Why this topic matters · 8 min read
Trigonometry is a high-frequency topic in NDA Maths (typically 8-12% of paper). Expect questions on angle identities, trigonometric ratios, inverse functions, and applications in heights/distances. NDA favors identity-based problems and angle conversion tricks over pure calculation. Master the 'magic angles' (0, 30, 45, 60, 90 degrees) and key identities to score quick marks.
Trigonometric Ratios & Standard Angles
The six trigonometric ratios (sin, cos, tan, cot, sec, cosec) are the foundation. In NDA, you must instantly recall values for 0, 30, 45, 60, 90 degrees — these appear in almost every paper. Remember: sin and cos are 'opposite' functions (sin 0 = 0, cos 0 = 1; sin 90 = 1, cos 90 = 0). Tan is the 'slope' ratio (opposite/adjacent). NDA often tests whether you can convert between degrees and radians, and apply these ratios in right triangles.
- sin(0°)=0, sin(30°)=1/2, sin(45°)=1/√2, sin(60°)=√3/2, sin(90°)=1
- cos values are reverse: cos(0°)=1, cos(30°)=√3/2, cos(45°)=1/√2, cos(60°)=1/2, cos(90°)=0
- tan(0°)=0, tan(30°)=1/√3, tan(45°)=1, tan(60°)=√3, tan(90°)=undefined
- Radian conversion: 180° = π radians; multiply degrees by π/180 to convert
- ASTC rule: All positive in Quadrant I; Sin positive in Q2; Tan positive in Q3; Cos positive in Q4
Key formulas
Basic Ratios
sin(θ) = opposite/hypotenuse, cos(θ) = adjacent/hypotenuse, tan(θ) = opposite/adjacent
When: In any right triangle; foundation for all trig problems
Radian to Degree
Radians = Degrees × (π/180); Degrees = Radians × (180/π)
When: When angle is given in one unit and you need the other
Pythagorean Identity
sin²(θ) + cos²(θ) = 1
When: Simplifying expressions or proving identities
Worked examples
If sin(θ) = 3/5 and θ is in Q1, find cos(θ). Using sin²(θ) + cos²(θ) = 1: (3/5)² + cos²(θ) = 1, so cos²(θ) = 16/25, thus cos(θ) = 4/5 (positive in Q1).
Convert 120° to radians: 120 × (π/180) = 2π/3 radians.
Trigonometric Identities & Simplification
NDA loves identity-based questions because they test conceptual understanding, not just memorization. The key identities are: sum/difference formulas, double angle formulas, and product-to-sum conversions. These appear in almost every paper, often disguised in 'prove that' or 'simplify' questions. Learn to recognize patterns — e.g., sin(A+B) vs sin(A-B) — and apply them mechanically. The double angle formulas are especially high-yield because they compress two angles into one.
- Sum formulas: sin(A±B) = sinA·cosB ± cosA·sinB; cos(A±B) = cosA·cosB ∓ sinA·sinB
- Double angle: sin(2θ) = 2sinθ·cosθ; cos(2θ) = cos²θ - sin²θ = 2cos²θ - 1 = 1 - 2sin²θ; tan(2θ) = 2tanθ/(1-tan²θ)
- Product-to-sum: sinA·sinB = [cos(A-B) - cos(A+B)]/2; cosA·cosB = [cos(A-B) + cos(A+B)]/2
- Sum-to-product: sinA + sinB = 2sin[(A+B)/2]·cos[(A-B)/2]
- Complementary angles: sin(90°-θ) = cosθ; cos(90°-θ) = sinθ; tan(90°-θ) = cotθ
Key formulas
Sum Formula (Sine)
sin(A+B) = sinA·cosB + cosA·sinB
When: When you need to expand sin of a sum; reverse it to combine two sine terms
Double Angle (Cosine)
cos(2θ) = 2cos²θ - 1 or 1 - 2sin²θ
When: Simplifying expressions with cos(2θ); choose form based on what's given
Tangent Addition
tan(A+B) = (tanA + tanB)/(1 - tanA·tanB)
When: Finding tan of sum; useful for angle addition problems
Worked examples
Prove: sin(60°+θ) + sin(60°-θ) = √3·cosθ. Using sum formulas: [sin60°cosθ + cos60°sinθ] + [sin60°cosθ - cos60°sinθ] = 2sin60°cosθ = 2·(√3/2)·cosθ = √3·cosθ. Done.
