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Simple Interest and Compound Interest Questions for BIHAR POLICE CONSTABLE

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Why this topic matters · 8 min read
SI and CI are bread-and-butter topics in Bihar Police Constable numerical section — typically 2-3 questions per paper, mixed difficulty. Examiners test formula application, comparison between SI and CI, time-period conversions, and rate-finding. High accuracy needed; calculation errors cost marks heavily. Weightage ~8-12% of numerical section.

Simple Interest (SI) Fundamentals

Simple Interest is interest calculated only on the principal amount, never on accumulated interest. Think of it as a straight line — same interest every year. If you borrow 1000 rupees at 10% SI for 3 years, you pay 100 rupees interest every single year (not compounding). It's the easiest interest type but rarely used in real banking; examiners love testing whether you confuse it with CI.

  • SI depends on Principal (P), Rate (R), and Time (T) only — never on previous interest
  • Interest amount is always the same each year
  • Total Amount = Principal + Total Interest
  • Used in government savings schemes, some loans, and exam trick questions
  • Formula: SI = (P × R × T) / 100
Key formulas
Simple Interest
SI = (P × R × T) / 100
When: Calculate interest when rate is fixed and does not compound yearly
Amount after SI
A = P + SI = P + (P × R × T) / 100 = P(1 + RT/100)
When: Find total money to be returned or received
Find Principal
P = (SI × 100) / (R × T)
When: SI and rate/time are given, need to find original amount
Find Rate
R = (SI × 100) / (P × T)
When: SI, principal, and time are known
Find Time
T = (SI × 100) / (P × R)
When: SI, principal, and rate are known
Worked examples

Principal = 5000, Rate = 8% p.a., Time = 2 years. SI = (5000 × 8 × 2) / 100 = 800. Amount = 5000 + 800 = 5800.

Amount = 6000, SI = 1200, Time = 3 years. Find Rate: SI = (P × R × T) / 100, so 1200 = (5000 × R × 3) / 100 [assuming P = 6000 - 1200 = 4800 or given]. Solve: R = (1200 × 100) / (4800 × 3) = 8.33% p.a.

Compound Interest (CI) Fundamentals

Compound Interest is interest calculated on principal PLUS accumulated interest. Each year, the interest is added to principal, and next year's interest is calculated on this new amount. Think of a snowball rolling downhill — it grows faster and faster. This is how real banks work. CI is always greater than or equal to SI (equal only when time = 1 year). Examiners frequently ask for the difference between SI and CI, or which is better for the lender.

  • Interest is calculated on principal + previous interest (compounding effect)
  • Amount grows exponentially, not linearly
  • CI >= SI always (equality only when T = 1)
  • Compounding can be yearly, half-yearly, quarterly, or monthly
  • Formula: A = P(1 + R/100)^T, then CI = A - P
Key formulas
Compound Interest (yearly)
A = P(1 + R/100)^T
When: Calculate amount when interest compounds annually
CI Amount
CI = A - P = P[(1 + R/100)^T - 1]
When: Find interest earned (not total amount)
CI Half-yearly
A = P(1 + R/200)^(2T)
When: Interest compounds twice per year (rate halved, time doubled)
CI Quarterly
A = P(1 + R/400)^(4T)
When: Interest compounds 4 times per year
Difference: CI - SI
CI - SI = P × R^2 × T(T+1) / (100)^2 × 2 (approx for 2 years)
When: Compare SI and CI or find difference directly
Worked examples

Principal = 1000, Rate = 10% p.a., Time = 2 years, compounded yearly. A = 1000(1 + 10/100)^2 = 1000 × 1.1^2 = 1000 × 1.21 = 1210. CI = 1210 - 1000 = 210.

Principal = 2000, Rate = 20% p.a., Time = 1.5 years, compounded half-yearly. A = 2000(1 + 20/200)^(2 × 1.5) = 2000(1.1)^3 = 2000 × 1.331 = 2662. CI = 2662 - 2000 = 662.

SI vs CI and Difference Calculation

This is a high-frequency exam question: given principal, rate, and time, find SI, find CI, then compare or find difference. The key insight is that CI grows faster because of compounding. For 2 years, there's a neat formula for the difference. For longer periods, just calculate both separately. Examiners also ask which is better for lender (CI) vs borrower (SI).

  • For T = 1 year: SI = CI always
  • For T = 2 years: CI - SI = P × R^2 / (100)^2 (simple formula)
  • For T > 2 years: calculate both and subtract
  • CI is always better for lender, SI better for borrower
  • Difference increases as rate or time increases
Worked examples

P = 1000, R = 10%, T = 2 years. SI = (1000 × 10 × 2) / 100 = 200. CI = 1000(1.1)^2 - 1000 = 1210 - 1000 = 210. Difference = 210 - 200 = 10. Using formula: 1000 × 10^2 / 10000 = 10. Matches!

