Why this topic matters · 8 min read
Oscillations and waves are core physics topics in Agniveer Vayu exams, typically appearing in 3-5 questions. The exam tests simple harmonic motion (SHM), wave equations, Doppler effect, and interference/diffraction. Expect numerical problems on frequency, wavelength, and energy. This topic bridges mechanics and optics, so mastering it unlocks multiple question types.
Simple Harmonic Motion (SHM) Basics
SHM is motion where an object oscillates back and forth around a fixed point (equilibrium), with acceleration always directed toward that point and proportional to displacement. Think of a pendulum or a mass on a spring. The key insight: the restoring force is always opposite to displacement. In Agniveer exams, you will see questions on time period, frequency, amplitude, and energy in SHM systems. The motion is sinusoidal, meaning displacement, velocity, and acceleration follow sine or cosine curves.
- Restoring force F = -kx (negative sign means opposite to displacement)
- Acceleration a = -omega squared times x (omega = angular frequency)
- Displacement x = A sin(omega t + phi), where A is amplitude and phi is phase
- Velocity v = A omega cos(omega t + phi), maximum when passing through equilibrium
- Acceleration maximum at extreme positions (amplitude), zero at equilibrium
Key formulas
Time Period of SHM
T = 2π√(m/k) for spring; T = 2π√(L/g) for pendulum
When: Calculate how long one complete oscillation takes. Spring: m is mass, k is spring constant. Pendulum: L is length, g is gravity.
Frequency
f = 1/T or f = ω/(2π)
When: Number of oscillations per second. Always inverse of period.
Total Energy in SHM
E = (1/2)kA² = (1/2)mω²A²
When: Constant throughout motion. At any point: E = KE + PE. At amplitude: all PE. At equilibrium: all KE.
Velocity at position x
v = ω√(A² - x²)
When: Find speed at any displacement without using time. Useful for energy-based questions.
Worked examples
A mass of 0.5 kg attached to a spring (k = 200 N/m) oscillates with amplitude 0.1 m. Find time period and maximum velocity. Solution: T = 2π√(0.5/200) = 2π√(0.0025) = 0.314 s. ω = 2π/T = 20 rad/s. v_max = ωA = 20 × 0.1 = 2 m/s.
A simple pendulum has length 1 m. Find its frequency on Earth (g = 10 m/s²). Solution: T = 2π√(1/10) = 2π√0.1 ≈ 1.99 s. f = 1/T ≈ 0.5 Hz.
Waves: Types and Properties
A wave is a disturbance that travels through a medium (or space) carrying energy. Transverse waves have particles moving perpendicular to wave direction (light, water ripples). Longitudinal waves have particles moving parallel to wave direction (sound, compression waves). Agniveer exams focus on wave equation, wavelength-frequency relationships, and wave speed. The fundamental relationship v = f × lambda connects all wave properties.
- Wavelength (lambda): distance between consecutive crests or troughs
- Frequency (f): number of waves passing a point per second, measured in Hz
- Wave speed (v): how fast the wave travels through medium, v = f × lambda
- Period (T): time for one complete wave to pass a point, T = 1/f
- Amplitude: maximum displacement of particles from equilibrium
- For sound in air at 20°C: v ≈ 340 m/s; for light in vacuum: v = 3 × 10^8 m/s
Key formulas
Wave Equation
v = f × λ
When: Core relationship. Given any two, find the third. Most common in Agniveer numericals.
Wave Speed in String
v = √(T/μ)
When: T is tension, μ is linear mass density (mass per unit length). Used for vibrating strings.
Intensity of Wave
I = (1/2)ρvω²A²
When: Power per unit area. Depends on medium density (ρ), speed (v), angular frequency (ω), and amplitude (A).
Worked examples
A sound wave has frequency 500 Hz and wavelength 0.68 m. Find wave speed. Solution: v = f × λ = 500 × 0.68 = 340 m/s (matches sound speed in air).
A string of length 1 m and mass 0.01 kg is under tension 100 N. Find wave speed. Solution: μ = 0.01/1 = 0.01 kg/m. v = √(100/0.01) = √10000 = 100 m/s.
Doppler Effect
The Doppler effect is the change in frequency (and wavelength) when a source and observer move relative to each other. When source moves toward observer, frequency increases (pitch rises). When source moves away, frequency decreases (pitch falls). This is tested heavily in Agniveer exams because it combines wave concepts with relative motion. The formula changes depending on whether source or observer (or both) are moving.