Simplify: cos(4θ) in terms of cosθ. Use cos(2θ) = 2cos²θ - 1 twice: cos(4θ) = 2cos²(2θ) - 1 = 2(2cos²θ - 1)² - 1 = 8cos⁴θ - 8cos²θ + 1.
Inverse Trigonometric Functions
NDA tests inverse trig (arcsin, arccos, arctan) in two ways: (1) finding the angle given a ratio, and (2) simplifying expressions like sin(arctan(x)). The key is understanding the range: arcsin and arctan return angles in [-π/2, π/2]; arccos returns [0, π]. Many aspirants forget these ranges and lose marks. Also, sin(arctan(x)) = x/√(1+x²) — this type of conversion is a favorite NDA trick.
- arcsin(x) returns angle in [-π/2, π/2]; arccos(x) returns angle in [0, π]; arctan(x) returns angle in (-π/2, π/2)
- sin(arctan(x)) = x/√(1+x²); cos(arctan(x)) = 1/√(1+x²); tan(arcsin(x)) = x/√(1-x²)
- arcsin(x) + arccos(x) = π/2 for all x in [-1, 1]
- arctan(x) + arctan(y) = arctan[(x+y)/(1-xy)] when xy < 1
- Domain restrictions: arcsin and arccos only defined for x in [-1, 1]; arctan defined for all real x
Key formulas
Inverse Sine-Tangent Conversion
sin(arctan(x)) = x/√(1+x²)
When: Simplifying expressions with mixed inverse functions
Complementary Inverse
arcsin(x) + arccos(x) = π/2
When: Proving identities or simplifying sums of inverse functions
Tangent Addition (Inverse)
arctan(x) + arctan(y) = arctan[(x+y)/(1-xy)]
When: Adding two arctan terms; check xy < 1 condition
Worked examples
Find sin(arctan(3/4)). Let θ = arctan(3/4), so tanθ = 3/4. In a right triangle: opposite=3, adjacent=4, hypotenuse=5. Thus sinθ = 3/5.
Simplify: arctan(1) + arctan(2) + arctan(3). Use arctan(1) + arctan(2) = arctan(3/(1-2)) = arctan(-3) = -arctan(3). So the sum = -arctan(3) + arctan(3) = 0. (This is a classic NDA trick.)
Heights & Distances (Applications)
This is the 'story problem' section of trigonometry in NDA. You're given a scenario (observer on a hill, angle of elevation/depression, distance), and must find height or distance. The method is always the same: draw a diagram, identify the right triangle, pick the correct ratio (sin, cos, or tan), and solve. NDA examiners test whether you can translate words into geometry. Common traps: confusing angle of elevation with depression, or forgetting to add/subtract initial heights.
- Angle of elevation: angle above horizontal when looking UP at an object
- Angle of depression: angle below horizontal when looking DOWN at an object
- Key insight: angle of elevation from A to B = angle of depression from B to A (alternate angles)
- Always draw a diagram first; identify the right triangle and the known/unknown sides
- Use tan(θ) = opposite/adjacent when you have horizontal and vertical distances; use sin/cos when hypotenuse is involved
Key formulas
Height from Angle of Elevation
height = distance × tan(angle of elevation)
When: Observer at ground level looking up at object; you know horizontal distance and angle
Distance from Angle of Depression
distance = height / tan(angle of depression)
When: Observer at height looking down; you know vertical height and angle
Worked examples
A man 1.5 m tall stands 20 m from a tower. The angle of elevation to the top is 60°. Find tower height. Height above man's eye = 20 × tan(60°) = 20√3 m. Total height = 20√3 + 1.5 ≈ 34.64 + 1.5 = 36.14 m.
