Why this topic matters · 9 min read
Complex Numbers and Quadratic Equations together form one of the most consistently tested algebra topics in NDA Maths. Expect 3 to 5 direct questions per paper. NDA loves testing: argument and modulus of complex numbers, cube roots of unity (omega properties), conversion between polar and rectangular forms, and the nature of roots of quadratic equations using discriminant. Quadratic equation questions often link back to complex roots, so mastering both together saves time and boosts accuracy.
Basics of Complex Numbers
A complex number is written as z = a + ib, where a is the real part and b is the imaginary part, and i is the imaginary unit defined as square root of -1. Think of it as a point (a, b) on a 2D plane called the Argand plane, where the x-axis is real and y-axis is imaginary. Two complex numbers are equal only if both real parts are equal AND both imaginary parts are equal.
- i = sqrt(-1), i squared = -1, i cubed = -i, i to power 4 = 1. After every 4 powers, the cycle repeats.
- Real part of z = Re(z) = a. Imaginary part = Im(z) = b.
- Conjugate of z = a + ib is z* = a - ib. Conjugate flips the sign of imaginary part only.
- |z| = modulus = sqrt(a squared + b squared). This is the distance from origin on Argand plane.
- z times z* = |z| squared = a squared + b squared. Very useful in division.
Key formulas
Modulus
|z| = sqrt(a^2 + b^2)
When: Whenever distance from origin or magnitude is asked
Conjugate Product
z * z_conjugate = |z|^2
When: To eliminate imaginary part in denominator or find modulus squared
i-power cycle
i^1=-1 wait: i^1=i, i^2=-1, i^3=-i, i^4=1, repeats
When: To simplify any power of i: divide power by 4, use remainder
Worked examples
Find i to the power 53. Divide 53 by 4: remainder is 1. So i^53 = i^1 = i.
If z = 3 + 4i, find |z|. |z| = sqrt(9 + 16) = sqrt(25) = 5.
Argument and Polar Form
The argument (angle) of a complex number z = a + ib is the angle theta that the line from origin to point (a, b) makes with the positive x-axis. The polar form rewrites z as r(cos theta + i sin theta) where r = |z|. NDA frequently asks you to convert forms or find the argument of expressions like (1+i)/(1-i).
- arg(z) = arctan(b/a). But adjust the quadrant based on signs of a and b.
- Principal argument lies between -pi and pi (inclusive).
- Polar form: z = r(cos theta + i sin theta), also written as r cis theta.
- arg(z1 times z2) = arg(z1) + arg(z2). arg(z1/z2) = arg(z1) - arg(z2).
- Modulus of product: |z1 times z2| = |z1| times |z2|.
Key formulas
Argument formula
theta = arctan(b/a), adjusted for quadrant
When: Finding direction/angle of complex number on Argand plane
Polar Form
z = r(cos(theta) + i*sin(theta))
When: When question involves multiplication/division or De Moivre
De Moivre Theorem
(cos theta + i sin theta)^n = cos(n*theta) + i*sin(n*theta)
When: Raising complex numbers to large powers, finding roots
Worked examples
Find arg((1+i)/(1-i)). Multiply numerator and denominator by conjugate (1+i): result = (1+i)^2 / 2 = (2i)/2 = i = 0 + 1i. arg(i) = pi/2.
Express z = 1 + i in polar form. r = sqrt(2), theta = pi/4. So z = sqrt(2)(cos(pi/4) + i sin(pi/4)).
Cube Roots of Unity
The three cube roots of 1 are: 1, omega, and omega squared, where omega = (-1 + i*sqrt(3))/2. These appear frequently in NDA questions involving algebraic identities and factorization. The two properties of omega are so important that you must memorize them the night before the exam.
- 1 + omega + omega squared = 0. This is the golden identity.
- omega cubed = 1. Powers of omega repeat with period 3.
- omega and omega squared are conjugates of each other.
- omega squared = (-1 - i*sqrt(3))/2.
- Common use: factoring a cubed + b cubed + c cubed - 3abc = (a+b+c)(a + b*omega + c*omega^2)(a + b*omega^2 + c*omega).
Key formulas
Sum of cube roots
1 + omega + omega^2 = 0
When: Simplifying expressions involving omega — use this to substitute
Omega cubed
omega^3 = 1
When: Reducing higher powers: omega^7 = omega^(6+1) = (omega^3)^2 * omega = omega
Worked example
Simplify: 1 + omega^10 + omega^20. omega^10 = omega^(9+1) = omega. omega^20 = omega^(18+2) = omega^2. So expression = 1 + omega + omega^2 = 0.
Quadratic Equations and Nature of Roots
A quadratic equation is ax^2 + bx + c = 0 with a not equal to 0. The discriminant D = b^2 - 4ac decides the nature of roots. NDA tests this both directly (find D) and indirectly (if roots are equal, find k). Always remember: complex roots always appear in conjugate pairs when coefficients are real.
