If two fair dice are tossed, then what is the probability that the sum of the numbers on the faces of the dice is strictly greater than 7?

Total outcomes when tossing two dice = 36. Outcomes with sum strictly greater than 7 (i.e., sums of 8, 9, 10, 11, 12): sum=8 has 5 ways, sum=9 has 4 ways, sum=10 has 3 ways, sum=11 has 2 ways, sum=12 has 1 way. Total = 5+4+3+2+1 = 15. Probability = 15/36 = 5/12.