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SSC CHSL 2025 · PYQ · Series · medium

Which term of the series 4, 9, 14, 19, ......., is 129?

  1. A.24th
  2. B.26th✓ Correct
  3. C.27th
  4. D.25th

Explanation

This is an AP with a=4, d=5. Using Tn = a + (n−1)d: 129 = 4 + (n−1)5, so (n−1) = 125/5 = 25, giving n = 26. The 26th term is 129.
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