ Start free — AGNIVEER VAYU mockAll AGNIVEER VAYU resourcesAlready a user? Sign in →
Why this topic matters · 8 min read
Gravitation and satellites appear in 2-3 questions per Agniveer Vayu paper, typically mixing conceptual understanding with numerical problem-solving. Expect questions on orbital velocity, escape velocity, gravitational potential energy, and satellite motion. This topic bridges mechanics and energy concepts — mastering it unlocks marks in both domains. High weightage in reasoning-based MCQs.

Newton's Law of Universal Gravitation

Every mass attracts every other mass. The force depends on how massive the objects are and how far apart they sit. Think of gravity as an invisible rope connecting all objects — the heavier the objects, the stronger the rope; the farther apart, the weaker it becomes. This is the foundation for understanding planetary motion and satellite behavior.

  • Force is directly proportional to product of masses (M and m)
  • Force is inversely proportional to square of distance (r squared)
  • Gravitational constant G = 6.67 × 10^-11 N⋅m²/kg² — always given in exam
  • Works for point masses and spherically symmetric bodies
  • Gravity is always attractive, never repulsive
Key formulas
Universal Gravitation
F = GMm / r²
When: Calculate gravitational force between any two masses
Gravitational Field Strength
g = GM / r²
When: Find acceleration due to gravity at distance r from center of mass
Worked example

Two satellites of mass 1000 kg each orbit at 400 km altitude. G = 6.67 × 10^-11. Find mutual gravitational force if separated by 1 km. Answer: F = (6.67 × 10^-11 × 10^6 × 10^6) / (10^3)² = 6.67 × 10^-3 N (very small, which is why satellites don't collide due to gravity alone).

Orbital Velocity and Circular Orbits

A satellite orbits when gravitational force provides exactly the centripetal force needed to keep it in circular motion. If velocity is too low, it falls; too high, it escapes. The orbital velocity is independent of the satellite's mass — a feather and a boulder orbit at the same speed if at the same altitude. This is counterintuitive but critical for Agniveer questions.

  • Gravitational force = Centripetal force: GMm/r² = mv²/r
  • Orbital velocity v_o = sqrt(GM/r) — depends only on central mass and radius
  • For Earth orbit at surface: v_o ≈ 7.9 km/s (first cosmic velocity)
  • Orbital velocity decreases with altitude: higher orbit = slower speed
  • Period of orbit T = 2πr / v_o = 2π sqrt(r³/GM)
Key formulas
Orbital Velocity
v_o = sqrt(GM/r)
When: Find speed needed for circular orbit at radius r
Orbital Period
T = 2π sqrt(r³/GM)
When: Calculate time for one complete orbit (Kepler's 3rd Law)
Orbital Kinetic Energy
KE = (1/2)mv_o² = GMm / 2r
When: Find kinetic energy of orbiting satellite
Worked examples

ISS orbits at 400 km altitude. Earth radius = 6400 km, g = 10 m/s². Find orbital velocity. r = 6400 + 400 = 6800 km = 6.8 × 10^6 m. g = GM/R² so GM = 10 × (6.4 × 10^6)² ≈ 4.1 × 10^14. v_o = sqrt(4.1 × 10^14 / 6.8 × 10^6) ≈ 7.8 km/s.

Geostationary satellite has T = 24 hours. Using T² ∝ r³, find its orbital radius. T = 86400 s. r³ = GMT²/(4π²) ≈ 7.5 × 10^22. r ≈ 42,000 km from Earth's center (about 36,000 km altitude).

Escape Velocity

Escape velocity is the minimum speed needed to break free from a planet's gravity and never return. Unlike orbital velocity (which keeps you in circular motion), escape velocity launches you away forever. It's independent of direction — you can escape upward, sideways, or at any angle. For Earth, it's about 11.2 km/s.

