NDA 2025 · PYQ · Trigonometry · hard
Let p = sin35°, q = sin25° and r = sin(-95°). What is (p² + q² + r²) equal to?
Answer
The correct answer is C: 3/2. From the previous calculation, p² + q² + r² = sin²35° + sin²25° + sin²95° = 3/2. Detailed: sin²35° + sin²25° + cos²5° using sum-to-product identities yields 3/2.
- A.1/2
- B.1
- C.3/2✓ Correct
- D.2
From the previous calculation, p² + q² + r² = sin²35° + sin²25° + sin²95° = 3/2. Detailed: sin²35° + sin²25° + cos²5° using sum-to-product identities yields 3/2.
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