- Source moving toward stationary observer: f' = f × v/(v - v_s), where v_s is source speed
- Source moving away from stationary observer: f' = f × v/(v + v_s)
- Observer moving toward stationary source: f' = f × (v + v_o)/v, where v_o is observer speed
- Observer moving away from stationary source: f' = f × (v - v_o)/v
- Both moving: combine the effects using relative velocity concept
- Real-world example: ambulance siren pitch changes as it passes you
Key formulas
Doppler Effect (General)
f' = f × (v + v_o)/(v - v_s)
When: When both observer and source move. v_o positive if observer moves toward source, v_s positive if source moves toward observer. v is wave speed in medium.
Worked examples
A train whistle emits 400 Hz. Train moves toward stationary observer at 20 m/s. Sound speed = 340 m/s. Find observed frequency. Solution: f' = 400 × 340/(340 - 20) = 400 × 340/320 = 425 Hz.
Observer moves toward a stationary speaker emitting 500 Hz at 10 m/s. Sound speed = 340 m/s. Find observed frequency. Solution: f' = 500 × (340 + 10)/340 = 500 × 350/340 ≈ 515 Hz.
Interference and Diffraction
Interference occurs when two or more waves overlap. If crests align (constructive interference), amplitude increases. If crest meets trough (destructive interference), they cancel. Diffraction is bending of waves around obstacles or through slits. Agniveer exams ask about path difference, phase difference, and conditions for bright/dark fringes. These concepts are critical for understanding light behavior and are often paired with numerical calculations.
- Constructive interference: path difference = n × lambda (n = 0, 1, 2, ...), waves reinforce
- Destructive interference: path difference = (n + 1/2) × lambda, waves cancel
- Phase difference = (2π/lambda) × path difference
- Young's double slit: fringe width w = λD/d, where D is distance to screen, d is slit separation
- Single slit diffraction: first minimum at sin(theta) = λ/b, where b is slit width
- Diffraction more pronounced when wavelength is comparable to obstacle size
Key formulas
Fringe Width (Double Slit)
w = λD/d
When: Distance between adjacent bright or dark fringes. λ is wavelength, D is slit-to-screen distance, d is slit separation.
Path Difference for Bright Fringe
Δ = nλ
When: n = 0, 1, 2, ... Constructive interference occurs at these positions.
Path Difference for Dark Fringe
Δ = (2n + 1)λ/2
When: n = 0, 1, 2, ... Destructive interference occurs at these positions.
Worked examples
Two coherent light sources (λ = 600 nm) are 2 mm apart. Screen is 1 m away. Find fringe width. Solution: w = (600 × 10^-9 × 1)/(2 × 10^-3) = 600 × 10^-9 / 2 × 10^-3 = 3 × 10^-4 m = 0.3 mm.
Path difference between two interfering waves is 1.5 × wavelength. Is this constructive or destructive? Solution: 1.5λ = (2 × 0 + 1) × λ/2 + λ = destructive interference (dark fringe).
Standing Waves and Resonance
Standing waves form when two waves of equal frequency and amplitude travel in opposite directions and interfere. They appear stationary with nodes (zero displacement) and antinodes (maximum displacement). Resonance occurs when driving frequency matches natural frequency, causing large amplitude oscillations. In Agniveer exams, standing waves in strings and pipes are common. These questions test understanding of boundary conditions and harmonic series.
- Nodes: points of zero displacement (always at fixed ends)
- Antinodes: points of maximum displacement (midway between nodes)
- For string fixed at both ends: L = n × (λ/2), where n = 1, 2, 3, ...
- For pipe closed at one end: L = (2n - 1) × (λ/4), where n = 1, 2, 3, ...
- For pipe open at both ends: L = n × (λ/2), same as string
- Resonance amplifies vibration when external frequency matches natural frequency
Key formulas
Fundamental Frequency (String)
f_1 = v/(2L)
When: Lowest frequency for string of length L with wave speed v. Higher harmonics: f_n = n × f_1.
Fundamental Frequency (Pipe Closed)
f_1 = v/(4L)
When: Lowest frequency for pipe closed at one end. Only odd harmonics present: f_n = (2n-1) × f_1.
Fundamental Frequency (Pipe Open)
f_1 = v/(2L)
When: Lowest frequency for pipe open at both ends. All harmonics present: f_n = n × f_1.
Worked examples
A guitar string of length 0.5 m vibrates at fundamental frequency 200 Hz. Find wave speed. Solution: v = 2 × f_1 × L = 2 × 200 × 0.5 = 200 m/s.
An organ pipe closed at one end has length 0.25 m. Sound speed = 340 m/s. Find first three frequencies. Solution: f_1 = 340/(4 × 0.25) = 340 Hz. f_2 = 3 × 340 = 1020 Hz. f_3 = 5 × 340 = 1700 Hz.