  • Escape velocity v_e = sqrt(2GM/R) — exactly sqrt(2) times orbital velocity at surface
  • For Earth: v_e ≈ 11.2 km/s (second cosmic velocity)
  • Independent of mass of escaping object — a rocket and a pebble escape at same speed
  • Derived from energy conservation: KE at surface = PE at infinity
  • Escape velocity increases with planet mass, decreases with planet radius
Key formulas
Escape Velocity
v_e = sqrt(2GM/R)
When: Minimum speed to escape gravitational field from surface
Escape Velocity vs Orbital
v_e = sqrt(2) × v_o
When: Quick relationship between two velocities
Worked example

Moon has mass 7.3 × 10^22 kg, radius 1700 km. Find escape velocity. GM = 6.67 × 10^-11 × 7.3 × 10^22 ≈ 4.9 × 10^12. v_e = sqrt(2 × 4.9 × 10^12 / 1.7 × 10^6) ≈ 2.4 km/s (much lower than Earth because Moon is smaller).

Gravitational Potential Energy

Gravitational PE is the energy stored in the gravitational field. Unlike everyday potential energy (which is zero at ground level), gravitational PE is zero at infinity and negative everywhere else. This negative sign is crucial — it means objects are bound to the planet. The more negative the PE, the deeper in the gravity well you are.

  • PE = -GMm/r (always negative for bound objects)
  • At Earth's surface: PE ≈ -GMm/R
  • Total mechanical energy of orbiting satellite: E = KE + PE = -GMm/2r (negative = bound)
  • To escape: total energy must be zero or positive
  • Potential energy increases (becomes less negative) as you move away from planet
Key formulas
Gravitational PE
PE = -GMm/r
When: Calculate potential energy at distance r from center
Total Orbital Energy
E_total = -GMm / 2r
When: Find total mechanical energy of satellite in circular orbit

Kepler's Laws and Satellite Motion

Kepler's laws describe how planets and satellites move. The third law is most useful for exams — it relates orbital period to orbital radius. All satellites follow these laws regardless of their mass. These laws emerge naturally from Newton's gravity law but are stated separately because they're so powerful for predictions.

  • Kepler 1st Law: Orbits are ellipses with central body at one focus
  • Kepler 2nd Law: Equal areas swept in equal times (angular momentum conservation)
  • Kepler 3rd Law: T² ∝ r³ or T² = (4π²/GM) × r³
  • For circular orbits, r is orbital radius; for ellipses, use semi-major axis
  • Useful for comparing satellites: T₁²/T₂² = r₁³/r₂³
Key formulas
Kepler's 3rd Law
T² = (4π² / GM) × r³
When: Relate orbital period to orbital radius
Kepler Ratio Form
T₁² / T₂² = r₁³ / r₂³
When: Compare two satellites without knowing G or M
Worked example

Moon orbits Earth in 27.3 days at 3.84 × 10^8 m. ISS orbits in 90 minutes at 6.8 × 10^6 m. Verify Kepler's law. T₁²/T₂² = (27.3 × 24 × 3600)² / (90 × 60)² ≈ 2.4 × 10^8. r₁³/r₂³ = (3.84 × 10^8)³ / (6.8 × 10^6)³ ≈ 2.4 × 10^8. Matches!

