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Algebra Questions for SSC CGL

Free, AI-curated practice for the Algebra section of SSC CGL. We have 95+ verified questions in this bank. Below: 5 sample questions. Sign up free to unlock unlimited practice + AI explanations + per-topic analytics.

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📍 Algebra is also tested in:
CDS (39)SSC CHSL (23)SSC MTS (15)
Why this topic matters · 9 min read
Algebra is one of the highest-weightage topics in SSC CGL Quant, typically contributing 4-6 questions per paper. Questions test algebraic identities, simplification of expressions, finding values of expressions given conditions, and linear/quadratic equations. The most common pattern is: given x + 1/x = k, find x^3 + 1/x^3 or similar. Mastering the 8-10 standard identities and their derived chains is the fastest route to full marks here.

Core Algebraic Identities

These are the building blocks of almost every SSC algebra question. You will rarely need to solve from scratch — the question gives you one expression and asks for a related one. The trick is to know which identity connects them. Think of these identities as bridges: x + 1/x is the starting bridge, and x^3 + 1/x^3 is three bridges away.

  • (a + b)^2 = a^2 + 2ab + b^2
  • (a - b)^2 = a^2 - 2ab + b^2
  • (a + b)^2 - (a - b)^2 = 4ab — useful to find ab when sum and difference are given
  • (a + b)^3 = a^3 + b^3 + 3ab(a + b)
  • (a - b)^3 = a^3 - b^3 - 3ab(a - b)
  • a^3 + b^3 = (a + b)(a^2 - ab + b^2) and a^3 - b^3 = (a - b)(a^2 + ab + b^2)
Key formulas
Sum of squares
a^2 + b^2 = (a + b)^2 - 2ab
When: When a+b and ab are known, find a^2+b^2
Cube from sum
a^3 + b^3 = (a + b)^3 - 3ab(a + b)
When: When a+b and ab are known, find a^3+b^3
Cube from difference
a^3 - b^3 = (a - b)^3 + 3ab(a - b)
When: When a-b and ab are known, find a^3-b^3
Product identity
(a^2 - b^2) = (a+b)(a-b)
When: Factorisation and simplification of large numbers
Worked examples

If x + 1/x = 5, find x^3 + 1/x^3. Step 1: (x + 1/x)^2 = 25, so x^2 + 1/x^2 = 25 - 2 = 23. Step 2: x^3 + 1/x^3 = (x + 1/x)(x^2 - 1 + 1/x^2) = 5 x (23 - 1) = 5 x 22 = 110.

If x - 1/x = 3, find x^2 + 1/x^2. Step 1: (x - 1/x)^2 = 9, so x^2 - 2 + 1/x^2 = 9, giving x^2 + 1/x^2 = 11.

The x + 1/x Chain — Most Tested Pattern

SSC CGL absolutely loves this chain. Given x + 1/x = k (or x - 1/x = k), you must quickly derive x^2 + 1/x^2, x^3 + 1/x^3, and even x^4 + 1/x^4. Memorise the chain steps so you can do this in under 30 seconds. Also note: if x + 1/x = 1, then x^3 = -1 (special case from cube identity with a+b+c=0 trick).

  • x^2 + 1/x^2 = (x + 1/x)^2 - 2
  • x^2 + 1/x^2 = (x - 1/x)^2 + 2
  • x^3 + 1/x^3 = (x + 1/x)^3 - 3(x + 1/x)
  • x^3 - 1/x^3 = (x - 1/x)^3 + 3(x - 1/x)
  • x^4 + 1/x^4 = (x^2 + 1/x^2)^2 - 2 — just apply the same chain again
Key formulas
Cube shortcut +
x^3 + 1/x^3 = (x + 1/x)[(x + 1/x)^2 - 3]
When: Fastest form to use directly when x+1/x is given
Cube shortcut -
x^3 - 1/x^3 = (x - 1/x)[(x - 1/x)^2 + 3]
When: When x - 1/x is given
Worked example

If x + 1/x = 3, find x^3 + 1/x^3 directly: 3 x (9 - 3) = 3 x 6 = 18. Done in one step.

a + b + c = 0 Special Identity

If a + b + c = 0, then a^3 + b^3 + c^3 = 3abc. SSC uses this in disguised form — they give you three numbers or expressions that sum to zero and ask for the cube sum or a ratio. Always check if the three terms add to zero before doing long calculations.

  • If a + b + c = 0, then a^3 + b^3 + c^3 = 3abc — no derivation needed, just apply
  • Corollary: (a^3 + b^3 + c^3) / abc = 3 when a + b + c = 0
  • Also: a^2 + b^2 + c^2 = -2(ab + bc + ca) when a + b + c = 0
  • Check for disguised zero sums like (x-y) + (y-z) + (z-x) = 0 — always true
Key formulas
Zero sum cube
a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - bc - ca)
When: General form; when a+b+c=0, left side becomes 3abc
Worked example

Find value of (x-2)^3 + (2-y)^3 + (y-x)^3 divided by 3(x-2)(2-y)(y-x). Since (x-2)+(2-y)+(y-x)=0, numerator = 3(x-2)(2-y)(y-x). Answer = 1.