⚠ Common mistakes to avoid
- Confusing amplitude with wavelength. Amplitude is vertical displacement; wavelength is horizontal distance between crests. They are independent properties.
- Using wrong formula for Doppler effect. Remember: source moving toward observer increases frequency; observer moving toward source also increases frequency. Sign convention matters.
- Forgetting that in standing waves, only certain frequencies are allowed. Not every frequency will resonate—only those matching boundary conditions (L = n × λ/2 for strings).
- Mixing up constructive and destructive interference conditions. Constructive: path difference = n × λ. Destructive: path difference = (n + 0.5) × λ. Easy to reverse.
- Assuming wave speed is constant across all media. Sound speed varies: ~340 m/s in air, ~1500 m/s in water, ~5000 m/s in steel. Always check the medium.
- Neglecting phase difference in SHM. Two oscillators with same frequency but different phases can have very different behaviors. Phase shift = 2π × (path difference / wavelength).
🧠 Memory aids
- SHM Energy Rule: At amplitude (extreme), all PE. At equilibrium (center), all KE. Energy swaps like a seesaw.
- Doppler Direction: Source/observer moving TOWARD each other = frequency UP. Moving AWAY = frequency DOWN. Think: ambulance siren pitch.
- Wave Speed Hierarchy: Light (3×10^8 m/s) > Sound in steel (5000 m/s) > Sound in water (1500 m/s) > Sound in air (340 m/s). Denser medium = faster sound.
- Interference Mnemonic: CCDD = Constructive (Crests together, Darkness disappears). Destructive (Dips meet crests, Darkness appears).
- Standing Wave Nodes: Fixed ends = NODES always. Free ends = ANTINODES. Think: fixed = frozen = node.
- Fringe Formula: w = λD/d. Bigger wavelength or distance = wider fringes. Bigger slit separation = narrower fringes. Intuitive: spread out sources = tight pattern.
🎯 AGNIVEER VAYU exam tips
- Agniveer Vayu typically asks 1-2 straightforward SHM numericals (time period, frequency, energy). Master the formulas T = 2π√(m/k) and E = (1/2)kA². These appear in almost every exam.
- Wave equation v = f × λ is tested in 2-3 questions annually. Often paired with Doppler effect or standing waves. Practice converting between frequency, wavelength, and speed quickly.
- Doppler effect questions usually involve moving vehicles (trains, ambulances) or sound sources. The exam expects you to identify whether source or observer moves and apply the correct formula. Recent papers show 1 question per exam.
- Interference and diffraction are less frequent (0-1 question) but high-scoring if you know path difference conditions. Young's double slit fringe width formula is a favorite. Practice at least 3-4 numerical problems.
- Standing waves in strings and pipes appear in 1-2 questions. Know the difference between closed and open pipes—this is a common trap. Closed pipe has only odd harmonics; open pipe has all harmonics.
- Time management: SHM and wave speed questions are quick (2-3 min). Doppler and interference take 4-5 min. Allocate accordingly. If stuck on Doppler direction, draw a diagram—it clarifies instantly.
- Recent trend: Agniveer exams combine SHM with energy conservation (e.g., 'A mass on spring oscillates. At what displacement is KE = PE?'). Practice energy-based SHM problems.
Q1 · easy · AI-verified
A simple pendulum completes 20 oscillations in 40 seconds. What is its frequency?
- 1 Hz
- 0.5 Hz
- 2 Hz
- 20 Hz
Q2 · hard · AI-verified
In a closed organ pipe of length 0.85 m, the frequency of the third harmonic (third overtone) is (speed of sound = 340 m/s):
- 300 Hz
- 500 Hz
- 200 Hz
- 100 Hz
Q3 · hard · AI-verified
The speed of sound in air is 340 m/s. Two tuning forks produce 5 beats per second. If the frequency of one fork is 500 Hz, what is the wavelength of the wave produced by the other fork (assuming its frequency is higher)?
- 0.645 m
- 0.653 m
- 0.680 m
- 0.673 m
Q4 · hard · AI-verified
A mass-spring system has a spring constant k = 200 N/m and mass m = 0.5 kg. It is given an initial displacement of 0.1 m from equilibrium. What is the maximum velocity of the mass?
- 4 m/s
- 1 m/s
- 2 m/s
- 0.5 m/s
Q5 · easy · AI-verified
Which of the following waves requires a material medium to propagate?
- X-rays
- Light waves
- Sound waves
- Radio waves