Why this topic matters · 8 min read
Binomial Theorem is a regular fixture in NDA Maths, typically contributing 2-4 questions per paper. Questions focus on finding specific terms (especially the middle term and term independent of x), finding coefficients, and using properties of binomial coefficients. Occasionally, the greatest term or numerically greatest coefficient is also tested. This topic is high-scoring because once you know the formula for the general term, most questions become direct substitution.
The Binomial Expansion Formula
The binomial theorem gives a way to expand (a + b)^n without multiplying repeatedly. Here n is a positive integer. The expansion has exactly (n+1) terms. Think of it as a shortcut machine: feed in any (a + b)^n, and it outputs a neat sum of terms using combinations.
- (a + b)^n = sum from r=0 to n of C(n,r) * a^(n-r) * b^r
- Total number of terms in expansion = n + 1
- The powers of a decrease from n to 0, powers of b increase from 0 to n
- The sum of powers in each term is always n
- Coefficients C(n,r) are called binomial coefficients and are always positive integers
- C(n,r) = n! divided by (r! times (n-r)!)
Key formulas
Binomial Expansion
(a + b)^n = C(n,0)*a^n + C(n,1)*a^(n-1)*b + ... + C(n,n)*b^n
When: Expanding any binomial raised to a positive integer power
General Term (T_{r+1})
T_(r+1) = C(n,r) * a^(n-r) * b^r
When: Finding any specific term in the expansion; r starts from 0
Worked example
Find the 4th term in (x + 2)^7. Here r = 3 (since T_(r+1), so T_4 means r=3). T_4 = C(7,3) * x^(7-3) * 2^3 = 35 * x^4 * 8 = 280x^4.
Middle Term
The middle term is one of the most common NDA question types. The position of the middle term depends on whether n is even or odd. Remember: total terms = n+1. If n+1 is odd (n is even), there is one middle term. If n+1 is even (n is odd), there are two middle terms.
- If n is even: middle term is the (n/2 + 1)th term
- If n is odd: middle terms are the ((n+1)/2)th and ((n+3)/2)th terms
- Substitute the position into the general term formula T_(r+1) to find it
- NDA mostly gives even n, so you mostly deal with one middle term
Key formulas
Middle Term (n even)
T_(n/2 + 1) = C(n, n/2) * a^(n/2) * b^(n/2)
When: When n is even and one unique middle term exists
Worked example
Find the middle term of (x + 1/x)^8. n=8 (even), middle term = T_(8/2+1) = T_5. r=4. T_5 = C(8,4)*x^4*(1/x)^4 = 70 * x^4 * 1/x^4 = 70.
Term Independent of x (Constant Term)
This is the most frequently tested NDA application. You write the general term, collect the power of x, set it equal to zero, and solve for r. The value of r gives you the term position, and substituting it gives the constant term. Always write out the power of x explicitly as a function of r before setting it to zero.
- Write T_(r+1) using the general term formula
- Simplify and express the power of x as a function of r
- Set power of x = 0 and solve for r
- r must be a non-negative integer; if not, no such term exists
- Substitute r back to find the actual term value
Key formulas
Power of x condition
Power of x in T_(r+1) = 0 (for term independent of x)
When: Finding constant term in expansions like (x + 1/x)^n or (x^2 + 1/x)^n
Worked example
Find the term independent of x in (x - 1/x^2)^9. T_(r+1) = C(9,r) * x^(9-r) * (-1/x^2)^r = C(9,r)*(-1)^r * x^(9-r-2r) = C(9,r)*(-1)^r * x^(9-3r). Set 9-3r=0, so r=3. T_4 = C(9,3)*(-1)^3 = 84*(-1) = -84.
Binomial Coefficients and Their Properties
Binomial coefficients have clean sum and symmetry properties that NDA tests as short one-step questions. These do not require heavy calculation — just remember the standard results. The coefficients in row n of Pascal's triangle are exactly C(n,0), C(n,1), ..., C(n,n).
