A, B and C can do a piece of work in 10, 15, 12 days, respectively. A and B worked alternately for 5 days each and left. Then C joined and completed the work. In how many days did C complete the remaining work?
A.4
B.3
C.1
D.2✓ Correct
Explanation
A and B alternately for 5 days each = 10 days total; work done = 5(1/10+1/15)×(1/2)×2 = 50 units out of 60. Remaining = 10 units. C does 60/12=5 per day, so C takes 10/5 = 2 days.
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