Why this topic matters · 7 min read
Simple Interest is one of the most regularly tested topics in SSC CHSL Quant. Expect 1-2 direct questions every paper. Questions range from finding SI or Rate or Time, to comparing SI with CI (compound interest), to problems where principal doubles or triples. Difficulty is low to medium — a strong candidate should solve these in under 60 seconds each. Missing this topic means losing easy marks.
Core Formula and Variables
Simple Interest is the extra money paid on a borrowed or invested amount, calculated only on the original principal — not on interest earned. Unlike compound interest, the base never changes. There are four variables: Principal (P), Rate (R), Time (T), and Simple Interest (SI). Know any three, find the fourth.
- Principal (P) = original amount deposited or borrowed
- Rate (R) = interest per year, expressed as a percentage
- Time (T) = duration in years
- SI = extra amount earned or paid
- Amount (A) = P + SI — this is what the person finally receives or repays
- Rate is always per annum (yearly) unless the question specifically says otherwise
Key formulas
Simple Interest
SI = (P x R x T) / 100
When: Use when you need to find interest earned. The 100 in denominator is because R is a percentage.
Principal from SI
P = (SI x 100) / (R x T)
When: Use when SI is given and P is unknown
Rate from SI
R = (SI x 100) / (P x T)
When: Use when rate is unknown and all other values are given
Time from SI
T = (SI x 100) / (P x R)
When: Use when time period is unknown
Amount
A = P + SI = P (1 + RT/100)
When: Use when the question asks for the final amount, not just interest
Worked examples
Example 1: P = 5000, R = 8%, T = 3 years. SI = (5000 x 8 x 3)/100 = 120000/100 = 1200. Amount = 5000 + 1200 = 6200.
Example 2: SI = 600, T = 4 years, R = 5%. Find P. P = (600 x 100)/(5 x 4) = 60000/20 = 3000.
Principal Doubles, Triples — Pattern Questions
SSC CHSL frequently asks: at what rate will a sum double in N years, or in how many years will a sum triple at R percent. These are shortcut-friendly questions. The key insight is: if a sum doubles, SI equals the principal (SI = P). If it triples, SI = 2P. Use this to set up the formula quickly.
- Sum doubles means A = 2P, so SI = P
- Sum triples means A = 3P, so SI = 2P
- Sum becomes N times means SI = (N-1) x P
- Time to double at R% = 100/R years
- Rate to double in T years = 100/T percent
- These shortcuts save 30-40 seconds per question
Key formulas
Time to become N times
T = (N - 1) x 100 / R
When: When question says sum becomes N times at rate R. Very common in SSC CHSL.
Rate to become N times
R = (N - 1) x 100 / T
When: When question gives time and asks what rate makes sum N times.
Worked examples
Example: A sum doubles in 8 years. Find rate. SI = P, so P = (P x R x 8)/100 => R = 100/8 = 12.5% per annum.
Example: At 6% per annum, in how many years does a sum triple? SI = 2P. 2P = (P x 6 x T)/100 => T = 200/6 = 33.33 years.
Two Installments or Two Parts of Principal
A common SSC CHSL pattern gives a total principal split into two parts, lent at different rates or for different times, and asks for either the split or the total interest. Set up two separate SI expressions and use the total interest as the equation to solve. This tests algebraic thinking but stays simple.
- Let one part be x, then the other part is (P - x)
- Write SI for each part separately
- Add both SIs and equate to total interest given
- Solve for x using basic algebra
- These questions may look scary but they collapse into a one-variable equation quickly
- Check: rates or times must be different, else the question makes no sense
Key formulas
Two-part SI equation
(x x R1 x T)/100 + ((P-x) x R2 x T)/100 = Total SI
When: When P is split into two parts at different rates for same time T
Worked example
Example: Rs 4000 split into two parts. One part at 5%, another at 8% for 2 years. Total SI = 520. Let first part = x. (x x 5 x 2)/100 + ((4000-x) x 8 x 2)/100 = 520. 10x/100 + (64000 - 16x)/100 = 520. 10x + 64000 - 16x = 52000. -6x = -12000. x = 2000. So parts are 2000 and 2000.