P = 5000, R = 5%, T = 3 years. SI = (5000 × 5 × 3) / 100 = 750. A (CI) = 5000(1.05)^3 = 5000 × 1.157625 = 5788.125. CI = 5788.125 - 5000 = 788.125. Difference ≈ 38.

Time Period Conversions and Rate Adjustments

Examiners trick aspirants by giving time in months or days, or rate as half-yearly/quarterly. Always convert to consistent units BEFORE applying formulas. If rate is annual but time is in months, convert months to years (divide by 12). If compounding is half-yearly, the rate per half-year is R/2 and time periods double. This is where calculation errors happen.

  • Time in months: divide by 12 to get years (e.g., 6 months = 0.5 years)
  • Time in days: divide by 365 (or 360 for some old problems)
  • Half-yearly compounding: use R/2 as rate, 2T as time periods
  • Quarterly compounding: use R/4 as rate, 4T as time periods
  • Monthly compounding: use R/12 as rate, 12T as time periods

Finding Unknown Variables (P, R, T)

Sometimes principal, rate, or time is unknown. Rearrange the SI or CI formula to solve. For SI, it's straightforward algebra. For CI, you may need to take roots or use logarithms (rare in Bihar Police, but possible). Most questions give you enough info to avoid complex math.

  • SI formula is linear — easy to rearrange for P, R, or T
  • CI formula is exponential — may need trial-and-error or approximation for rate/time
  • If CI and time are given, find rate by testing values (common exam trick)
  • Always check your answer by substituting back into original formula
⚠ Common mistakes to avoid
  • Confusing SI and CI formulas — SI is P×R×T/100, CI is P(1+R/100)^T. Write them on paper before solving.
  • Forgetting to convert time to years — 6 months is 0.5 years, not 6. This causes massive errors.
  • Using wrong compounding frequency — if half-yearly, divide rate by 2 AND double time periods. Doing only one is fatal.
  • Calculating CI as interest only, then adding to principal again — CI = A - P, not A. Don't double-count.
  • Rounding intermediate values — keep decimals until final answer. Rounding 1.1^3 to 1.3 instead of 1.331 costs marks.
  • Assuming annual compounding when not stated — always read 'compounded half-yearly' or 'quarterly' carefully.
🧠 Memory aids
  • SI = Simple = Straight line = Same interest every year = P×R×T/100
  • CI = Compound = Curve (exponential) = Growing faster = P(1+R/100)^T
  • For 2 years: CI - SI = P×R^2/10000 (remember: R squared, divided by 10000)
  • HY = Half-Yearly = Divide rate by 2, multiply time by 2. Q = Quarterly = Divide by 4, multiply by 4.
  • Lender loves CI (more interest), Borrower loves SI (less interest) — think 'L' for Lender and 'C' for CI.
🎯 BIHAR POLICE CONSTABLE exam tips
  • Bihar Police papers typically have 1 easy SI/CI question (direct formula application) and 1 medium question (comparing SI and CI or finding unknown variable). Expect 2-3 minutes per question if you know formulas.
  • Time conversion questions are common — always check if time is in months/days. This is where 30% of aspirants lose marks.
  • Half-yearly compounding appears in 1 out of 3 papers. Practice the formula A = P(1 + R/200)^(2T) until it's automatic.
  • Difference between SI and CI for 2 years (using P×R^2/10000) is a favorite shortcut question — memorize this formula.
  • In the last 5 years, no question asked for logarithms or complex rate-finding. Stick to straightforward formula application and trial-and-error for rate.
  • Watch out for 'per annum' vs 'per half-year' in the problem statement — read carefully, underline the rate type.

Sample questions

Q1 · hard · AI-verified
The compound interest on ₹30,000 at 20% per annum is ₹13,200. What is the time period in years?
  1. 2 years
  2. 3 years
  3. 1.5 years
  4. 2.5 years
Q2 · hard · AI-verified
A person borrows ₹5,000 at 8% per annum simple interest and repays ₹6,200 after some years. How many years did he borrow the money?
  1. 2 years
  2. 4 years
  3. 3 years
  4. 2.5 years
Q3 · medium · AI-verified
If the compound interest on a sum for 2 years at 10% per annum is ₹2100, what is the principal?
  1. ₹9000
  2. ₹11000
  3. ₹12000
  4. ₹10000
Q4 · easy · AI-verified
A principal of ₹6000 earns a simple interest of ₹900 in 3 years. What is the annual rate of interest?
  1. 4%
  2. 7.5%
  3. 6%
  4. 5%
Q5 · medium · AI-verified
The difference between the simple interest and compound interest on ₹8000 for 2 years at 5% per annum is:
  1. ₹25
  2. ₹20
  3. ₹40
  4. ₹10
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