From a cliff 100 m high, the angle of depression to a boat is 30°. Find the horizontal distance to the boat. Distance = 100 / tan(30°) = 100 / (1/√3) = 100√3 ≈ 173.2 m.
⚠ Common mistakes to avoid
- Forgetting ASTC rule: Many aspirants compute sin(120°) as -√3/2 instead of +√3/2. Remember: sine is positive in Q1 and Q2. 120° is in Q2, so sin(120°) = sin(60°) = √3/2.
- Mixing up angle of elevation and depression: Elevation is UP (positive angle above horizontal), depression is DOWN (negative angle below horizontal). A common NDA trap is to use the wrong angle in the formula.
- Incorrect range for inverse functions: arcsin(0.5) = 30° OR 150°? No — arcsin only returns [-90°, 90°], so arcsin(0.5) = 30° only. The other solution is found separately using ASTC.
- Forgetting to simplify after identity application: You correctly apply sin(A+B) but then leave the answer unsimplified. NDA expects fully simplified final answers. Always check if you can combine like terms or use another identity.
- Careless radian-degree conversion: Converting 45° to radians as 45π instead of π/4. Always divide by 180 first: 45 × (π/180) = π/4.
🧠 Memory aids
- ASTC = All Students Take Calculus (or 'All Sin Tan Cos'): Quadrant I all positive, Q2 sine positive, Q3 tangent positive, Q4 cosine positive.
- SOH-CAH-TOA = Sine = Opposite/Hypotenuse, Cosine = Adjacent/Hypotenuse, Tangent = Opposite/Adjacent. Drill this until it's automatic.
- Magic angles: 0-30-45-60-90. Their sin/cos values follow a pattern: sin goes 0, 1/2, 1/√2, √3/2, 1 (increasing); cos is reversed (decreasing). Visualize a rising and falling curve.
- Complementary angles sum to 90°: sin(θ) = cos(90°-θ). This is why sin(30°) = cos(60°). Use this to check your answers.
- Double angle = 2 × single: sin(2θ) = 2sinθ·cosθ is literally 'two times' the single angle formula. Helps you remember it's not sin(θ)·sin(θ).
🎯 NDA exam tips
- NDA Maths papers (2019-2024) show a consistent pattern: 1-2 questions on standard angle values, 2-3 on identity simplification/proof, 1-2 on inverse functions, and 1-2 on heights/distances. Total ~8-10% of paper. Prioritize identities and standard angles.
- Identity questions are almost always 'Prove that' or 'Simplify'. They test whether you can chain multiple identities together. Practice converting between sin/cos/tan forms and recognizing when to apply sum vs. double angle formulas.
- Heights and distances questions are usually straightforward IF you draw the diagram correctly. Spend 30 seconds on the diagram; it prevents 90% of errors. NDA examiners reward clear working here.
- Inverse trig questions often hide in 'find the angle' or 'simplify sin(arctan(x))' format. Know the three key conversions (sin/cos/tan of arctan, arcsin, arccos) cold. These appear almost every year.
- Time management: Trig questions are medium-difficulty. Allocate 8-10 minutes for 2-3 trig questions. If you get stuck on an identity, move on and come back; don't waste 5 minutes on one proof.
Q1 · medium · AI-verified
The value of (1 + tan 15°)/(1 - tan 15°) is:
- √3
- 1/√3
- 2 + √3
- 2 - √3
Q2 · easy · PYQ 2026
cos x + √3 sin x is maximum when x is equal to
- π/2
- π/3
- π/4
- π/6
Q3 · hard · PYQ 2026
If cos α + cos β = 0 = sin α + sin β, α ≠ β then what is a value of cos 2α + cos 2β + 2 cos(α + β)?
- 0
- 1
- 2
- 4
Q4 · medium · AI-verified
If A + B + C = 180°, then tan A/2 tan B/2 + tan B/2 tan C/2 + tan C/2 tan A/2 equals:
- 0
- 1
- -1
- 2
Q5 · medium · PYQ 2025
Let p = |sinα - sin(α - 90°)|. What is the minimum value of p?
- 0
- 1/2
- 1/√2
- 1