x = √2+√3. x³-3x = x(x²-3). x² = 2+2√6+3 = 5+2√6. x²-3 = 2+2√6. x(2+2√6) = (√2+√3)(2+2√6) = 2√2+2√12+2√3+2√18 = 2√2+4√3+2√3+6√2 = 8√2+6√3. Hmm, that's option C. But book answer might be option A. Let me recheck: (√2+√3)(2+2√6) = 2√2+2√2·√6+2√3+2√3·√6 = 2√2+2√12+2√3+2√18 = 2√2+4√3+2√3+6√2 = 8√2+6√3. So answer should be C=8√2+6√3.
💡 Practice unlimited SSC CHSL PYQs + AI-tracked progress on each topic. Sign up free →