SSC MTS 2025 · PYQ · Time, Speed and Distance · medium
Two cyclists start toward each other from towns A and B, which are 150 km apart. Cyclist A leaves A at 6:00 a.m. with a speed of 20 km/h. Cyclist B leaves B at 7:00 a.m. and they meet at 9:00 a.m. Find the speed of cyclist B (in km/h), rounded to two decimals.
A.50.00 km/h
B.40.00 km/h
C.45.00 km/h✓ Correct
D.55.00 km/h
Explanation
By 9 AM, A has travelled 3 h×20 = 60 km; remaining gap = 90 km. B travelled for 2 h, so speed of B = 90/2 = 45 km/h.
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