- Sum of all binomial coefficients: C(n,0)+C(n,1)+...+C(n,n) = 2^n (put a=b=1)
- Sum of even-positioned coefficients = Sum of odd-positioned coefficients = 2^(n-1)
- Symmetry property: C(n,r) = C(n, n-r)
- Pascal's identity: C(n,r) = C(n-1,r-1) + C(n-1,r)
- C(n,r) = C(n,s) implies r=s or r+s=n
Key formulas
Sum of coefficients
C(n,0) + C(n,1) + ... + C(n,n) = 2^n
When: Direct substitution x=1 in (1+x)^n
Alternating sum
C(n,0) - C(n,1) + C(n,2) - ... = 0
When: Put x=-1 in (1+x)^n; useful for evaluating alternating coefficient sums
Greatest Term and Greatest Coefficient
NDA occasionally asks for the numerically greatest term or the greatest binomial coefficient. For the greatest binomial coefficient, it is C(n, n/2) when n is even, or C(n, (n-1)/2) = C(n, (n+1)/2) when n is odd. For the greatest term in numerical value, compare consecutive terms using the ratio T_(r+1)/T_r and find where this ratio crosses 1.
- Greatest binomial coefficient: C(n, n/2) for even n; two equal greatest values for odd n
- To find greatest term: compute ratio T_(r+1)/T_r, find r where ratio changes from >1 to <1
- The term where the ratio first becomes less than or equal to 1 is the greatest term
- NDA rarely goes deep here — knowing the greatest coefficient rule is usually enough
Key formulas
Consecutive Term Ratio
T_(r+1)/T_r = ((n-r+1)/r) * (b/a)
When: Finding the greatest term in (a+b)^n numerically
⚠ Common mistakes to avoid
- Forgetting that r starts from 0, not 1 — writing T_4 as r=4 instead of r=3 is the most common error in general term problems.
- In the term independent of x, forgetting to account for negative signs inside the bracket. Always carry the sign of b when computing (-1)^r.
- Confusing the number of terms (n+1) with n. For (x+y)^10, there are 11 terms, not 10.
- Applying the middle term formula for even n (one middle term) to an odd n case (two middle terms) — always check if n is odd or even first.
- Using C(n,r) = C(n,s) and concluding only r=s without checking the other case r+s=n, which can lead to missing one valid answer in MCQs.
🧠 Memory aids
- General Term trick: 'r is one less than the term number' — T_4 uses r=3, T_1 uses r=0. Think: r = Term position minus 1.
- Middle term mnemonic: 'Even n = One Queen, Odd n = Twin Queens' — even n has one middle term, odd n has two.
- Sum of coefficients = 2^n: Remember '2 to the power n because you substitute x=1 and (1+1)^n = 2^n'. The number 2 comes from plugging in 1.
- For constant term: 'Power of x = 0 gives you the hero term' — set the exponent of x to zero and solve for r.
🎯 NDA exam tips
- NDA typically asks 2-4 questions from Binomial Theorem per paper. Of these, at least one will be a general term or term independent of x question — always practice these first.
- Middle term and term independent of x together account for nearly 60 percent of PYQ questions from this topic. Master these two before anything else.
- Binomial coefficient property questions (like finding the sum C(n,0)+C(n,2)+... or evaluating an alternating sum) are direct one-step questions if you remember 2^n and 2^(n-1) results — easy marks.
- Typical difficulty is moderate. Each question should take 90 seconds to 2 minutes. If a question is taking longer, check if you set up the general term correctly first.
- Watch for expressions like (x^2 + 1/x)^n or (sqrt(x) - 1/x)^n — the power of x in the general term will not be a simple integer. Write it out carefully as a fraction and then set equal to zero.
Q1 · medium · PYQ 2026
What is the value of uv?
- 1
- 2
- 0 < uv < 1
- 1 < uv < 2
Q2 · hard · PYQ 2026
What is the value of u? [Given: u is positive integer, 0 < f < 1, (√2+1)¹⁰ = u + f]
- 9725
- 6971
- 6726
- 6725
Q3 · medium · PYQ 2026
What is the multiplicative inverse of (√2 + 1)^20?
- v
- v² − 1
- v²
- v² + 1
Q4 · medium · PYQ 2026
What is the multiplicative inverse of (√2 + 1)²⁰? [Given: (√2+1)¹⁰ = u + f, (√2-1)¹⁰ = v]
- v
- v² - 1
- v²
- v² + 1
Q5 · easy · PYQ 2025
If the sum of binomial coefficients in the expansion of (x + y)^n is 256, then the greatest binomial coefficient occurs in which one of the following terms?
- Third
- Fourth
- Fifth
- Ninth