Why this topic matters · 8 min read
Time and Work is one of the most frequently tested topics in RRB Group D Quant section. Expect 2-4 questions per attempt. Questions are typically straightforward — finding days to complete a job alone or together, pipe and cistern problems, and efficiency-based comparisons. Difficulty stays low to moderate, so a well-prepared aspirant should aim to solve each question in under 90 seconds.
Core Concept: Work = Rate x Time
Think of work as filling a bucket. Each worker fills the bucket at their own speed (rate). The total work is always considered as 1 complete job. If someone finishes a job in N days, they complete 1/N of the job each day. This daily fraction is their work rate.
- Total Work = 1 (always treat the full job as 1 unit)
- If A finishes in N days, A's 1-day work = 1/N
- If A and B work together, combined 1-day work = 1/A + 1/B
- Days to finish together = 1 divided by (1/A + 1/B)
- More workers = fewer days (inverse relationship)
- More efficiency = fewer days needed
Key formulas
One-day work
Work per day = 1 / Total days
When: Use this to find how much a single person does in one day
Together formula
Days together = (A x B) / (A + B)
When: Use when exactly two people work together — fastest formula for two-person problems
Three people together
Days = 1 / (1/A + 1/B + 1/C)
When: When three workers collaborate — add all three rates then take reciprocal
Remaining work
Remaining Work = 1 - Work already done
When: When one person works for some days then another joins — subtract completed portion
Efficiency formula
Efficiency is inversely proportional to Days: E1/E2 = D2/D1
When: Comparing two workers with given efficiency ratio to find days
Worked examples
A finishes a job in 12 days, B in 15 days. Together: (12 x 15)/(12+15) = 180/27 = 6.67 days, about 6 and 2/3 days.
A can do a job in 10 days. A works for 4 days alone, then B joins. Work done by A in 4 days = 4/10 = 2/5. Remaining = 1 - 2/5 = 3/5. If B alone takes 15 days, together they do 1/10+1/15 = 1/6 per day. Days for remaining = (3/5)/(1/6) = 18/5 = 3.6 days.
LCM Method: Easier than Fractions
Instead of dealing with fractions, assign total work = LCM of all given days. Then each worker gets a whole-number efficiency (units per day). This avoids messy fraction addition and saves time in the exam. This is the preferred shortcut for RRB-level problems.
- Step 1: Find LCM of all days given in the problem
- Step 2: Assign that LCM as total work units
- Step 3: Each person's efficiency = LCM divided by their individual days
- Step 4: Add efficiencies of working people, divide total work by combined efficiency
- This method turns fractions into simple division — much faster
- Works perfectly for 2, 3 or more worker problems
Worked example
A takes 12 days, B takes 18 days. LCM of 12 and 18 = 36. Total work = 36 units. A does 36/12 = 3 units/day. B does 36/18 = 2 units/day. Together = 5 units/day. Days = 36/5 = 7.2 days.
Pipes and Cisterns
Pipes and Cisterns is just Time and Work in disguise. Filling a tank = positive work. Emptying/leaking = negative work. An inlet pipe fills the tank, an outlet pipe drains it. Treat the full tank as 1 unit of work and apply the same rules.
- Inlet pipe fills tank — treat as positive rate (+1/T)
- Outlet pipe empties tank — treat as negative rate (-1/T)
- Net rate = sum of all inlets minus sum of all outlets
- If net rate is positive, tank fills; if negative, tank empties
- Time to fill = 1 / Net rate
- A leak question: tank fills slower because of the leak — subtract leak rate
Key formulas
Net filling rate
Net Rate = (1/Inlet time) - (1/Outlet time)
When: When both inlet and outlet are open simultaneously
Time to fill with leak
Time = 1 / (1/Fill time - 1/Leak time)
When: A pipe fills but a leak drains — find actual time to fill
Worked example
Pipe A fills tank in 10 hours, Pipe B empties in 15 hours. Both open: Net rate = 1/10 - 1/15 = 3/30 - 2/30 = 1/30. Tank fills in 30 hours.
Men, Days and Hours (MDH Concept)
When the number of workers, days worked, and hours per day all change together, use the Men-Days-Hours formula. Think of it as: total man-hours of work stays constant. If you increase workers, days go down. If workers reduce hours per day, more days are needed.
