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Speed, Distance and Time Questions for SSC MTS

Free, AI-curated practice for the Speed, Distance and Time section of SSC MTS. We have 18+ verified questions in this bank. Below: 5 sample questions. Sign up free to unlock unlimited practice + AI explanations + per-topic analytics.

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📍 Speed, Distance and Time is also tested in:
SSC CHSL (11)UP POLICE CONSTABLE (10)
Why this topic matters · 8 min read
Speed, Distance and Time is a regular fixture in SSC MTS Quant. Expect 2-3 questions per paper. Questions are mostly straightforward: finding speed or time, trains crossing each other or a platform, boats and streams, and average speed problems. Difficulty is low to moderate. A candidate who knows the core formula and its variations can solve these in under 60 seconds each.

The Core Triangle

Everything in this topic comes from one simple relationship: Distance equals Speed multiplied by Time. Think of it as a triangle where D is at the top and S and T are at the bottom. Cover the one you want to find and the remaining two tell you the operation. This is your starting point for every problem in this chapter.

  • Distance = Speed x Time
  • Speed = Distance divided by Time
  • Time = Distance divided by Speed
  • If speed increases, time decreases for the same distance (inverse relationship)
  • Units must match: km with hours, metres with seconds
Key formulas
Core Formula
D = S x T
When: Use always as the base. Rearrange for S or T as needed.
Unit Conversion km/h to m/s
m/s = km/h x (5/18)
When: When problem mixes km and metres, convert km/h to m/s first.
Unit Conversion m/s to km/h
km/h = m/s x (18/5)
When: When answer is needed in km/h but speed was in m/s.
Worked examples

A car travels 240 km in 4 hours. Speed = 240/4 = 60 km/h. Simple direct formula.

A person walks at 5 m/s. In km/h that is 5 x (18/5) = 18 km/h.

Average Speed

This is the most common trap in SSC MTS. When someone travels the same distance at two different speeds, average speed is NOT the simple average of the two. You must use the harmonic mean formula. Think of it this way: you spend more time at the slower speed, so it drags the average down more than the faster speed pulls it up.

  • Average Speed = Total Distance divided by Total Time
  • For same distance at two speeds: Avg Speed = 2ab divided by (a+b)
  • Never just add speeds and divide by 2 for equal distances
  • If distances are different, calculate total distance and total time separately, then divide
Key formulas
Average Speed (equal distances)
Avg Speed = 2ab / (a + b)
When: When a person covers the same distance at speed a and then at speed b.
Average Speed (general)
Avg Speed = Total Distance / Total Time
When: When distances or times are different. Always safe to use this.
Worked examples

Ravi goes from A to B at 40 km/h and returns at 60 km/h. Average speed = 2x40x60/(40+60) = 4800/100 = 48 km/h. NOT 50 km/h.

If a man travels 60 km at 20 km/h and 40 km at 40 km/h. Total time = 60/20 + 40/40 = 3 + 1 = 4 hours. Total distance = 100 km. Avg speed = 100/4 = 25 km/h.

Trains Problems

Train questions are very common in SSC MTS. The key concept is that a train has length, so it does not just pass a point, it passes its own entire body. When a train crosses a pole or a person, the distance covered equals the length of the train. When a train crosses a platform, the distance equals length of train plus length of platform. When two trains cross each other, add their lengths and use relative speed.

  • Train crosses a pole or person: Distance = Length of train
  • Train crosses a platform: Distance = Length of train + Length of platform
  • Two trains moving in same direction: Relative Speed = Difference of speeds
  • Two trains moving in opposite direction: Relative Speed = Sum of speeds
  • Always convert speed to m/s when length is in metres
Key formulas
Train crossing platform
Time = (Length of Train + Length of Platform) / Speed
When: When a train fully crosses a platform or bridge.
Relative Speed (opposite)
Relative Speed = S1 + S2
When: Two trains or objects moving toward each other.
Relative Speed (same direction)
Relative Speed = S1 - S2
When: Two trains moving in the same direction, faster one overtaking.
Worked examples

A 200 m train at 72 km/h crosses a 300 m platform. Speed in m/s = 72 x 5/18 = 20 m/s. Time = (200+300)/20 = 500/20 = 25 seconds.

Two trains 100 m and 150 m long run at 60 km/h and 40 km/h toward each other. Relative speed = 100 km/h = 100 x 5/18 = 250/9 m/s. Time = 250/(250/9) = 9 seconds.

