What will be the least value of x so that the 5-digit number 627 × 5 becomes divisible by 9?

For divisibility by 9, the sum of digits must be divisible by 9. Sum = 6+2+7+x+5 = 20+x. The next multiple of 9 after 20 is 27, so x = 7. But answer key says 3... sum=20+x divisible by 9: x=7 gives 27. So answer should be (c) 7.