- Total work = Men x Days x Hours per day
- M1 x D1 x H1 = M2 x D2 x H2 (for same amount of work)
- If work amount changes, add W1 and W2: M1xD1xH1/W1 = M2xD2xH2/W2
- More men means fewer days — inverse relationship
- More hours per day means fewer days — also inverse
- Always check what quantity you are solving for before substituting
Key formulas
MDH formula
(M1 x D1 x H1) / W1 = (M2 x D2 x H2) / W2
When: Use when men, days, hours and/or work quantity all change between two situations
Worked example
10 men finish a wall in 8 days working 6 hours/day. How many days for 12 men working 5 hours/day for same wall? 10x8x6 = 12x D2x5. 480 = 60xD2. D2 = 8 days.
⚠ Common mistakes to avoid
- Adding days instead of rates: Never add days directly. Always convert to 1-day work (fractions or LCM units) before adding.
- Forgetting negative sign in pipes: Students add outlet pipe rate instead of subtracting it, giving a wrong shorter time.
- Using wrong LCM: Taking LCM of 3 numbers incorrectly. Double-check: LCM of 12 and 18 is 36, not 30.
- Not accounting for already-completed work: When one person works for some days before another joins, students forget to subtract the portion already done before calculating remaining days.
- Confusing efficiency ratio direction: If A is twice as efficient as B, A takes HALF the days of B — not double. The ratio flips.
🧠 Memory aids
- RATE NOT DAYS: Always remember — ADD the RATES (1/day fractions), never add the days themselves. Think of cars on a highway merging — their speeds add, not their travel times.
- LCM = LIFE SAVER: When you see 2 or more workers, immediately find LCM of their days. This converts ugly fractions to clean whole numbers. LCM is your best friend in the exam hall.
- FILL PLUS, DRAIN MINUS: For pipes, just remember: tap filling is a plus, hole draining is a minus. Like your bank account — income is positive, spending is negative.
- MDH Constant: Men x Days x Hours = constant work. Think of it as total bricks to lay — no matter how you split workers and shifts, the total bricks stay the same.
🎯 RRB GROUP D exam tips
- RRB Group D usually gives 2 to 3 Time and Work questions. At least one will be a simple two-person together problem — direct formula (AxB)/(A+B) will solve it in 20 seconds.
- Pipes and Cisterns appears at least once. The twist is usually a leak — practice the net rate formula so it becomes automatic.
- MDH questions come with a sentence like 20 men complete a work in 15 days — how many men needed if days reduce to 10? Set up the formula first, then substitute. Do not do it in your head.
- Options in RRB Group D are often well-spaced (like 6, 8, 10, 12 days) so if your calculation gives a fraction, recheck — the answer is likely a clean integer.
- LCM method is highly recommended over fraction method for this exam level — it saves 30-40 seconds per question which adds up across the paper.
Q1 · medium · AI-verified
Two railway maintenance teams working together can service a section of track in 12 days. The first team alone can do it in 20 days. If the second team works alone for 15 days and then both teams work together, in how many more days will the work be completed?
- 3 days
- 4 days
- 5 days
- 6 days
Q2 · medium · AI-verified
20 machines can produce 400 railway sleepers in 8 hours. How many sleepers can 15 machines produce in 12 hours?
- 450 sleepers
- 500 sleepers
- 400 sleepers
- 600 sleepers
Q3 · medium · AI-verified
A railway track maintenance crew of 8 workers can repair 240 meters of track in 6 days. How many meters can 12 workers repair in 9 days?
- 540 meters
- 480 meters
- 600 meters
- 450 meters
Q4 · medium · AI-verified
A group of workers can repair a damaged railway signal in 18 days. After working for 6 days, 3 more workers join them and the work is completed in 8 more days. How many workers were there initially?
- 9 workers
- 12 workers
- 6 workers
- 15 workers
Q5 · medium · AI-verified
A train helper can load 60 boxes in 4 hours. Working at the same rate, how many boxes can he load in 7 hours?
- 105 boxes
- 120 boxes
- 90 boxes
- 100 boxes