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Statistics and Probability Questions for NDA

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Why this topic matters · 9 min read
Statistics and Probability together form one of the most scoring and high-frequency areas in NDA Maths. Expect 6-10 questions per paper covering measures of central tendency, measures of dispersion, and probability concepts including conditional probability and basic theorems. Questions are mostly formula-based and calculation-intensive but follow predictable patterns from previous years. A student who masters mean, variance, standard deviation, and Bayes theorem can confidently attempt all questions in this section within 12-15 minutes.

Measures of Central Tendency

Central tendency tells you where the center of a data set lies. The three main measures are Mean, Median, and Mode. For NDA, arithmetic mean is most frequently tested, especially for grouped data. The relationship between mean, median, and mode (the empirical formula) is a direct one-line question that appears almost every year.

  • Arithmetic Mean (AM) for ungrouped data: sum of all values divided by number of values
  • For grouped/frequency data: AM = sum of (f times x) divided by sum of f, where f is frequency and x is midpoint
  • Median for ungrouped data: middle value when arranged in order; for even n, average of two middle values
  • Median for grouped data uses the formula with cumulative frequency and class interval
  • Mode is the value with highest frequency; for grouped data use the modal class formula
  • Empirical relation: Mode = 3 Median minus 2 Mean (very commonly asked as a fill-in)
Key formulas
Arithmetic Mean (grouped)
Mean = Sum(f * x) / Sum(f)
When: Use when data is given in a frequency table with class intervals; x is the midpoint of each class
Median (grouped)
Median = L + [(N/2 - CF) / f] * h
When: L = lower boundary of median class, N = total frequency, CF = cumulative frequency before median class, f = frequency of median class, h = class width
Mode (grouped)
Mode = L + [(f1 - f0) / (2f1 - f0 - f2)] * h
When: f1 = frequency of modal class, f0 = frequency before it, f2 = frequency after it, L = lower boundary, h = class width
Empirical Relation
Mode = 3 * Median - 2 * Mean
When: Use when any one of the three is unknown and the other two are given
Worked examples

If Mean = 25 and Median = 26, find Mode. Mode = 3(26) - 2(25) = 78 - 50 = 28. Answer: 28.

Data: 4, 7, 13, 2, 1. Mean = (4+7+13+2+1)/5 = 27/5 = 5.4. Arrange: 1,2,4,7,13. Median = 4 (middle value).

Measures of Dispersion

Dispersion tells you how spread out the data is. NDA tests Variance and Standard Deviation most heavily. Remember: Standard Deviation (SD) is the square root of Variance. The Coefficient of Variation (CV) is used to compare two distributions and appears in NDA questions asking which data set is more consistent — lower CV means more consistent.

  • Range = Maximum value minus Minimum value; simplest measure of dispersion
  • Mean Deviation = Sum of |x - Mean| divided by n
  • Variance = Sum of (x - Mean)^2 divided by n for ungrouped data
  • For grouped data: Variance = Sum(f * x^2)/Sum(f) - [Sum(f * x)/Sum(f)]^2
  • Standard Deviation (SD) = Square root of Variance
  • Coefficient of Variation (CV) = (SD / Mean) * 100; lower CV means more consistent data
Key formulas
Variance (ungrouped)
Variance = [Sum(x^2)/n] - [Sum(x)/n]^2
When: Quick shortcut formula; avoids computing (x - mean) for each value separately
Variance (grouped)
Variance = [Sum(f * x^2)/Sum(f)] - [Sum(f * x)/Sum(f)]^2
When: Use with frequency distribution tables; x is midpoint of class interval
Standard Deviation
SD = sqrt(Variance)
When: Always the final step after computing variance
Coefficient of Variation
CV = (SD / Mean) * 100
When: Comparing consistency of two or more data sets; pick lower CV for more consistent
Worked examples

Data: 2, 4, 6, 8, 10. Mean = 6. Sum of x^2 = 4+16+36+64+100 = 220. Variance = 220/5 - 36 = 44 - 36 = 8. SD = sqrt(8) = 2root2.

Group A: Mean=50, SD=5. Group B: Mean=40, SD=4. CV_A = 10%, CV_B = 10%. Both equally consistent.

Basic Probability

Probability measures the likelihood of an event. NDA tests classical probability most often: number of favorable outcomes divided by total outcomes. You must be comfortable with counting techniques (permutations and combinations) to find favorable and total outcomes. Events can be mutually exclusive or independent — knowing which formula to apply is the key skill tested.

  • P(A) = Favorable outcomes / Total outcomes; always between 0 and 1
  • P(A') = 1 - P(A), where A' is the complement (event not happening)
  • Mutually exclusive events: P(A or B) = P(A) + P(B)
  • Non-mutually exclusive: P(A or B) = P(A) + P(B) - P(A and B)
  • Independent events: P(A and B) = P(A) * P(B)
  • Dependent events: P(A and B) = P(A) * P(B given A)
Key formulas
Addition Rule
P(A union B) = P(A) + P(B) - P(A intersection B)
When: Events are not mutually exclusive; if mutually exclusive, P(A intersection B) = 0
Multiplication Rule (independent)
P(A intersection B) = P(A) * P(B)
When: When events do not affect each other, e.g., tossing two coins separately
Conditional Probability
P(B|A) = P(A intersection B) / P(A)
When: Probability of B given that A has already occurred
Worked examples

A card is drawn from 52 cards. P(King or Heart) = P(King) + P(Heart) - P(King of Hearts) = 4/52 + 13/52 - 1/52 = 16/52 = 4/13.

