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Age Problems Questions for SSC MTS

Free, AI-curated practice for the Age Problems section of SSC MTS. We have 18+ verified questions in this bank. Below: 5 sample questions. Sign up free to unlock unlimited practice + AI explanations + per-topic analytics.

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📍 Age Problems is also tested in:
SSC CGL (10)
Why this topic matters · 7 min read
Age problems appear in 1-2 questions per SSC MTS paper, usually in Arithmetic section. They test your ability to set up equations from word clues and solve linear equations. Typical patterns: ratio of ages, age after/before certain years, sum/difference of ages. These are scoring questions if you avoid careless mistakes in equation setup.

Core Concept: Translating Words to Equations

Age problems are really just algebra disguised in story form. The key skill is converting English statements into mathematical equations. When you read 'A is 5 years older than B', that means A = B + 5. When you read 'In 3 years, A will be twice B's age', that means A + 3 = 2(B + 3). The trick is to identify the reference point (now, past, future) and write equations carefully. Always define your variables clearly at the start: let A's current age = x, let B's current age = y. This prevents confusion.

  • Define variables for current ages first, not future or past ages
  • Identify the time reference: 'now', 'x years ago', 'in y years'
  • Translate 'is' to '=', 'older/younger' to '+/-', 'times' to multiplication
  • Set up at least 2 equations if 2 people are involved; 3 equations for 3 people
  • Solve the system and verify by substituting back into the original statement
Key formulas
Age difference is constant
A_now - B_now = A_past - B_past = A_future - B_future
When: Use this to link ages across different time periods. Age gap never changes.
Ratio of ages at different times
(A + n) / (B + n) = p / q
When: When problem states 'in n years, ratio will be p:q'. Solve for current ages.
Worked examples

Example 1: A is 8 years older than B. In 4 years, A will be twice B's age. Find current ages. | Let B = x, A = x + 8. In 4 years: (x + 8 + 4) = 2(x + 4) => x + 12 = 2x + 8 => x = 4. So B = 4, A = 12. Check: In 4 years, A = 16, B = 8, and 16 = 2 × 8. Correct.

Example 2: The ratio of A's age to B's age is 5:3. After 10 years, the ratio will be 3:2. Find their current ages. | Let A = 5k, B = 3k. After 10 years: (5k + 10)/(3k + 10) = 3/2 => 2(5k + 10) = 3(3k + 10) => 10k + 20 = 9k + 30 => k = 10. So A = 50, B = 30. Check: After 10 years, A = 60, B = 40, ratio = 60:40 = 3:2. Correct.

Common Problem Types in SSC MTS

SSC MTS repeats certain age problem patterns. Knowing these patterns helps you recognize the setup instantly. The most common are: (1) Simple difference problems where one person is a fixed number of years older; (2) Ratio problems where ages are in a given ratio now or will be in future; (3) Sum problems where total age of two or more people is given; (4) Product/multiple problems where one age is a multiple of another. Each type has a standard equation setup.

  • Type 1 (Difference): A = B + k, plus one more condition about future/past
  • Type 2 (Ratio): A:B = p:q, plus condition about ratio after n years
  • Type 3 (Sum): A + B = S, plus ratio or difference condition
  • Type 4 (Multiple): A = m × B, plus condition about future age
  • Always check: Does your answer make sense? Are ages positive? Does it satisfy all conditions?

Tricky Scenarios: Three People & Reverse Problems

Harder SSC MTS questions involve three family members (father, mother, child) or ask you to work backwards from a future state. With three people, you need three independent equations. For reverse problems, you're given future/past ages and asked to find current ages — just rearrange your equation. Example: 'In 5 years, A will be 25' means A is currently 20. These aren't harder mathematically, just require careful reading.

  • Three-person problems: Set up 3 equations, solve systematically (substitution or elimination)
  • Reverse problems: Subtract years if going backward, add if going forward
  • Family problems often mix: father is twice son's age now, and in 10 years will be 1.5 times
  • Watch for 'at that time' — it refers to the same future/past year for all people
  • Sanity check: Father should be older than son; ages should be realistic
⚠ Common mistakes to avoid
  • Forgetting to apply the time shift to BOTH people. If A is x + 8 now, then in 3 years A is x + 11, not x + 8 + 3. You must add 3 to the current age expression.
  • Mixing up 'A is twice B' (A = 2B) with 'A is twice as old as B was 5 years ago' (A = 2(B - 5)). The second one has a time reference inside the equation.
  • Setting up ratio equations wrong. If ratio is 5:3, write 5k and 3k for current ages, not 5 and 3 directly. Otherwise you lose the scaling.
  • Not checking the answer. Always substitute back into the original statement. If it doesn't work, your algebra is wrong.
  • Assuming age must be a whole number. In SSC MTS, ages can be fractional (e.g., 12.5 years), though rare. Don't reject an answer just because it's not an integer.
🧠 Memory aids
  • AGE GAP NEVER CHANGES: No matter what year you're in, the difference between two people's ages stays the same. Use this to jump between time periods.
  • DEFINE NOW, SOLVE NOW: Always define variables as current ages. Don't define future ages as variables — that makes equations messy.
  • RATIO = k MULTIPLIER: When you see a ratio like 5:3, immediately think 5k and 3k. This is the universal way to handle ratio problems.
  • TRANSLATE CAREFULLY: 'In n years' means add n to current age. 'n years ago' means subtract n. 'Will be' means future equation. 'Was' means past equation.
🎯 SSC MTS exam tips
  • SSC MTS typically asks 1-2 age problems in the 40-minute Quant section. They're usually in the first 10 questions, so treat them as quick wins. Spend max 3-4 minutes per problem.
  • Recent papers show a preference for ratio-based age problems over simple difference problems. Practice converting 'ratio will be p:q after n years' into equations.
  • Watch for multi-step problems: 'A is 5 years older than B. In 3 years, A will be 1.5 times B's age.' These need two equations but are still solvable in under 3 minutes if you're organized.
  • No calculator needed — all answers are clean integers or simple fractions. If your answer is messy (like 7.33), you've made an error. Recheck your equation setup.
  • Family-based problems (father-son, mother-daughter) are common. The logic is identical to A-B problems, just with real-world context. Don't overthink the story.

Sample questions

Q1 · medium · PYQ 2025
Father's age 3 years ago from present was 5 times the age of his son 6 years ago from present. Son's age after 7 years from present is 20 years. What is the ratio of present ages of father and son?
  1. 37:10
  2. 28:11
  3. 13:10
  4. 38:13
Q2 · medium · PYQ 2025
The ratio of present ages of P and Q is 2 : 7. P is 5 years younger than Q. What is the present age of Q?
  1. 5 years
  2. 8 years
  3. 7 years
  4. 2 years
Q3 · medium · PYQ 2014
The ratio of the ages of A, B and C is 5 : 8 : 9. If the sum of the ages of A and C is 56 years, the age of B will be
  1. 12 years
  2. 23 years
  3. 21 years
  4. 32 years
Q4 · medium · PYQ 2018
The present age of Manoj is twice the sum of the ages of his two children. After 20 years, the age of Manoj will become equal to the sum of the ages of his two children. What is the present age of Manoj?
  1. 35 years
  2. 30 years
  3. 36 years
  4. 40 years
Q5 · medium · PYQ 2025
Sum of the ages of 3 children born at interval of 5 years is 30 years. What is the age of the youngest child?
  1. 5 years
  2. 9 years
  3. 3 years
  4. 7 years
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