SI vs CI — Difference Questions
SSC CHSL often asks the difference between CI and SI for 2 years or 3 years. For 2 years, the difference has a neat formula. These questions mix SI and CI concepts but only the difference formula is needed — you do not need to calculate CI from scratch. Memorise the two-year difference formula as a shortcut.
- For 2 years: CI - SI = P x (R/100)^2
- For 3 years: CI - SI = P x (R/100)^2 x (R/100 + 3)
- The 2-year formula is far more common in SSC CHSL
- This difference is always positive — CI is always more than SI
- If SI for 2 years is given, derive P x R / 100 first, then use in CI-SI formula
Key formulas
CI minus SI for 2 years
Difference = P x (R/100)^2
When: When question asks how much more CI is than SI over 2 years at same rate
Worked example
Example: P = 10000, R = 10%, 2 years. SI = 2000. CI - SI = 10000 x (10/100)^2 = 10000 x 0.01 = 100. So CI = 2100.
⚠ Common mistakes to avoid
- Using months directly in the formula: Time must be in years. If T = 6 months, use T = 0.5 or T = 6/12 before applying the formula.
- Confusing Amount with Interest: The question may ask for Amount (P + SI) but you stop at SI. Always re-read the question last line.
- Forgetting to subtract 1 in the N-times formula: If sum triples, SI = 2P (not 3P). N-1 is the multiplier for SI, not N.
- Treating rate as decimal in formula: The formula already divides by 100, so enter R as a number like 8, not as 0.08.
- In two-part problems, setting up one equation but solving incorrectly by mixing up which rate belongs to which part: Always label clearly as Part 1 = x at R1, Part 2 = (Total - x) at R2.
🧠 Memory aids
- PRT formula mnemonic: Remember it as PARTY — P-A-R-T-Y where A = amount, the goal of every party (investment). SI = (P x R x T)/100.
- Doubles rule: Think of 100 as a wall. Rate x Time must hit 100 to double the money. R x T = 100 to double.
- N-times shortcut: Subtract 1 from N, then use T = (N-1) x 100 / R. Think: subtract before you multiply.
- CI - SI for 2 years: Think of it as the interest-on-interest for one year. CI earns extra interest on the first year SI. That extra = P x (R/100)^2.
🎯 SSC CHSL exam tips
- SSC CHSL typically has 1-2 SI questions per paper. They are placed in the easy-to-medium band — solve them in under 75 seconds each to save time for harder topics.
- The most common question types in recent papers: finding rate when sum doubles in N years, finding total amount after given years, and the CI-SI difference for 2 years.
- Questions rarely go beyond 3-variable problems. If a question looks complex, check whether values simplify nicely — they usually do in CHSL.
- Watch for unit traps: rate given as half-yearly or monthly. Convert everything to yearly before applying the standard formula.
- In the two-part split questions, if answer choices are round numbers like 1000, 1500, 2000, plug those back instead of solving algebra — saves time in exam hall.
Q1 · medium · PYQ 2024
In how many years will the simple interest on a sum of money be equal to the principal at the rate of 2(6/7)% per annum?
- 33 years
- 37 years
- 35 years
- 34 years
Q2 · medium · AI-verified
In how many years will ₹3600 amount to ₹4680 at 7.5% per annum simple interest?
- 4 years
- 3 years
- 5 years
- 2 years
Q3 · medium · AI-verified
In how many years will Rs. 3,600 become Rs. 4,320 at 10% per annum simple interest?
- 2 years
- 3 years
- 2.5 years
- 1.5 years
Q4 · medium · AI-verified
A man invests ₹12,000 at 8% simple interest and ₹15,000 at 10% simple interest. What is his total income after 2 years?
- ₹4,920
- ₹4,800
- ₹5,100
- ₹4,680
Q5 · medium · AI-verified
Two equal sums are lent at 6% and 8% simple interest respectively for 3 years. If the difference in interests is ₹180, find each sum.
- ₹3,000
- ₹2,500
- ₹3,500
- ₹4,000