If two fair dice are tossed, then what is the probability that the sum of the numbers on the faces of the dice is strictly greater than 7?
Answer
The correct answer is B: 5/12. Total outcomes when tossing two dice = 36. Outcomes with sum strictly greater than 7 (i.e., sums of 8, 9, 10, 11, 12): sum=8 has 5 ways, sum=9 has 4 ways, sum=10 has 3 ways, sum=11 has 2 ways, sum=12 has 1 way.
A.1/3
B.5/12✓ Correct
C.7/12
D.3/4
Explanation
Total outcomes when tossing two dice = 36. Outcomes with sum strictly greater than 7 (i.e., sums of 8, 9, 10, 11, 12): sum=8 has 5 ways, sum=9 has 4 ways, sum=10 has 3 ways, sum=11 has 2 ways, sum=12 has 1 way. Total = 5+4+3+2+1 = 15. Probability = 15/36 = 5/12.
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