Why this topic matters · 7 min read
Simple Interest is one of the most reliable scoring topics in SSC CGL Quant. It appears in 1-2 questions almost every year, often combined with comparisons to Compound Interest or problems involving installments and time reversal. The difficulty is low to medium, making it a must-score area. Questions test your ability to rearrange the SI formula, find the rate when principal and time change, and decode tricky word problems where the interest equals a fraction of the principal.
Core Formula and Variables
Simple Interest grows in a straight line. Every year the same fixed interest is added on the original principal only — unlike compound interest which snowballs. The four variables are Principal (P), Rate (R% per annum), Time (T in years), and Interest (SI). If you know any three, you can find the fourth by simple algebra.
- SI = (P x R x T) / 100
- Amount A = P + SI = P(1 + RT/100)
- P = (SI x 100) / (R x T)
- R = (SI x 100) / (P x T)
- T = (SI x 100) / (P x R)
- Rate and Time are always in matching units — both per annum, or both per month
Key formulas
Simple Interest
SI = (P x R x T) / 100
When: Use whenever interest, principal, rate, or time is unknown — rearrange as needed
Amount
A = P + SI
When: Use when the question gives or asks for total amount repaid
Rate from SI fraction
If SI = (x/y) of P, then R x T = (x/y) x 100
When: Use when interest is given as a fraction or percentage of principal
Worked examples
A sum of Rs 4000 is lent at 5% per annum for 3 years. SI = (4000 x 5 x 3)/100 = Rs 600. Amount = 4000 + 600 = Rs 4600.
A sum doubles in 10 years at SI. Find rate. If P doubles, SI = P. So P = (P x R x 10)/100 => R = 10% per annum.
Sum Doubles, Triples, N-Times
A very common SSC CGL pattern asks: at what rate does a sum double in X years, or in how many years does it triple at Y%. The logic is simple — if a sum doubles, SI earned = P itself. If it triples, SI = 2P. Once you know SI as a multiple of P, plug into the formula and cancel P.
- Sum doubles => SI = P => R x T = 100
- Sum triples => SI = 2P => R x T = 200
- Sum becomes N times => SI = (N-1)P => R x T = (N-1) x 100
- If rate doubles and time halves, SI stays the same
- Time to double at 10% = 100/10 = 10 years — quick mental calculation
Key formulas
N-times rule
R x T = (N - 1) x 100
When: When a sum becomes N times itself under SI — most direct shortcut
Worked examples
A sum triples at 8% SI. In how many years? R x T = (3-1) x 100 = 200. T = 200/8 = 25 years.
In how many years does Rs 5000 become Rs 8000 at 6% SI? SI = 3000. T = (3000 x 100)/(5000 x 6) = 10 years.
Effect of Changing P, R, or T
SSC CGL loves questions where two conditions are given simultaneously — same principal at two different rates or times — and you must find an unknown. Treat each condition as a separate SI equation and set them equal or subtract them. This gives you a system of two equations with two unknowns.
- Write condition 1: SI1 = (P x R1 x T1)/100
- Write condition 2: SI2 = (P x R2 x T2)/100
- Subtract or divide to eliminate P or find R
- If same P and T, ratio of SI = ratio of R
- If same P and R, ratio of SI = ratio of T
Key formulas
Two-rate difference shortcut
Difference in SI = P x (R1 - R2) x T / 100
When: When same sum is lent at two rates for same time and the difference in interest is given
Worked example
The SI on a sum for 2 years at 4% is Rs 80 less than SI at 6% for same time. Find P. Difference = P x (6-4) x 2/100 = 80 => 4P/100 = 80 => P = Rs 2000.
SI vs CI Connection
A popular hybrid question compares SI and CI on the same principal for 2 years. For 2 years: CI - SI = P(R/100)^2. This is a fixed formula to memorise. For 3 years the gap is bigger but SSC rarely tests beyond 2 years in this format. If you know SI for 2 years, CI = SI + P(R/100)^2.
- For 2 years: CI - SI = P x (R/100)^2
- SI for 2 years = 2 x (annual SI)
- CI is always greater than or equal to SI for same P, R, T
- If CI - SI is given along with R, you can find P directly
Key formulas
CI minus SI (2 years)
CI - SI = P x (R/100)^2
When: When question gives both CI and SI for 2 years on same sum and asks for P or R
Worked example
CI and SI on a sum for 2 years at 10% differ by Rs 50. Find P. 50 = P x (10/100)^2 = P x 0.01 => P = Rs 5000.
⚠ Common mistakes to avoid
- Using A (Amount) instead of SI in the formula — always check whether the question gives total amount or only the interest earned
- Forgetting to convert months to years — if T is given as 6 months, use T = 0.5 in the formula
- In N-times problems, forgetting that SI = (N-1)P not NP — the principal itself is not interest
- Mixing up CI-SI formula direction — CI is always larger; if you get a negative answer you have flipped it
- Assuming rate is per month when it is stated per annum — always re-read the unit of rate
🧠 Memory aids
- PRT formula: Think PART — P-A-R-T, just replace A with nothing and divide by 100. Principal, Rate, Time over 100 gives SI.
- N-times rule memory hook: Extras times Hundred — (N-1) x 100 = R x T. The N-1 is the EXTRA beyond your original sum.
- Doubles at 10% in 10 years, at 5% in 20 years — inverse relationship: Rate x Years = 100 always for doubling.
- CI vs SI gap for 2 years: gap is P times Rate-fraction squared — imagine the rate fraction biting itself once extra.
🎯 SSC CGL exam tips
- SSC CGL Tier 1 typically has 1-2 SI questions, occasionally a hybrid SI-CI question. Tier 2 Maths can have 2-3 questions with slightly more complex multi-part conditions.
- The most common formats in recent papers: sum doubles/triples, difference in SI under two rates, and finding principal when SI is a given fraction of principal.
- Time-saving trick: for straight formula questions, set up the equation mentally and avoid writing intermediate steps — these should take under 45 seconds each.
- Hybrid SI-CI questions for 2 years are a safe trap — examiners give Amount instead of SI to confuse you. Extract SI first before using any formula.
- If you see SI = (1/5) of P or similar fraction language, immediately convert: R x T = 20. Do not expand the full equation — use the shortcut R x T = fraction x 100.
Q1 · medium · AI-verified
A sum of ₹5,000 is invested at a simple interest rate of 8% per annum. What will be the interest earned after 3 years?
- ₹1,400
- ₹1,500
- ₹1,000
- ₹1,200
Q2 · medium · PYQ 2024
Sohan borrows a sum of ₹1,41,545 at the rate of 11% per annum simple interest. At the end of the first year, he repays ₹25,490 towards return of principal amount borrowed. If Sohan clears all pending dues at the end of the second year, including interest payment that accrued during the first year, how much does he pay (in ₹) at the end of the second year?
- 1,41,222
- 1,36,453
- 1,44,391
- 1,37,407
Q3 · hard · AI-verified
The simple interest on a certain sum for 3 years at 10% per annum is ₹300 less than the simple interest on the same sum for 5 years at 8% per annum. Find the principal.
- ₹7,500
- ₹3,000
- ₹6,000
- ₹4,500
Q4 · medium · AI-verified
A sum doubles itself in 10 years at simple interest. In how many years will it become 4 times?
- 40 years
- 25 years
- 20 years
- 30 years
Q5 · medium · AI-verified
At simple interest, the ratio of amount after 5 years to the principal is 3:2. What is the rate of interest per annum?
- 15%
- 10%
- 20%
- 12%