Two dice thrown. P(sum = 7) = 6 favorable pairs (1+6,2+5,3+4,4+3,5+2,6+1) out of 36 = 6/36 = 1/6.

Conditional Probability and Bayes Theorem

Bayes Theorem is the most advanced probability concept tested in NDA. It helps reverse the direction of probability: given that an outcome happened, what was the probable cause? Questions usually involve two or three bags with balls, or two machines producing defective items. The structure is always the same — find the probability of a hypothesis given observed evidence.

  • Bayes Theorem is used when you know P(Evidence given Cause) and want P(Cause given Evidence)
  • Always identify all possible causes (hypotheses) first
  • Compute P(Evidence given each cause) and multiply by prior probability of each cause
  • Denominator = total probability = sum of all such products
  • These questions appear as 2-3 step calculations — organize in a table to avoid errors
  • Total Probability Theorem: P(B) = Sum of P(Ai) * P(B|Ai) for all mutually exclusive Ai
Key formulas
Bayes Theorem
P(Ai|B) = [P(Ai) * P(B|Ai)] / Sum[P(Aj) * P(B|Aj)]
When: When event B has occurred and you need the probability of cause Ai being responsible
Total Probability
P(B) = P(A1)*P(B|A1) + P(A2)*P(B|A2) + ... + P(An)*P(B|An)
When: Finding overall probability of an event using all possible causes
Worked example

Bag 1 has 3 red 2 blue. Bag 2 has 2 red 3 blue. A bag is chosen randomly, then a ball drawn is red. P(it came from Bag 1) = [0.5 * 3/5] / [0.5 * 3/5 + 0.5 * 2/5] = 0.3/0.5 = 3/5.

⚠ Common mistakes to avoid
  • Using Mode = 3 Median - 2 Mean with wrong signs or wrong order — memorize it exactly as Mode = 3(Median) - 2(Mean), not the reverse
  • Confusing Variance with Standard Deviation — NDA questions sometimes ask for one when calculations lead to the other; always check what is asked at the end
  • In grouped data, using class boundaries (exact limits) instead of class midpoints as the x value in mean and variance calculations
  • Applying the multiplication rule P(A)*P(B) for dependent events — this formula is only for independent events; use conditional probability for dependent ones
  • In Bayes theorem questions, forgetting to include the denominator (total probability) and just reporting the numerator as the answer — always divide by the sum of all weighted probabilities
🧠 Memory aids
  • MeMo aid for empirical relation: Mo = 3Me - 2Ma (Mode = 3 times Median minus 2 times Mean). Say it as Mo-3Me-2Ma like a chant.
  • For SD vs Variance: Variance is the Square, SD is the Root. V comes before S in the alphabet, Square root comes after squaring.
  • For Bayes: think CAUSE then CLUE — you know the Clue (evidence), find the Cause. Numerator = one cause, Denominator = all causes.
  • MICE rule for probability: Mutually exclusive = add, Independent = multiply, Complement = subtract from 1, Exhaustive = total is 1.
🎯 NDA exam tips
  • NDA typically asks 2-3 direct formula questions on mean/median/mode from grouped data — these are gift marks if you know the formulas cold. Practice substituting into the median and mode formulas quickly.
  • Variance and SD questions often give you raw data of 5-6 numbers. Use the shortcut formula Sum(x^2)/n - (Mean)^2 to save time rather than computing deviations one by one.
  • Probability questions on cards, dice, and bags appear almost every paper. Know total outcomes for a standard deck (52), one die (6), two dice (36) by heart — do not waste time recounting.
  • Bayes theorem appears as a single high-value conceptual question, usually with exactly 2 bags or 2 machines. If you see the words given that or it turned out to be defective, it is a Bayes problem.
  • CV comparison questions (which group is more consistent) are 1-step questions once you have SD and Mean — do not skip them as they look hard but take under 30 seconds.

Sample questions

Q1 · hard · AI-verified
Three cards are drawn at random from a pack of 52 cards without replacement. What is the probability that all three cards are kings?
  1. 1/1105
  2. 4/2197
  3. 1/5525
  4. 1/2197
Q2 · hard · AI-verified
A random variable X has the following probability distribution: P(X=0)=k, P(X=1)=2k, P(X=2)=3k, P(X=3)=4k, and P(X=r)=0 for r>3. What is the value of E(X²)?
  1. 5
  2. 6
  3. 4
  4. 3
Q3 · hard · AI-verified
The coefficient of variation of two series A and B are 60% and 70% respectively, and their standard deviations are 21 and 35. What are the means of A and B respectively?
  1. 35 and 50
  2. 35 and 40
  3. 40 and 50
  4. 30 and 45
Q4 · hard · AI-verified
The median of the data 4, 7, 2, 1, 6, 8, 10, 3, 5, 9 is grouped in class intervals. If the data is: 1-3 (frequency 3), 4-6 (frequency 4), 7-9 (frequency 2), 10-12 (frequency 1), what is the median using the formula?
  1. 4.75
  2. 5.5
  3. 5
  4. 4.5
Q5 · hard · AI-verified
In a normal distribution, 31% of items are under 45 and 8% are over 64. What is the mean of the distribution? (Given: area under normal curve from z=0 to z=0.5 is 0.19 and from z=0 to z=1.41 is 0.42)
  1. 52
  2. 50
  3. 45
  4. 55
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