Four dice are rolled. What is the probability that getting a total of the numbers on the dice is 6?

Number of ways to get sum 6 with four dice (each ≥ 1): number of solutions to a+b+c+d = 6 with 1 ≤ each ≤ 6. Substituting a' = a-1 etc., a'+b'+c'+d' = 2 with each ≥ 0: C(5,3) = 10 ways. Total outcomes = 6⁴ = 1296. Probability = 10/1296 = 5/648.