⚠ Common mistakes to avoid
  • Forgetting that orbital velocity is independent of satellite mass — many students think heavier satellites need higher speeds. Wrong. Speed depends only on the central body and altitude.
  • Confusing escape velocity with orbital velocity — escape velocity is sqrt(2) times larger and launches you away forever, not into orbit.
  • Using r as Earth's radius instead of orbital radius — always measure from center of Earth. If altitude is h, then r = R + h.
  • Treating gravitational PE as positive — it's always negative for bound objects. This trips up energy conservation problems.
  • Forgetting that Kepler's 3rd Law uses semi-major axis for ellipses, not just any radius — circular orbits use the radius directly.
  • Mixing up 'g' at surface with 'g' at altitude — g decreases as 1/r², so at 2R from center, g becomes g/4, not g/2.
🧠 Memory aids
  • GOVE: Gravitation, Orbit, Velocity, Escape — the four pillars of satellite physics. Master each separately, then combine.
  • Orbital velocity = sqrt(GM/r). Escape velocity = sqrt(2GM/r). Escape is sqrt(2) times orbital. Remember: 1.414 × orbital = escape.
  • PE is negative, KE is positive, total energy of orbit is negative (bound). Negative total = trapped. Zero or positive = free.
  • Kepler 3: T² goes with r³. If radius doubles, period increases by 2^(3/2) ≈ 2.83 times, not 2 times. Cube root relationship is key.
  • ISS memory peg: ~7.8 km/s orbital velocity, ~90 min period, ~400 km altitude. Use this as a reference point for all Earth orbit problems.
🎯 AGNIVEER VAYU exam tips
  • Agniveer Vayu typically asks 1-2 direct calculation questions (orbital velocity, escape velocity, period) and 1-2 conceptual questions (why satellites don't fall, how geostationary orbits work). Practice both types.
  • Recent papers favor questions combining two concepts: e.g., 'A satellite is launched from Earth's surface with escape velocity. How high does it go?' (Requires energy conservation + escape velocity knowledge).
  • Diagram-based questions are common — you may see orbital diagrams and be asked to identify which satellite is fastest, has longest period, or requires most energy to launch. Faster orbits are lower; slower orbits are higher.
  • Time management: Numerical problems take 3-4 minutes. Conceptual questions take 1-2 minutes. Allocate accordingly in your 2-hour exam window.
  • Always state your assumptions clearly (e.g., 'assuming circular orbit,' 'neglecting air resistance'). Agniveer examiners value reasoning, not just final answers.
  • Use g = 10 m/s² and GM = 4 × 10^14 m³/s² for Earth unless told otherwise — this speeds up calculations significantly.

Sample questions

Q1 · hard · AI-verified
A satellite is orbiting Earth at a height h above the surface. If the radius of Earth is R and acceleration due to gravity at the surface is g, what is the orbital velocity of the satellite?
  1. √(gR/(R+h))
  2. √(2gR²/(R+h))
  3. √(gR²/(R+h)²)
  4. √(gR²/(R+h))
Q2 · hard · AI-verified
The binding energy of a satellite of mass m in a circular orbit of radius r around Earth (mass M) is:
  1. GMm/r
  2. GMm/(4r)
  3. 2GMm/r
  4. GMm/(2r)
Q3 · easy · AI-verified
The weight of an object at the centre of the Earth is:
  1. Half its weight at the surface
  2. Equal to its weight at the surface
  3. Zero
  4. Double its weight at the surface
Q4 · easy · AI-verified
The gravitational force between two objects is inversely proportional to the square of the distance between them. This law is known as:
  1. Hooke's Law
  2. Kepler's Second Law
  3. Coulomb's Law
  4. Newton's Law of Universal Gravitation
Q5 · hard · AI-verified
The gravitational potential energy of a body of mass m at a depth d below Earth's surface is given by (R = radius of Earth, M = mass of Earth, G = gravitational constant):
  1. −GMm(R − d)/R²
  2. −GMm(3R² − d²)/(2R³)... wait, the gravitational potential at depth d is −Gm(3R²−r²)/(2R³); simplified: U = −GMm/(2R³)(3R² − d²)
  3. −GMm/d
  4. −GMm/(R − d)
💡 Want answers + explanations + 15+ more Gravitation and Satellites questions? Sign up free →
⭐ Recommended for AGNIVEER VAYU aspirants

Full AI 6-Month

all your target exams · 6 months · unlimited mocks + AI
₹799~₹4.4/day
Sign up free, then unlockSee all plans →

More AGNIVEER VAYU topics

Oscillations and Waves
20+ practice questions
Algebra Complex Numbers Class 11
20+ practice questions
Laws of Motion and Friction
20+ practice questions
Properties of Solids and Fluids
20+ practice questions
Para Jumbles
20+ practice questions
Electrostatics and Capacitance
19+ practice questions

Free practice, AI explanations, 24 exams — all in one app

Daily 10-Q quiz · AI doubt solver in Hindi + English · adaptive mocks · 49,000+ practice questions (19,000+ verified PYQs).

Sign up freePricingTry Daily 10-Q