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SSC CHSL 2025 · PYQ · Algebra · medium

If a² + b² + c² = 240 and ab − bc − ca = 64, then find the value of (a + b − c)².

Answer

The correct answer is C: 368. (a+b-c)² = a²+b²+c² + 2ab - 2bc - 2ca = 240 + 2(ab-bc-ca) = 240 + 2×64 = 240+128 = 368.

  1. A.388
  2. B.321
  3. C.368✓ Correct
  4. D.340

Explanation

(a+b-c)² = a²+b²+c² + 2ab - 2bc - 2ca = 240 + 2(ab-bc-ca) = 240 + 2×64 = 240+128 = 368.
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