Boats and Streams

A boat in water is affected by the current. When the boat goes with the current (downstream), current adds to its speed. When it goes against the current (upstream), current reduces its speed. Think of it like cycling with wind vs against wind. SSC MTS usually asks to find the speed of boat or stream when upstream and downstream speeds are given.

  • Downstream speed = Boat speed + Stream speed
  • Upstream speed = Boat speed - Stream speed
  • Speed of Boat in still water = (Downstream + Upstream) / 2
  • Speed of Stream = (Downstream - Upstream) / 2
  • Downstream is always faster than upstream
Key formulas
Boat speed in still water
Boat Speed = (D + U) / 2
When: When downstream speed D and upstream speed U are given.
Stream speed
Stream Speed = (D - U) / 2
When: To find how fast the river current flows.
Worked example

A boat goes 20 km/h downstream and 12 km/h upstream. Boat speed = (20+12)/2 = 16 km/h. Stream speed = (20-12)/2 = 4 km/h.

⚠ Common mistakes to avoid
  • Using simple average for average speed when distances are equal: the correct formula is 2ab/(a+b), not (a+b)/2. This trap appears often.
  • Forgetting to add the length of the platform to the train length when calculating crossing time. Students only use train length and get the wrong answer.
  • Not converting units: mixing km/h and metres. Always check if speed and distance are in matching units before calculating.
  • In boats and streams, confusing which formula gives boat speed and which gives stream speed. Remember: Add for boat (average), Subtract for stream (difference), both divided by 2.
  • In two-train problems, forgetting to use relative speed. Students use just one train's speed and get wrong time.
🧠 Memory aids
  • DST Triangle: Draw a triangle with D on top. Cover D to get S x T. Cover S to get D/T. Cover T to get D/S. Always works.
  • 5/18 and 18/5: To go from km/h to m/s, multiply by 5/18 (you are going smaller, so smaller fraction). To go from m/s to km/h, multiply by 18/5 (you are going bigger, so bigger fraction).
  • Boats memory hook: DS = Downstream is Sum (B+S), US = Upstream is subtraction (B-S). DS and US are also short forms that remind you add or subtract.
  • Same direction trains: think of a faster car trying to overtake a slower car on a highway, they close in slowly so relative speed is the difference. Opposite direction: head-on, they close fast, so relative speed is the sum.
🎯 SSC MTS exam tips
  • SSC MTS typically asks 2-3 questions from this chapter. Average speed and train crossing a platform are the two highest frequency question types. Prioritize these.
  • Questions are mostly one-step or two-step. If your calculation goes beyond 3 steps, you are likely overcomplicating it. Re-read the question.
  • Unit conversion is tested indirectly. A question may give speed in km/h and distance in metres without telling you to convert. Always check units first.
  • Boats and streams questions in SSC MTS are usually direct formula plugging: downstream and upstream given, find boat or stream speed. Rarely more complex than this.
  • Time yourself: each SDT question should take 45-60 seconds. If you practice the triangle and unit conversion till they are automatic, this chapter is free marks.

Sample questions

Q1 · medium · PYQ 2025
A car travels at a speed of 100 km/hr and covers a particular distance in 2 hours 30 minutes. How much time (in hours) will another car travelling at the speed of 50 km/hr take to cover the same distance?
  1. 6
  2. 5
  3. 4
  4. 3
Q2 · medium · PYQ 2021
A man rows downstream at a speed of 15 km/h and upstream at 11 km/h. Find his speed in still water and the speed of the current, respectively. [Give both your answers in km/h]
  1. 13 : 2
  2. 13 : 6
  3. 11 : 4
  4. 13 : 5
Q3 · hard · AI-verified
A train covers 360 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less to cover the same distance. Find the original speed of the train.
  1. 35 km/h
  2. 50 km/h
  3. 40 km/h
  4. 45 km/h
Q4 · medium · PYQ 2014
Raju has to cover a distance of 240 km in 4 hours. If he covers one-third of the journey in 2/7 th time, what is his speed at the beginning of the journey?
  1. 75 km/hr
  2. 70 km/hr
  3. 65 km/hr
  4. 60 km/hr
Q5 · medium · PYQ 2020
Two trains of the same length are running on parallel tracks in the same direction at 44 km/h and 32 km/h. The faster train passes the other train in 72 seconds. What is the length (in m) of each train?
  1. 100
  2. 135
  3. 75
  4. 120
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