- D > 0: two distinct real roots. D = 0: two equal real roots. D < 0: two complex conjugate roots.
- Sum of roots = -b/a. Product of roots = c/a. Memorize as S = -b/a, P = c/a.
- If alpha and beta are roots, equation is: x^2 - (alpha+beta)x + alpha*beta = 0.
- For real coefficients, complex roots come in pairs: if p+iq is a root, then p-iq is also a root.
- If one root is 2+3i and coefficients are real, the other root must be 2-3i.
Key formulas
Discriminant
D = b^2 - 4ac
When: Checking nature of roots — do this first in every quadratic problem
Quadratic Formula
x = (-b +/- sqrt(D)) / 2a
When: Finding actual root values
Sum and Product of Roots
S = -b/a, P = c/a
When: Forming new equations or checking given roots without solving fully
Worked examples
If one root of x^2 - 5x + k = 0 is 2+i, find k. Since coefficients are real, other root is 2-i. Sum = (2+i)+(2-i) = 4 = 5/1, wait: sum = -(-5)/1 = 5. But 4 is not 5 — check: actually sum = 4, not 5, so this would be inconsistent. Correct example: x^2 - 4x + k = 0 with root 2+i. Sum = 4 = 4 (checks). Product = (2+i)(2-i) = 4+1 = 5 = k. So k = 5.
Find nature of roots of 2x^2 - 3x + 4 = 0. D = 9 - 32 = -23 < 0. Roots are complex conjugates.
⚠ Common mistakes to avoid
- Forgetting the quadrant adjustment when finding argument: arctan(b/a) always gives angle in first or fourth quadrant only. If a < 0, add or subtract pi to get correct quadrant.
- Mixing up 1 + omega + omega^2 = 0 with omega^3 = 0. omega^3 equals 1, not 0. The sum of all three cube roots equals 0.
- In division of complex numbers, students multiply only the numerator by conjugate and forget to divide by |denominator|^2. Always multiply both top and bottom by conjugate of denominator.
- When D < 0 and coefficients are real, assuming roots are unrelated. They are always conjugates. NDA uses this to set up equations for unknown coefficients.
- Confusing modulus with argument. Modulus is a positive real number (magnitude). Argument is an angle in radians. Do not mix them up in polar form questions.
🧠 Memory aids
- i-cycle mnemonic: I In Negative Isolation — i, -1, -i, 1. Four steps, then repeat. Remainder on dividing power by 4 gives your answer.
- Omega rule: ONE plus OMEGA plus OMEGA-SQUARE = ZERO. Think of it as three brothers whose sum is always zero, and each cubed becomes ONE.
- For Sum and Product of roots, remember SP formula: S = -b/a (negative of middle over first), P = c/a (last over first). Mnemonic: NMA — Negative Middle over A, Last over A.
- Argand plane = Address plane. Real part is the street number (x), imaginary part is the floor number (y). Modulus is your straight-line distance from the origin building.
🎯 NDA exam tips
- NDA typically asks 3 to 4 questions from this combined topic. Cube roots of unity and argument/modulus questions appear almost every year — prioritize these over obscure subtopics.
- Questions on omega are very fast to solve if you remember 1+omega+omega^2=0. A typical question gives a big expression like (1+omega^2)^5 and expects simplification — the answer is almost always -1 or 1 or omega.
- Quadratic equations in NDA often ask: given one complex root, find the equation or a coefficient. Always use the conjugate-pair rule for real coefficients — it cuts the work in half.
- Polar form and De Moivre questions are medium difficulty. If time is short in the exam, skip De Moivre and return to it — modulus and argument questions are faster and more frequent.
- Do not waste time deriving the quadratic formula in the exam. Memorize D = b^2 - 4ac and the sum/product formulas. Most NDA quadratic questions can be solved with these alone without finding actual roots.
Q1 · easy · AI-verified
What is the modulus of the complex number z = 3 + 4i?
- √7
- 25
- 7
- 5
Q2 · easy · AI-verified
If ω is a cube root of unity (ω ≠ 1), then 1 + ω + ω² equals:
- −1
- 0
- 3
- 1
Q3 · easy · AI-verified
The product of the roots of the quadratic equation x² − 7x + 12 = 0 is:
- 7
- −7
- −12
- 12
Q4 · easy · AI-verified
If α and β are roots of x² − 3x + 2 = 0, then α² + β² equals:
- 4
- 5
- 9
- 13
Q5 · easy · AI-verified
The nature of roots of the equation x² + 2x + 5 = 0 is:
- One real and one complex root
- Complex conjugate roots
- Two equal real roots
- Two distinct real roots