Linear Equations and Simultaneous Equations

SSC CGL occasionally tests two equations in two unknowns. The fastest methods are substitution and elimination. Do not use cross-multiplication unless you are very comfortable — it introduces sign errors. Also watch for questions where they ask for expressions like 2x + 3y rather than individual values.

  • Elimination: multiply equations to make one variable's coefficient equal, then subtract
  • If asked for x + y or 2x - y directly, sometimes adding/subtracting equations gives it without finding x and y individually
  • For ratio problems: if x:y = a:b, substitute x = ak and y = bk
  • Equations with fractions: multiply through by LCM first to clear denominators
Key formulas
Cramer shortcut
x = (b1*c2 - b2*c1)/(a1*b2 - a2*b1), y = (a2*c1 - a1*c2)/(a1*b2 - a2*b1)
When: Only use if you are fast with signs; otherwise stick to elimination
Worked example

If 2x + 3y = 12 and 3x + 2y = 13, find x + y. Add both: 5x + 5y = 25, so x + y = 5. No need to find x and y separately.

Factorisation and Simplification Tricks

Many SSC algebra questions are simplification puzzles disguised as hard problems. The moment you see a long expression, look for difference of squares, common factor, or a perfect square/cube hiding inside. These questions are meant to be solved in 40-60 seconds if you spot the pattern.

  • Always factorise before multiplying out — it saves enormous time
  • Spot perfect squares: x^2 + 6x + 9 = (x+3)^2
  • Spot difference of squares immediately: 999^2 - 1 = (999-1)(999+1) = 998 x 1000
  • For expressions like (a^2 + b^2 + c^2 - ab - bc - ca), recognise it as half of [(a-b)^2 + (b-c)^2 + (c-a)^2]
  • Cyclic expressions often cancel: (a-b)/(b-c) type chains multiply to 1 or -1
Key formulas
Symmetric square
a^2 + b^2 + c^2 - ab - bc - ca = (1/2)[(a-b)^2 + (b-c)^2 + (c-a)^2]
When: When this expression appears in numerator or denominator — it never equals zero unless a=b=c
⚠ Common mistakes to avoid
  • Forgetting to subtract 2 when squaring x + 1/x to get x^2 + 1/x^2 — the most frequent error in the chain
  • Mixing up signs: (a - b)^3 = a^3 - b^3 - 3ab(a-b), NOT plus 3ab(a-b) — the minus sign on the 3ab term trips everyone
  • Not checking if a + b + c = 0 before expanding cubes — wastes 2-3 minutes on what should be a 10-second question
  • In simultaneous equations, finding x and y individually when the question only asks for a combined expression like x + y or 3x - y
  • Treating x^2 + 1/x^2 = (x + 1/x)^2 as correct without subtracting 2 — this is the number one algebra error in SSC papers
🧠 Memory aids
  • CHAIN OF 3: +1/x gives you square (minus 2), square gives you cube (use shortcut). Remember: Minus 2 for plus, Plus 2 for minus — when squaring x plus or minus 1/x
  • ZERO SUM MAGIC: Three terms add to zero? Cube sum = 3 x product. Think of a triangle where all three sides meet at zero — power triples.
  • BRIDGE METHOD: Every algebra question is a bridge problem. x + 1/x is Bridge 1. x^2 + 1/x^2 is Bridge 2. x^3 + 1/x^3 is Bridge 3. Each bridge uses the previous one.
  • FACTORISE FIRST, CALCULATE NEVER: Before doing any arithmetic in a simplification problem, spend 5 seconds looking for a^2 - b^2 or a^3 plus/minus b^3 patterns.
🎯 SSC CGL exam tips
  • In SSC CGL Tier 1, expect 3-5 algebra questions. At least 2 will be of the x + 1/x chain type. These are free marks if you have memorised the chain — target under 45 seconds each.
  • The a + b + c = 0 identity appears almost every year in disguised form. The disguise is usually (p-q) + (q-r) + (r-p) which is always zero — this is a guaranteed 1-mark question if you recognise it.
  • Simultaneous equation questions in SSC usually have clean integer answers. If your calculation is getting messy, you have likely made a sign error — restart rather than push through.
  • Difficulty is usually easy to medium for identity-based questions. Do not spend more than 60 seconds on any single algebra question — move on and return if needed.
  • In Tier 2, algebra questions can involve longer expressions and composite identities (combining two identities). Practice questions where you need to apply two identities in sequence.

Sample questions

Q1 · medium · AI-verified
If log₂ x = 3, then find the value of x.
  1. 9
  2. 8
  3. 6
  4. 12
Q2 · medium · PYQ 2015
If 2 + x√3 = 1/(2 + √3), then x is equal to:
  1. 0
  2. -1
  3. 1
  4. 2
Q3 · medium · PYQ 2021
If x + y = −3 and xy = 3, find the value of x³ + y³ − 9xy.
  1. −22
  2. −20
  3. −16
  4. −18
Q4 · medium · PYQ 2024
If x = 1, y = 1, z = 1, which equation is satisfied?
  1. x² + y² – z² = 0
  2. x – y + z = 0
  3. xyz = 1
  4. x + y + z = 0
Q5 · medium · PYQ 2024
If the equations 4x + (k−2)y + 3 = 0 and (k−2)x + 9y − 5 = 0 (k > 0) are parallel, then find the value of k² + 6.
  1. 70
  2. 64
  3. 68
  4. 72
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