Why this topic matters · 7 min read
Simple Interest is one of the most reliable scoring topics in SSC CGL Quant. It appears in 1-2 questions almost every year, often combined with comparisons to Compound Interest or problems involving installments and time reversal. The difficulty is low to medium, making it a must-score area. Questions test your ability to rearrange the SI formula, find the rate when principal and time change, and decode tricky word problems where the interest equals a fraction of the principal.
Core Formula and Variables
Simple Interest grows in a straight line. Every year the same fixed interest is added on the original principal only — unlike compound interest which snowballs. The four variables are Principal (P), Rate (R% per annum), Time (T in years), and Interest (SI). If you know any three, you can find the fourth by simple algebra.
- SI = (P x R x T) / 100
- Amount A = P + SI = P(1 + RT/100)
- P = (SI x 100) / (R x T)
- R = (SI x 100) / (P x T)
- T = (SI x 100) / (P x R)
- Rate and Time are always in matching units — both per annum, or both per month
Key formulas
Simple Interest
SI = (P x R x T) / 100
When: Use whenever interest, principal, rate, or time is unknown — rearrange as needed
Amount
A = P + SI
When: Use when the question gives or asks for total amount repaid
Rate from SI fraction
If SI = (x/y) of P, then R x T = (x/y) x 100
When: Use when interest is given as a fraction or percentage of principal
Worked examples
A sum of Rs 4000 is lent at 5% per annum for 3 years. SI = (4000 x 5 x 3)/100 = Rs 600. Amount = 4000 + 600 = Rs 4600.
A sum doubles in 10 years at SI. Find rate. If P doubles, SI = P. So P = (P x R x 10)/100 => R = 10% per annum.
Sum Doubles, Triples, N-Times
A very common SSC CGL pattern asks: at what rate does a sum double in X years, or in how many years does it triple at Y%. The logic is simple — if a sum doubles, SI earned = P itself. If it triples, SI = 2P. Once you know SI as a multiple of P, plug into the formula and cancel P.
- Sum doubles => SI = P => R x T = 100
- Sum triples => SI = 2P => R x T = 200
- Sum becomes N times => SI = (N-1)P => R x T = (N-1) x 100
- If rate doubles and time halves, SI stays the same
- Time to double at 10% = 100/10 = 10 years — quick mental calculation
Key formulas
N-times rule
R x T = (N - 1) x 100
When: When a sum becomes N times itself under SI — most direct shortcut
Worked examples
A sum triples at 8% SI. In how many years? R x T = (3-1) x 100 = 200. T = 200/8 = 25 years.
In how many years does Rs 5000 become Rs 8000 at 6% SI? SI = 3000. T = (3000 x 100)/(5000 x 6) = 10 years.
Effect of Changing P, R, or T
SSC CGL loves questions where two conditions are given simultaneously — same principal at two different rates or times — and you must find an unknown. Treat each condition as a separate SI equation and set them equal or subtract them. This gives you a system of two equations with two unknowns.
- Write condition 1: SI1 = (P x R1 x T1)/100
- Write condition 2: SI2 = (P x R2 x T2)/100
- Subtract or divide to eliminate P or find R
- If same P and T, ratio of SI = ratio of R
- If same P and R, ratio of SI = ratio of T
Key formulas
Two-rate difference shortcut
Difference in SI = P x (R1 - R2) x T / 100
When: When same sum is lent at two rates for same time and the difference in interest is given
Worked example
The SI on a sum for 2 years at 4% is Rs 80 less than SI at 6% for same time. Find P. Difference = P x (6-4) x 2/100 = 80 => 4P/100 = 80 => P = Rs 2000.
SI vs CI Connection
A popular hybrid question compares SI and CI on the same principal for 2 years. For 2 years: CI - SI = P(R/100)^2. This is a fixed formula to memorise. For 3 years the gap is bigger but SSC rarely tests beyond 2 years in this format. If you know SI for 2 years, CI = SI + P(R/100)^2.
- For 2 years: CI - SI = P x (R/100)^2
- SI for 2 years = 2 x (annual SI)
- CI is always greater than or equal to SI for same P, R, T
- If CI - SI is given along with R, you can find P directly
Key formulas
CI minus SI (2 years)
CI - SI = P x (R/100)^2
When: When question gives both CI and SI for 2 years on same sum and asks for P or R
Worked example
CI and SI on a sum for 2 years at 10% differ by Rs 50. Find P. 50 = P x (10/100)^2 = P x 0.01 => P = Rs 5000.
⚠ Common mistakes to avoid
- Using A (Amount) instead of SI in the formula — always check whether the question gives total amount or only the interest earned
- Forgetting to convert months to years — if T is given as 6 months, use T = 0.5 in the formula
- In N-times problems, forgetting that SI = (N-1)P not NP — the principal itself is not interest
- Mixing up CI-SI formula direction — CI is always larger; if you get a negative answer you have flipped it
- Assuming rate is per month when it is stated per annum — always re-read the unit of rate
🧠 Memory aids
- PRT formula: Think PART — P-A-R-T, just replace A with nothing and divide by 100. Principal, Rate, Time over 100 gives SI.
- N-times rule memory hook: Extras times Hundred — (N-1) x 100 = R x T. The N-1 is the EXTRA beyond your original sum.
- Doubles at 10% in 10 years, at 5% in 20 years — inverse relationship: Rate x Years = 100 always for doubling.
- CI vs SI gap for 2 years: gap is P times Rate-fraction squared — imagine the rate fraction biting itself once extra.
🎯 SSC CGL exam tips
- SSC CGL Tier 1 typically has 1-2 SI questions, occasionally a hybrid SI-CI question. Tier 2 Maths can have 2-3 questions with slightly more complex multi-part conditions.
- The most common formats in recent papers: sum doubles/triples, difference in SI under two rates, and finding principal when SI is a given fraction of principal.
- Time-saving trick: for straight formula questions, set up the equation mentally and avoid writing intermediate steps — these should take under 45 seconds each.
- Hybrid SI-CI questions for 2 years are a safe trap — examiners give Amount instead of SI to confuse you. Extract SI first before using any formula.
- If you see SI = (1/5) of P or similar fraction language, immediately convert: R x T = 20. Do not expand the full equation — use the shortcut R x T = fraction x 100.
Q1 · medium · AI-verified
At what rate of simple interest per annum will ₹8,000 amount to ₹10,400 in 5 years?
- 8%
- 5%
- 6%
- 7%
Q2 · hard · AI-verified
A sum of money at simple interest amounts to ₹8,150 in 3 years and ₹9,800 in 6 years. What is the principal amount?
- ₹7,000
- ₹6,500
- ₹7,500
- ₹6,000
Q3 · medium · AI-verified
The simple interest on a sum of money is 1/4 of the principal and the number of years equals the rate percent per annum. Find the rate of interest.
- 6%
- 5%
- 7%
- 4%
Q4 · medium · PYQ 2024
SI₁ is calculated on ₹8000 at 12% per annum for 4 years. SI₂ is calculated on ₹5000 at 15% per annum for 3 years. Find the difference between SI₁ and SI₂.
- ₹1390
- ₹1690
- ₹1490
- ₹1590
Q5 · hard · AI-verified
The simple interest on a certain sum for 3 years at 10% per annum is ₹300 less than the simple interest on the same sum for 5 years at 8% per annum. Find the principal.
- ₹7,500
- ₹3,000
- ₹6,000
- ₹4,500